form-submit

I'm not very familiar with jQuery. I'm trying to make a form that is submitted in the background without reloading page. I have a hidden div which shows and hides on click, inside the div there's a form. I have two problems: 1) When the form validation fails, the form is still submitted. I tried to put validation and submission codes in condition if(validation == valid) { $.ajax.... } but it does not work properly. 2) After the form is submitted the div automatically hides, so successful message cannot be seen. Here's the code: $().ready(function() { // Validate the form when it is submitted,

// html <% using (Html.BeginForm("MyAction", "MyController", new { id = ViewContext.RouteData.Values["id"] }, FormMethod.Post, new { enctype = "multipart/form-data", class="myForm" })) { %> <input type="file" name="blah" /> <% } %> // script $container.find('.myButton').click(function() { $container.find('.myForm').submit(); }); Before the form is submitted, I need to add some extra parameters (route values) which can only be calculated at the time of submit. How do I do that? You could append a hidden field to the form before submitting it: $container.find('.myButton').click(function() { var

How do I get the name of the submit button in PHP? I got the value of submit button, but I could not find any code to get the name of the button. Below is the code I have written. <form name="form1" method="post"> <input type="submit" value="hello" name="submitbutton"> </form> <?php echo "Value of submit button: " . $_POST['submitbutton']; echo "Name of submit button: " . // What should I do here? //; ?> You will find the name in the $_POST array. <?php print_r($_POST); ?> This way you will see everything in the $_POST array. You can iterate through the array with: foreach($_POST as $name =>

In my html I have multiple forms (text inputs, radio buttons, check boxes and select) and one button. I would like to fill all these forms and send values to my php file. For now I am trying to submit values from text input and select but I am stuck at this point. I have a js submit file: submitForms = function(){ document.getElementById("form1").submit(); document.getElementById("form2").submit(); } And my forms are like this: SELECT: <form id ="form1" name="dists" action="solve.php" method="post"> <select id="demo" name="sadzba" onchange="selectElement1(this.value)> <option value="">--

Consider the following HTML: <form action=""> <input /> <select> <option>A</option> <option>B</option> </select> <input type="submit" /> </form> If the focus is on the input (text box) and I hit enter, the form submits. But, if the focus is on the select (dropdown box) and I hit enter, nothing happens. I know I could figure out some JavaScript to override this, but I want to know why hitting enter doesn't just work? Is there something I would break by capturing the enter with JavaScript (maybe some native keyboard accessibility of the dropdown)? It's simply the nature of the control. The Enter

I'm wondering how can I submit a form via Ajax (using prototype framework) and display the server response in a "result" div. The html looks like this : <form id="myForm" action="/getResults"> [...] <input type="submit" value="submit" /> </form> <div id="result"></div> I tried to attach a javascript function (which uses Ajax.Updater) to "onsubmit" (on the form) and "onclick" (on the input) but the form is still "non-Ajax" submitted after the function ends (so the whole page is replaced by the results). Check out Prototype API's pages on Form.Request and Event handling. Basically, if you have

I have this form in my HTML: <form action="/awe/ChangeTheme/Change" method="post"> <select id="themes" name="themes"> ... <option value="blitzer">blitzer</option> </select> <input type="submit" value="change" /> </form> Anybody knows how to submit it when a value is selected in the 'themes' dropdown? The other solutions will submit all forms on the page, if there should be any. Better would be: $(function() { $('#themes').change(function() { this.form.submit(); }); }); $('#themes').change(function(){ $('form').submit(); }); In case your html contains more than one form $(function() { $('