forward

Is it possible to forward or redirect from a servlet filter after the response has been committed?

不问归期 提交于 2019-11-29 19:32:36
问题 The logic is that the filter gets hit, the condition is not true, so it goes through the filter chain. After the response is committed, the filter gets hit, and the condition is now true (a request attribute was set). It goes in to execute the forward, but the page never forwards. I know this has something to do with the response being committed because I tested different logic where it forwards before it hits the chain for the first time, and it does forward successfully. public void

Forward declare a struct in Objective-C

↘锁芯ラ 提交于 2019-11-29 17:15:38
问题 I'm creating a protocol, and one of the parameters to a method I'm defining is a CMTime* . I would like to forward declare CMTime as opposed to including it. However, I've tried @class CMTime and it complains that it is redefined elsewhere as a different type of symbol. Documentation says it's a struct. I've tried forward declaring it as struct CMTime; but it still is complaining that it doesn't know what it is. Any ideas what I'm doing wrong? 回答1: A source compiled as ObjC has the same rules

Ajax-典型应用-三级联动

独自空忆成欢 提交于 2019-11-29 14:46:16
Ajax 典型应用_三级联动_需求及准备 ①先在WebContent下新建employees.jsp用来转发到pages文件夹下的employees.jsp页面 <!-- 这个方法也行 直接去listLocations页面 <jsp:forward page="EmployeeServlet?method=listLocations"></jsp:forward> --> <% response.sendRedirect("EmployeeServlet?method=listLocations"); %> ②在src下新建com.atguigu.ajax.app.dao包,包下有BaseDao.java和DBManager.java BaseDao.java import java . sql . Connection ; import java . util . List ; import org . apache . commons . dbutils . DbUtils ; import org . apache . commons . dbutils . QueryRunner ; import org . apache . commons . dbutils . handlers . BeanHandler ; import org . apache . commons

Struts 学习笔记之Action

流过昼夜 提交于 2019-11-29 06:14:20
下面是 Struts 中的一些常用 Action 如 DispatchAction/LookupDispatchAction/MappingDispatchAction/ForwardAction/IncludeAction 的总结 1 . DispatchAction extends BaseAction 一般的 Action 如 <action path="/createUser" type="examples.UserAction"> ,在这里 UserAction 只需要继承父类( extends Action 类),然后重写父类的 execute 方法,在 execute 中实现具体的控制转向。 对于同一个 formbean 上进行的新增、修改、删除等,我们需要分发不同的 Action ,这里有两种做法。 ① 一种是通过在 execute 方法中 if 判断进行不同的转向: ㈠ UserAction 类的 execute 方法中 String method = request.getParameter("method") ; if (method.equals(" create ")) { …… return mapping.findForward("createUser"); } if (method.equals(" save ")) { …… return

JSP的forward指令实战

拜拜、爱过 提交于 2019-11-29 04:53:23
一 jsp-forward.jsp <%@ page contentType="text/html; charset=GBK" language="java" errorPage="" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title> forward的原始页 </title> <meta name="website" content="http://www.crazyit.org" /> </head> <body> <h3>forward的原始页</h3> <jsp:forward page="forward-result.jsp"> <jsp:param name="age" value="29"/> </jsp:forward> </body> </html> 二 forward-result.jsp <%@ page contentType="text/html; charset=GBK" language="java" errorPage="" %> <

Sequential feature selection Matlab

最后都变了- 提交于 2019-11-29 04:44:13
Can somebody explain how to use this function in Matlab "sequentialfs" it looks straight forward but I do not know how can we design a function handler for it?! any clue?! Here's a simpler example than the one in the documentation. First let's create a very simple dataset. We have some class labels y . 500 are from class 0 , and 500 are from class 1 , and they are randomly ordered. >> y = [zeros(500,1); ones(500,1)]; >> y = y(randperm(1000)); And we have 100 variables x that we want to use to predict y . 99 of them are just random noise, but one of them is highly correlated with the class

Apache forwarding request to another server

馋奶兔 提交于 2019-11-29 01:57:51
I want apache to forward request coming to one server to another server. Here is the complete scnario: There are 3 servers: Machine A - IP: A.A.A.A - Client machine which wants to call an API there on machine C. Machine B - IP: B.B.B.B - Intermediate machine Machine C - IP: C.C.C.C - Machine hosting the API. API URL: http:// Machine c: 8000 /v1/customer/.... Connectivity status: Machine A -> Machine B: Telnet on port 80 - Good Machine B -> Machine C: Telnet on port 8000 - Good Machine A -> Machine C: Telnet on port 8000 - Bad Ideally, from Machine A I want to call an API on machine C, but

struts1

試著忘記壹切 提交于 2019-11-29 01:40:33
Struts就是一个MVC框架,下面Struts1 是如何实现MVC 的。参考图如下: M主要是ActionForm和JavaBean。负责程序的数据收集和业务处理,ActionForm属于Struts的框架的,这里的JavaBean是应用本身的业务逻辑。 V层主要是Jsp。主要用于动态页面的显示,Struts本身是没有V层的,作为一个框架只是一个大体结构。这个V层是由开发人员补全的。 C层是Struts的主要部分,包含了Struts框架本身的很多大部分内容,有: struts-config.xml Struts框架自身的配置文件,包含了很多配置信息。 ActionServlet Struts框架核心控制类(替代servlet实现的抽象物)。 RequestProcessor 配合ActionServlet完成截取URL功能。 Struts通过内部对象及配置文件的协同工作,完成了对页面和Action灵活控制。从而实现Model和View的分离,降低他们之间的耦合程度。 一、配置ActionServlet (web.xml) Struts 最核心的控制器,ActionServlet 是一个标准的Servlet ,在web.xml 文件中配置,该Servlet 用于拦所有的HTTP 请求,井将用户请求转入到Struts 体系内。因此,应将该Servlet 配置成自启动Servlet

How to access site through IP address when website is on a shared host?

∥☆過路亽.° 提交于 2019-11-28 19:22:26
I want to edit my host file to forward a website to another IP, but that IP is on a shared host, so the IP doesn't take me to the domain I want. Is there a way around this? i.e. Website: http://somerandomservice.com/ Ping the site and go to: 67.225.235.59 But they're different sites. Thanks! Update: Tried nmap, but unable to find the correct port. One possible way to access your website via its ip number is by including a tilde ~ and then your user name: Example: http://serverIPaddress/~cpanelusername According with the HTTP/1.1 standard, the shared IP hosted site can be accessed by a GET

Forwarding an error in Swift

♀尐吖头ヾ 提交于 2019-11-28 14:46:49
Is there a better solution to forward a Swift error from one function to another? In the moment, I'm doing it like this: enum Error:ErrorType{ case Error1 case Error2 } func func1()throws{ do{ try func2() }catch Error.Error1{ throw Error.Error1 }catch Error.Error2{ throw Error.Error2 } } func func2()throws{ // proof something throw Error.Error1 } So, to forward an error, I need to catch all the errors and throw them again. Is there a better solution? Yes: don't wrap it in a do ... catch block. func func2() throws{ // proof something throw Error.Error1 } func func1()throws{ try func2() } You