Flutter

How can I dd in-app-purchase functionality to my flutter app?

↘锁芯ラ 提交于 2021-02-13 17:38:07
问题 I am going to add in-app-purchase functionality to my flutter app, but could not find any relevant information or sample app about in-app-purchases, can anyone share any links or example apps that contain in-app-purchase functionality? Thank you 回答1: Have a look at this package https://pub.dev/packages/in_app_purchase dependencies: in_app_purchase: ^0.3.4+8 Example code: import 'dart:async'; import 'dart:io'; import 'package:flutter/material.dart'; import 'package:in_app_purchase/in_app

Handle the list of dynamic checkboxes when the widget is added on button click in flutter

强颜欢笑 提交于 2021-02-13 12:16:56
问题 When clicking the add button, the same widget is replicated. The widget contains the list of checkboxes that are multi selectable. I am able to replicate the widget but I got problem to handle the checkboxes according to the index of the widget. In image below the checkbox checked state is replicated along with the new add widget. I have implemented as follows: Build the widget according to the addbutton click ListView.builder( itemCount: counting, shrinkWrap: true, physics: const

Flutter常用命令和mac电脑常用命令

ⅰ亾dé卋堺 提交于 2021-02-12 15:24:00
0. flutter create example_demo 新建flutter项目 1、 flutter packages get 安装新增的包 2、 flutter run 运行flutter项目:   r 刷新xian jian x页面 R刷新重构程序 h帮助 d和q退出 o 是ios和andriod的切换 3、 flutter doctor 检测必要依赖是否安装成功 4.flutter运行.当有多个模拟器的时候,指定只运行于一个模拟器的方法: More than one device connected; please specify a device with the ' -d <deviceId> ' flag, oruse ' -d all ' to act on all devices. “xx”的 iPhone • ebde052af5111ac5ff3b41dasdasdasdadd6cbfedc • ios • iOS 12.0 . 1 iPhone Xs Max • 6F2F0D31 -9EDF-43EF-AC8D-558FC52D9EC4 • ios • iOS 12.1 (simulator) flutter run -d all 在所有模拟器上运行项目 flutter run -d 6F2F0D31-9EDF-43EF-AC8D

Flutter之Container详解

↘锁芯ラ 提交于 2021-02-12 04:55:45
1 基本内容 1.1 继续关系 Object > Diagnosticable > DiagnosticableTree > Widget > StatelessWidget > Container 注:所有控件都是Widget的子类! 1.2 介绍 一个便利的控件,结合了常见的绘画,定位和大小调整。 1.3 行为 由于Container结合了许多其他Widget,每个Widget都有自己的布局行为,因此Container的布局行为有点复杂。 依次是: 1.采用alignment 2.以child调整自身大小 3. 采用了width,height和constraints 4.扩大以适应父Widget 5.要尽可能小 具体情况来说: 1· 如果Container没有子Widget,没有height,没有width,没有constraints,并且父窗口提供无限制约束,则Container尝试尽可能小。 2· 如果Container没有子Widget,没有alignment,而是一个height,width或 constraints提供,Container试图给出这些限制和父Widget的约束相结合,以尽可能小。 3· 如果Container没有子Widget,没有height,没有width,没有constraints,没有alignment,但是父窗口提供了有界约束

Flutter Scaffold组件详情配制使用

我们两清 提交于 2021-02-11 23:19:33
重要消息 精通点的可以查看这里 精述 Flutter 从入门实践到开发一个APP之UI基础篇 视频 flutter从入门 到精通 系列文章 Flutter Scaffold 组件系列 Scaffold组件的基本使用 Scaffold组件中floatingButton悬浮按钮 Scaffold组件中drawer侧拉页面详述 Scaffold组件中bottomNavigationBar底部导航栏配制 本文章将详细综述Scaffold组件的属性配制 本页面中最终实现的页面效果 1 Scaffold简述 Scaffold 实现了基本的 Material Design 布局结构,Scaffold在英文中的解释为角手架,我们可以理解为楼体中的钢架结构,通过它可以构建一个页面。 在Flutter应用开发中,我们可以将 Scaffold 理解为一个布局的容器。可以在这个容器中绘制我们的用户界面。 2 Scaffold 组件的基本使用 2.1 Flutter应用程序的入口函数 import 'package:flutter/cupertino.dart'; import 'package:flutter/material.dart'; import 'package:mdemo1/scaffold/scffold_home_page.dart'; ///flutter应用程序中的入口函数 void

【Flutter学习】之MaterialApp和Scaffold组件使用详解

与世无争的帅哥 提交于 2021-02-11 23:01:40
一,前言:   MaterialApp和Scaffold是Flutter提供的两个Widget,其中: MaterialApp是一个方便的Widget,它封装了应用程序实现Material Design所需要的一些Widget。 Scaffold组件是Material Design布局结构的基本实现。此类提供了用于显示drawer、snackbar和底部sheet的API。MaterialApp 的 child 是 Scaffold Widget。 二,MaterialApp属性介绍                       * 22个参数 字段 类型 navigatorKey(导航键) GlobalKey<NavigatorState> home(主页) Widget routes(路由) Map<String, WidgetBuilder> initialRoute(初始路由) String onGenerateRoute(生成路由) RouteFactory onUnknownRoute(未知路由) RouteFactory navigatorObservers(导航观察器) List<NavigatorObserver> builder(建造者) TransitionBuilder title(标题) String onGenerateTitle(生成标题)

displayName return null when logged using email and password

烈酒焚心 提交于 2021-02-11 18:14:30
问题 I have two options for user login, using email and password using google sign in When I log using google sign in method its display name, but it not display name when using email and password, user.displayName is return null when using 1st option. I have use provider for authenticating, I have tried currentUser method also. I store users in firestore. This is what I am getting.This is my users collection 回答1: If a user signed up using email and password, there is an option to update

formatexception (formatexception: unexpected character (at character 1) json

怎甘沉沦 提交于 2021-02-11 18:12:07
问题 The error as stated is: formatexception (formatexception: unexpected character (at character 1) json Is there a solution to this? 回答1: Try this one bro final response = await http.post("url", body{ 'username': username, 'password': password, }, header{ 'accept':'*/*' }); 回答2: As you can see in the Exception, you are getting HTML code instead of JSON in the response.body: <!DOCTYPE html PUBLIC "~//W3C/DTD XHTML 1.0 Strict//EN" "http://www.w3.org... The solution would be to receive a JSON or to

displayName return null when logged using email and password

巧了我就是萌 提交于 2021-02-11 18:11:20
问题 I have two options for user login, using email and password using google sign in When I log using google sign in method its display name, but it not display name when using email and password, user.displayName is return null when using 1st option. I have use provider for authenticating, I have tried currentUser method also. I store users in firestore. This is what I am getting.This is my users collection 回答1: If a user signed up using email and password, there is an option to update

formatexception (formatexception: unexpected character (at character 1) json

戏子无情 提交于 2021-02-11 18:10:30
问题 The error as stated is: formatexception (formatexception: unexpected character (at character 1) json Is there a solution to this? 回答1: Try this one bro final response = await http.post("url", body{ 'username': username, 'password': password, }, header{ 'accept':'*/*' }); 回答2: As you can see in the Exception, you are getting HTML code instead of JSON in the response.body: <!DOCTYPE html PUBLIC "~//W3C/DTD XHTML 1.0 Strict//EN" "http://www.w3.org... The solution would be to receive a JSON or to