format-string

I'm using NSLog() to print some tabular data consisting of an NSString and an associated integer . Assume I know the length of the longest word. Is there a way using format strings to get this kind of column alignment: word:tree rank:5 word:frog rank:3 word:house rank:2 word:peppercorn rank:2 word:sword rank:2 word:antlion rank:1 The reason I'm asking about formatting strings is I'm hoping for a lightweight way to format my ghetto debugging output. Here is what I tried: NSString *word = @"tree"; NSUInteger rank = 4; NSString *str = [NSString stringWithFormat:@"word:%-20@ rank:%u", word, rank];

Examples: "Something %d" and "Something else %d" // Compatible "Something %d" and "Something else %f" // Not Compatible "Something %d" and "Something %d else %d" // Not Compatible "Something %d and %f" and "Something %2$f and %1$d" // Compatible I figured there should be some C function for this, but I'm not getting any relevant search results. I mean the compiler is checking that the format string and the arguments match, so the code for checking this is already written. The only question is how I can call it. I'm using Objective-C, so if there is an Objective-C specific solution that's fine

This simple method just creates an array of dynamic size n and initializes it with values 0 ... n-1. It contains a mistake, malloc() allocates just n instead of sizeof(int) * n bytes: int *make_array(size_t n) { int *result = malloc(n); for (int i = 0; i < n; ++i) { //printf("%d", i); result[i] = i; } return result; } int main() { int *result = make_array(8); for (int i = 0; i < 8; ++i) { printf("%d ", result[i]); } free(result); } When you check the output you will see that it will print some numbers as expected but the last ones are gibberish. However, once I inserted the printf() inside the

#include <stdio.h> int main() { char s[200] int a=123; int b=&a; scanf("%50s",s); printf(s); if (a==31337) func(); } The aim is to execute a format string attack - to execute func() by inputting a string. I tried to use %n to overwrite the variable but I came to conclusion is that it is impossible without displaying b variable first and I have no idea how. Any hint would be appreciated. Sorry for my bad english. Let's try with and without printing: $ cat > f.c << \EOF #include <stdio.h> void func() { fprintf(stderr, "func\n"); } int main() { char s[200]; int a=123; int b=&a; #ifdef FIXER

I have a small C program to be exploited. And I also understood the logic behind the attack to be performed. However, as much as I try, it is just not working for me. #include <stdio.h> #include <stdlib.h> #define SECRET1 0x44 #define SECRET2 0x55 int main(int argc, char *argv[]) { char user_input[100]; int *secret; int int_input; int a, b, c, d; /* other variables, not used here.*/ /* The secret value is stored on the heap */ secret = (int *) malloc(2*sizeof(int)); /* getting the secret */ secret[0] = SECRET1; secret[1] = SECRET2; printf("Please enter a decimal integer\n"); scanf("%d", &int