form-submit

How to submit a form using javascript

由 ε祈祈猫儿з 提交于 2020-01-16 00:45:13
问题 I'm trying to click on a submit button and submit a form using purely javascript. I have tried: document.getElementById('sell_form').submit(); and for(var i=0;i<document.getElementsByName('operation').length;i++){ if(document.getElementsByName('operation')[i].value=='Sell'){ document.getElementsByName('operation')[i].submit(); } } but I just can't get it. Can anyone show me how I could do this? Thanks in advance. The web code is: <form id="sell_form" class="ajaxform" action="/member/sell"

Submit Form dropdown with jQuery

由 怎甘沉沦 提交于 2020-01-15 10:08:11
问题 I am using a dropdown plugin called dropkick, which replaces select menus with better looking, custom dropdowns. I want to display my list of WordPress categories in this dropdown. Here is the PHP code that generates the dropdown: <form action="<?php bloginfo('url'); ?>/" method="get" class="pretty"> <?php $select = wp_dropdown_categories('show_option_none=Select category&show_count=1&orderby=name&echo=0'); echo $select; ?> </form> The JavaScript code to turn this into a "pretty dropdown" is

Submit Form dropdown with jQuery

由 落花浮王杯 提交于 2020-01-15 10:06:03
问题 I am using a dropdown plugin called dropkick, which replaces select menus with better looking, custom dropdowns. I want to display my list of WordPress categories in this dropdown. Here is the PHP code that generates the dropdown: <form action="<?php bloginfo('url'); ?>/" method="get" class="pretty"> <?php $select = wp_dropdown_categories('show_option_none=Select category&show_count=1&orderby=name&echo=0'); echo $select; ?> </form> The JavaScript code to turn this into a "pretty dropdown" is

Submit Form dropdown with jQuery

由 泪湿孤枕 提交于 2020-01-15 10:03:02
问题 I am using a dropdown plugin called dropkick, which replaces select menus with better looking, custom dropdowns. I want to display my list of WordPress categories in this dropdown. Here is the PHP code that generates the dropdown: <form action="<?php bloginfo('url'); ?>/" method="get" class="pretty"> <?php $select = wp_dropdown_categories('show_option_none=Select category&show_count=1&orderby=name&echo=0'); echo $select; ?> </form> The JavaScript code to turn this into a "pretty dropdown" is

angular event success when submit form it opens popup

由 我的梦境 提交于 2020-01-13 11:05:13
问题 I have a page which post data to a ASPNET MVC page by angular $http.post(..) and when the calling finish I have to submit a form. Basically I do the following: <html ng-app> <body data-ng-controller="testController"> <form id="Checkpay" name="Checkpay" style="margin: 0" method="post" action="https://www.sandbox.paypal.com/cgi-bin/webscr" target="_blank" class="ng-pristine ng-valid"> <input type="hidden" name="quantita" id="qtytext" value="0"> <input type="hidden" name="cmd" value="_xclick">

Jquery Rails 3… form submits twice… deletes twice… help

由 无人久伴 提交于 2020-01-10 03:15:12
问题 It seems like eveyone has this problem but no one has a laymans terms answer or even a proper solutions. I have a form that uses ajax to submit the form and automatically adds it to the list below the text field. The form submits twice so i have two identical (apart form the ID) records. Worse still is when you try to delete it wont renew the page because its tried to delete the same record twice. I hope someone has a great answer out there... btw im new to rails. code: index.html.erb <h1

Submit form input fields added with javascript

由 被刻印的时光 ゝ 提交于 2020-01-09 11:10:49
问题 I'm making a simple form to create polls, therefore I want the possibility to add additional input fields in case the user wants more options in the poll. I've made Javascript code that adds a new input field to the form, but the dynamically added input fields are not posted when the form is submitted (I use a standard submit button). Is there some way to get the dynamically added fields posted/recognized as a part of the form? <form id="myForm" method="post"> <input type="submit"> <input

Submit form input fields added with javascript

由 隐身守侯 提交于 2020-01-09 11:06:48
问题 I'm making a simple form to create polls, therefore I want the possibility to add additional input fields in case the user wants more options in the poll. I've made Javascript code that adds a new input field to the form, but the dynamically added input fields are not posted when the form is submitted (I use a standard submit button). Is there some way to get the dynamically added fields posted/recognized as a part of the form? <form id="myForm" method="post"> <input type="submit"> <input

MVC jQuery submit form (without page refresh) from JavaScript function

由 雨燕双飞 提交于 2020-01-09 08:31:07
问题 I'm pretty new to all this. I'm using ASP.NET MVC C# LINQ to SQL. I have an edit page that loads Authors and all their Books. The Books are loaded via an Ajax call. <script type="text/javascript"> $(document).ready(function() { LoadBooks(); }); function LoadBooks() { $(".Books").hide(); $(".Books").load("/Books/Edit/<%= Model.AuthorID %>"); $(".Books").show('slow'); } </script> This part is working fine. The page loads with the Author info, then the Books load (a partial view in a DIV id=

PHP MySQL inserting 3 different form values to 4 different tables

由 你说的曾经没有我的故事 提交于 2020-01-06 18:33:34
问题 I need help with Php forms. I am trying to insert at least 2 & a Max of 3 team players data to MySQL for registration purposes. By using a loop to get the 3 form values and iterate until data is stored in the tables First Table is Players table: columns names are as follows. playerid, playerfirstname, playerlastname, playerdob, playernationalranking, playerphonenumber, playeremailaddress, playerpassportnumber,playerplayinghistory, playeraddress, playercountry Second Table is Participants
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