forms

问题 With django I could simply pass the POST data to the form after failed validation and the user would not have to enter everything again: question_form = QuestionForm(request.POST) choice_form_set = ChoiceFormSet(request.POST) How could I implement this on my own in flask? 回答1: It's pretty similarly possible with Flask as well: @app.route('/register', methods=['GET', 'POST']) def register(): form = RegistrationForm(request.form) if request.method == 'POST' and form.validate(): user = User(form

问题 When I send a form with an unchecked checkbox, if the related entity property equals true , then it does not change to false . The other way round (setting property to true when the form is sent with a checked checkbox) works fine, as well as all the forms other fields saving. Here is how I build the form and declare the related property: // --- Form creation function EntityType::buildForm() --- $builder->add('secret', 'checkbox', array( 'required' => false )); // --- Entity related property,

问题 I am trying to take through req.body the checked values from checkbox. If i check only one there is no problem and on req.body there is an object with the value. If i check more than one then it returns the last one in a row i check. I am using express ejs and express.json() as a body parser. This is a section from my app file where i config the express.json() const express = require("express"); const path = require("path"); const rateLimit = require("express-rate-limit"); const helmet =

问题 I have a search box which slides out when you click on a div but it wont let me put any text in and I can't find a reason why. $('#searchh').click(function() { $('.search-button').animate({ 'left': '520px' }); }); $('#searchh').click(function() { $('.search-balk').animate({ 'width': '295px' }); }); .search-button { position: absolute; left: 225px; margin-top: -30px; z-index: -1; -webkit-transition: background-position 0.8s, color 1s; -moz-transition: background-position 0.8s, color 1s;

问题 This question already has answers here : PHP form - on submit stay on same page (9 answers) Closed 3 years ago . I have a form on a website ( www.mywebsite.com ). I have a PHP script that sends me an e-mail with information when somebody submits a form on my website. But with action="submitform.php" in the form, it updates the site to the URL www.mywebsite.com/submitform.php . I would like it to stay on the main site (index). The solution for this: I added header("Location: http://mywebsite

问题 I have tried all of the solutions to similar problems and haven't gotten this one figured out. I have a has_many :through relationship between 'Clinician', and 'Patient' with a joined model 'CareGroupAssignment'. None of the methods I have tried so far been able to save the clinician to patient association. I would like to have a patient be able to have multiple clinicians associated with it and clinicians will have multiple patients . clinician.rb (simplified) class Clinician < ActiveRecord:

问题 Is it possible in Yesod to handle forms that contain a collection of data? I have a form that the user can add multiple people to, on the frontend it currently looks like this: { people.map((person, key) => ( <td> <input type="hidden" name={ `person[${key}][firstName]` } value={person.firstName} /> <input type="hidden" name={ `person[${key}][lastName]` } value={person.lastName} /> { person.firstName } { person.lastName } </td> )) } I then want to be able to translate that over to the backend

问题 I've created component for datepicker that I want to use in many other components in my application. I have some problems becouse it doesn't change value of parent form group control. Lets get to the code: export class DatePickerComponent { @ViewChild('input', {read: ElementRef, static: false}) inputRef: ElementRef; @Input() formName?: FormGroup; @Input() formControlName: any; constructor() { this.formControlName.setValue(['']); } onKeyPress = (event) => { const pressedKey = event.keyCode; if

问题 I am using django-alluth for authentication/registration on my django app. And I need to create a custom signup form with only one field: email. The password will be generated on the server. Here is a form I have created: from django import forms from users.models import User class SignupForm(forms.ModelForm): email = forms.CharField() class Meta: model = User fields = ['email',] esclude = ['password1', 'password'] def __init__(self, *args, **kwargs): super(SignupForm, self).__init__(*args, *

问题 I have a wicket form that has a file upload box on it. Sometimes this file upload box is hidden because the user isn't required to attach documentation. I have called setMultiPart(true) on the form object , but I still (but only rarely) get this error: java.lang.IllegalStateException: ServletRequest does not contain multipart content. One possible solution is to explicitly call Form.setMultipart(true), Wicket tries its best to auto-detect multipart forms but there are certain situation where