form-submit

Writing a page with use of $.cookie to show a form upon submit in a multi form page. I have seen similar questions go unanswered when it got to this specific code. I have read and read, seems like this should work. Yes, very new to jquery, 1 week. I have container divs (class) each with an p toggle to show/hide each form. Upon submit I want the form to remain .show() so that errors or even response will be seen. p must be clicked to .hide form; so a person could open all the forms. I know there are much more complicated ways to do this. I just want to learn the simple, possibly long hand

I have a form which has a few text boxes, and two submit buttons. When a text box is selected, and I press Enter , the first submit button is triggered. However, this is not the button that should be pressed at that time. How can I make it so that when the Enter button is pressed, the second submit button (or at least, the last occurrence of the submit button) clicked? I have an implementation of this currently using JavaScript, but I'm hoping there is a native option for it. Its pretty tough to get more native than javascript. You're gonna need it here. By the way, the behavior you noticed is

I have a quite complex form that has one "file" input, such as: <input type="file" /> Is it possible to trigger some kind of "upload successful" with JS, so after user uploads the file the whole form submits itself? You can upload your files asynchronously (if you want you may upload multiple files). So for example: <input type="file" class="js-file-upload" multiple> After creating input tag, you can listen to change event $(".js-file-upload").on("change", function(e){ var files = e.target.files; // your own logic to filter files etc. // upload your file }); After all this you can listen to

Using Symfony, version 2.3 and more recent, I want the user to click on a link to go to the edition page of an already existing entity and that the form which is displayed to be already validated, with each error associated to its corresponding field, i.e. I want the form to be validated before the form is submitted. I followed this entry of the cookbook : $form = $this->container->get('form.factory')->create(new MyEntityFormType, $myEntity, array('validation_groups' => 'my_validation_group')); $form->submit($request->request->get($form->getName())); if ($form->isValid()) { ... } But the form

jQuery $.ajax() does not seem to work correctly with IE8 but it is working with Firefox, Chrome and Safari. I am submittin the form and response back in JSON format. Here is my code: test.php: <script type="text/javascript" src="jquery-1.4.2.js"></script> <script type="text/javascript" src="jsFile.js"></script> <form action='_test.php' method='post' class='ajaxform'> <input type='text' name='txt' value='Test Text'> <input type='submit' value='submit'> </form> <div id='testDiv'></div> _test.php: <?php $arr = array( 'testDiv' => $_POST['txt'] ); echo json_encode( $arr ); ?> jsFile.js: jQuery('

I'm having an issue with the jquery function submit for a form : $(document).ready(function () { $('#message').keydown(function(e) { if(e.which == 13 && !e.shiftKey) { $('#edit_message_11').submit(function() { alert("HELLO2"); }); return false; } }); }); <form id="edit_message_11" class="edit_message" method="post" action="/message/11" accept-charset="UTF-8"> <textarea id="message" class="form-control edit_message_form" name="message"> Hello </textarea> http://jsfiddle.net/978QC/ When I do the following for my form : $('#edit_message_11').submit(function() { ... }); it doesn't trigger the