forms

Drupal 8 Can't persist custom template content type form

独自空忆成欢 提交于 2020-02-05 03:42:05
问题 I am trying to display and customize an add form page. My content type, created via admin interface, is simple but uses workbench moderation module to manage content entity state (draft, published and archived). I use this code to display form : my__module.routing.yml my__module.declare_security_practice: path: '/declarer-une-pratique-securite' defaults: _controller: '\Drupal\node\Controller\NodeController::add' _title: 'Déclarer une pratique sécurité' node_type: 'pratiques_securite'

PHP jQuery .ajax() file upload server side understanding

浪子不回头ぞ 提交于 2020-02-05 03:29:06
问题 I have an HTML form that previously was only used for text attributes for users, that was all using AJAX to call a PHP controller functions via URLs to refresh page content via database and server-side calls (abridged version) <input type="text" id="firstname" name="FIRSTNAME"/> <input type="text" id="lastname" name="LASTNAME"/> <input name="Submit"type="submit" value="Submit" /> This "create user" form now needs to incorporate a file uploading mechanism, for user images <input type="file"

Create multiple records using single form (Not nested attributes)

倾然丶 夕夏残阳落幕 提交于 2020-02-05 02:36:07
问题 In my application I have a Thought model which has content and author attributes. I want to create multiple thoughts at once using new form. But this is not a case of nested forms as i am not using any associated models. Please suggest some solution. Thanks in advance! 回答1: You can try with the below solution In your View File <%= form_tag your_action_path do %> <% 4.times do |i|%> Content : <%= text_area_tag :thought_content, "", :name => "thoughts[][content]" %> Author : <%= text_field_tag

Passing value of a selection from Dynamic Dropdown List in HTML form created from a separate Google Sheet using Google App Script

家住魔仙堡 提交于 2020-02-04 20:42:11
问题 I am unable to Pass the value of a selection from the Dynamic Dropdown List in HTML form created from a another Google Sheet within same file using Google App Script. I am a newbie and make Google Sheets to automate / organize my daily workflow for personal use. I take help from videos / scripts from other users through internet & edit them to achieve my objective. I am developing a small Google Sheet for one of my close friend so that to create a Client List in Google Sheet for his startup

How to collect Date of birth from php form and insert into mysql?

吃可爱长大的小学妹 提交于 2020-02-04 14:31:34
问题 I am new to programming, have done a few things but i have no idea how to collect dob information. How do i collect it from a form and how do i insert it? Do i use three fields: month/day/year and then in the db also have three columns? Is there a tutorial i can be pointed to? Thanks 回答1: Depending on what you're going to do with the data (if it's not going to be too complex), you could simply reformat the submitted form: $bday = date('Y-m-d',strtotime($_POST['userSubmittedBDay'])); and

How to collect Date of birth from php form and insert into mysql?

梦想与她 提交于 2020-02-04 14:28:58
问题 I am new to programming, have done a few things but i have no idea how to collect dob information. How do i collect it from a form and how do i insert it? Do i use three fields: month/day/year and then in the db also have three columns? Is there a tutorial i can be pointed to? Thanks 回答1: Depending on what you're going to do with the data (if it's not going to be too complex), you could simply reformat the submitted form: $bday = date('Y-m-d',strtotime($_POST['userSubmittedBDay'])); and

django formset not validating because ID is required

安稳与你 提交于 2020-02-03 08:10:25
问题 MY view receives a model formset from the template, but it doesn't pass validation, claiming that ID is required. Al my use of forms until now has never brought up this problem, and I've never had to pass ID's around. Here is a simplified version of my view: def BudgetView(request): import pdb pdb.set_trace() if request.user.is_authenticated: U=request.user #initalize formset factories ItemFormSet = modelformset_factory(Item, fields=(blabla), extra=0) CatFormset=modelformset_factory

IntelliJ IDEA Can't create GUI Form

爷,独闯天下 提交于 2020-02-03 04:32:22
问题 Supposedly creating a new GUI form should be a simple matter of right-clicking your project, package or src folder and go New > GUI Form. The problem is I don't have that option. I've created a Java project and it compiles and runs fine. But the only options I get under New are Java Class, File, Package, HTML File, and JavaScript File. 回答1: Double check that you have UI Designer enabled in Settings | Plugins . 回答2: Really old question, but if I got here someone else may as well... So, step by

django : create table form when selecting multiple rows

放肆的年华 提交于 2020-02-02 14:36:05
问题 I need to create a pretty straight forward form with Django but seems to be unable to find the proper tool for it, maybe because of the lack of vocabulary on what I want : I have a table of n rows (n varies), each row represents a database object. I want to put a checkbox in front left of each row to be able to select multiple rows and apply an action placed in a multiplechoice widget at the top. I thought about "serialize" a deleteview with formset but anyway I don't know how to add extra

Javascript - How to hide a drop down control if it's empty

橙三吉。 提交于 2020-02-02 14:30:33
问题 I have a cascade dropdown on a form. User selects Document Type and most of the document type has Category. However, if a doc type does not have category then I would like to hide the category drop down. Is there a way to see if category dropdown (calculate array or something) and hide category control (by default it always show Select a value even if the drop down does not have any value to select from) So far I have following and wondering how to evaluate category drop down control based on