format

问题 What's the quickest way to convert a date in one format, say 2008-06-01 to a date in another format, say Sun 1st June 2008 The important bit is actually the 'Sun' because depending on the dayname, I may need to fiddle other things around - in a non-deterministic fashion. I'm running GNU bash, version 3.2.17(1)-release (i386-apple-darwin9.0). [Background: The reason that I want to do it from the command line, is that what I really want is to write it into a TextMate command... It's an annoying

问题 Below is what I have in my table. myTable ++++++++++++++++++++ Parent + Child ++++++++++++++++++++ C1 + G1 C1 + G2 C1 + G3 G3 + D1 G3 + D2 C1 + G4 G4 + D3 G4 + D4 C2 + G5 C2 + G6 C2 + G7 C2 + G8 ++++++++++++++++++++ What, I want is as below using MYSQL. C1 G1 G2 G3 D1 D2 G4 D3 D4 C2 G5 G6 G7 G8 Please let me know if this is possible in MYSQL. The output is something like TREE . Update 1 If I get new table like below is also fine so that I can use this example. ++++++++++++++++++++++++++++++++

问题 string binary = Convert.ToString(15, 2); Console.WriteLine("{0}", binary); Prints: 1111 I want it to print 00001000 Because the data type is of string and not integer I cannot do something like this: Console.WriteLine("{0:00000000}", binary); 回答1: Console.WriteLine( binary.PadLeft(8, '0')); 回答2: You can try this one: Convert.ToString(15, 2).PadLeft(8, '0'); It should give you 00001111 来源： https://stackoverflow.com/questions/7682628/how-to-pad-a-binary-string-with-zeros

问题 I've researched and tried numerous options to try and get this to work, but am not getting anywhere with this unfortunately. What I am trying to do is set the Date Taken tag (Tag_DateTime) in a JPEG's Exif data from within an Android app. I already have working code to set the Latitude and Longitute tags, but cannot for the life of me get the Date taken tag to set. Here is the code: SimpleDateFormat fmt_Exif = new SimpleDateFormat("yyyy:MM:dd HH:mm:ss"); try { ExifInterface exif = new

问题 When I run the following code in Python 2.5.2: for x in range(1, 11): print '{0:2d} {1:3d} {2:4d}'.format(x, x*x, x*x*x) I get: Traceback (most recent call last): File "<pyshell#9>", line 2, in <module> print '{0:2d} {1:3d} {2:4d}'.format(x, x*x, x*x*x) AttributeError: 'str' object has no attribute 'format' I don't understand the problem. From dir('hello') there is no format attribute. How can I solve this? 回答1: The str.format method was introduced in Python 3.0, and backported to Python 2.6

问题 When I run the following code in Python 2.5.2: for x in range(1, 11): print '{0:2d} {1:3d} {2:4d}'.format(x, x*x, x*x*x) I get: Traceback (most recent call last): File "<pyshell#9>", line 2, in <module> print '{0:2d} {1:3d} {2:4d}'.format(x, x*x, x*x*x) AttributeError: 'str' object has no attribute 'format' I don't understand the problem. From dir('hello') there is no format attribute. How can I solve this? 回答1: The str.format method was introduced in Python 3.0, and backported to Python 2.6

问题 I'm printing data line by line and want it to be organized like a table. I initially used firstName + ", " + lastName + "\t" + phoneNumber . But for some of the larger names, the phone number gets pushed out of alignment I'm trying to use String.format() to achieve this effect. Can anyone tell me the format syntax to use? I tried String.format("%s, %s, %20s", firstName, lastName, phoneNumber) , but that's not what I want. I want it to look like this: John, Smith 123456789 Bob, Madison

问题 I'm trying to format this and other elements alike, so it would look like this 2,590: <Add_Amount>2,59</Add_Amount> Doing it like this: <xsl:decimal-format name="dkk" decimal-separator="," grouping-separator="."/> .... <xsl:value-of select="translate(format-number(Add_Amount, '#.###,000', 'dkk'), ',', '.')" /> And the output comes out NaN. Any help is greatly appreciated. Thanks. //Daniel 回答1: Use : format-number(translate(., ',','.'), '#.###,000', 'd') This transformation : <xsl:stylesheet

问题 I have a now time: new Date(); And I have some hour constants, for example, 23 and 8 (it's 11pm or 23:00, 8am or 08:00). How I can know is now time between it's two hour constants? It need to run some code of program or not to run if now time is between in two hours, for example, do not run some code if its already evening and while it is not a morning. Here the image to better explain: Some situations when silent mode does not fire: 00:00 20.06.13 - 23:00 20.06.13 // after 23.00 can loud!!

问题 i need to format the contents of a Json file in a certain format in a pandas DataFrame so that i can run pandassql to transform the data and run it through a scoring model. file = C:\scoring_model\json.js (contents of 'file' are below) { "response":{ "version":"1.1", "token":"dsfgf", "body":{ "customer":{ "customer_id":"1234567", "verified":"true" }, "contact":{ "email":"mr@abc.com", "mobile_number":"0123456789" }, "personal":{ "gender": "m", "title":"Dr.", "last_name":"Muster", "first_name":