flatten

问题 I'd like to flatten a nested json object, e.g. {"a":{"b":1}} to {"a.b":1} in order to digest it in solr. I have 11 TB of json files which are both nested and contains dots in field names, meaning not elasticsearch (dots) nor solr (nested without the _childDocument_ notation) can digest it as is. The other solutions would be to replace dots in the field names with underscores and push it to elasticsearch, but I have far better experience with solr therefore I prefer the flatten solution

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed last year . I have several "main" XSD documents, which import "supporting" XSD documents. These schema documents happen to be from the HR-XML 3.0 specification, in particular related to Background Screening. For the purposes of code-generation and convenient single-file schema to reference in my WSDL, I am trying to "flatten"

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed last year . I have several "main" XSD documents, which import "supporting" XSD documents. These schema documents happen to be from the HR-XML 3.0 specification, in particular related to Background Screening. For the purposes of code-generation and convenient single-file schema to reference in my WSDL, I am trying to "flatten"

问题 I am using a coordinate system x (width), y (height), z (Depth) Just to clear confusion if there is any x & y are a flat plane and I am using Z as elevation. I am going to be accessing the array millions of times per second and benchmarking shows that a 1D array using index is faster and I would like to squeeze as much efficiency as possible so that other things can use that time For example a 2D array --> 1D array creation is just Object[] oneDArray = new Object[width * height] and to index

问题 I am trying to write a function to flatten an array. I have part of the function working and I need help in the other half. flatten: function(anyArray, singleLevel) { if (singleLevel == true) { flatArray = Array.prototype.concat.apply([], anyArray); return flatArray; } flatArray = Array.prototype.concat.apply([], anyArray); if (flatArray.length != anyArray.length) { flatArray = someObject.array.flatten(flatArray); } return flatArray; } if I type .flatten([[[1],[1,2,3,[4,5],4],[2,3]]], true);

问题 I'm trying to plot many data using subplots and I'm NOT in trouble but I'm wondering if there is a convenience method to do this. below is the sample code. import numpy as np import math import matplotlib.pyplot as plt quantities=["sam_mvir","mvir","rvir","rs","vrms","vmax" ,"jx","jy","jz","spin","m200b","m200c","m500c","m2500c" ,"xoff","voff","btoc","ctoa","ax","ay","az"] # len(quantities) = 21, just to make the second loop expression # shorter in this post. ncol = 5 nrow = math.ceil(21 /

问题 I'm trying to plot many data using subplots and I'm NOT in trouble but I'm wondering if there is a convenience method to do this. below is the sample code. import numpy as np import math import matplotlib.pyplot as plt quantities=["sam_mvir","mvir","rvir","rs","vrms","vmax" ,"jx","jy","jz","spin","m200b","m200c","m500c","m2500c" ,"xoff","voff","btoc","ctoa","ax","ay","az"] # len(quantities) = 21, just to make the second loop expression # shorter in this post. ncol = 5 nrow = math.ceil(21 /

问题 I was wondering about how I could completely flatten lists and things that contain them. Among other things, I came up with this solution that slips things that have more than one element and puts them back, or takes things with one element after slipping it. This is a bit different than How do I “flatten” a list of lists in perl 6?, which doesn't completely flat because the task is to restructure. But, maybe there's a better way. my @a = 'a', ('b', 'c' ); my @b = ('d',), 'e', 'f', @a; my @c

问题 Given I have an array: $array = array( 'a' => array( 'b' => array( 'c' => 'hello', ), ), 'd' => array( 'e' => array( 'f' => 'world', ), ), ); I want to "flatten" it to a single dimension look-up of references, concatenating keys with a delimiter ( in the case of this example, a forward slash / ) Performing a var_dump() on a successful output would yield: ( note all the references ) array(6) { ["a"]=> &array(1) { ["b"]=> &array(1) { ["c"]=> &string(5) "hello" } } ["a/b"]=> &array(1) { ["c"]=>

问题 I am a beginner interested in Haskell, and I have been trying to implement the flatmap (>>=) on my own to better understand it. Currently I have flatmap :: (t -> a) -> [t] -> [a] flatmap _ [] = [] flatmap f (x:xs) = f x : flatmap f xs which implements the "map" part but not the "flat". Most of the modifications I make result in the disheartening and fairly informationless Occurs check: cannot construct the infinite type: a = [a] When generalising the type(s) for `flatmap' error. What am I