firebug

How do I tell Firefox not to stop if it sees a debugger keyword? I need to avoid a continuous debugger loop in case the website uses debugging protection generating debugger statements on the fly using timers. Here is an example. In case you open the debugging console the script will throw tons of debugger statements, which will block you from normal debugging work. An example website is http://www.avito.ru - the biggest classified site in Russia. Open it and then open the debugger console and it will be immediately stop at the debugger keyword in generated script. (function(x/**/) { (function

As you know var_dump() in addition to value show its data type and length . Is there any way to log its output to FireBug console ? I tried FirePHP and FireLogger but both output only value of a variable (sometimes even incorrect variable value). Walter Tross Maybe what you need is something like this: function var2console($var, $name='', $now=false) { if ($var === null) $type = 'NULL'; else if (is_bool ($var)) $type = 'BOOL'; else if (is_string ($var)) $type = 'STRING['.strlen($var).']'; else if (is_int ($var)) $type = 'INT'; else if (is_float ($var)) $type = 'FLOAT'; else if (is_array ($var)

I'm writing an extension for Firefox, and I need to log some data to Firebug's console. Within the scope of my addon, "console" is undefined, and "window.content.console" is also undefined. So how do I log to the console? robr Since you're not writing Javascript that executes within a window, console is not defined. So you need to reference the Firebug extension first: Firebug.Console.log(str); To log to the console from inside a firefox extension’s javascript: Application.console.log("Hello from my Firefox Extension!"); As far as I know you can only do that if you are creating a JetPack Add

When testing performance of various web pages on my web application I noticed that there are some gaps in net tab (waterfall chart) in firebug. In some cases these may take up half of the time for the whole request. What usually causes these gaps and how can they be removed? The main reason this happens is for files that are loaded by scripts and CSS files. For example: CSS, background images won't start loading until a small delay after the CSS file that links to them loads. Many JS libraries also load images, CSS, and/or other files. These loads won't start until the calling JS is loaded,

如何选择开发工具 有许多可以编辑网页的软件，事实上你不需要用任何专门的软件来建立HTML页面，你所需要的只是一个文本编辑器（或字处理器），如Office Word、记事本、写字板等。制作页面初学者通常都会选择一个集成开发环境（IDE），例如Dreamweaver，入门快、见效快，在不知不觉中已经完成了页面制作。但是随着学习的深入，你就会发现步入了一种窘境，因为过分的依赖IDE导致我们不清楚其实现的本质，知其然但不知其所以然。特别是页面出现BUG时，不用工具你便手足无措，更不用提如何进行页面优化以及完成一些更高级的应用了，所以越聪明的IDE越使我们忽略了华丽网页背后最本质的代码。这里笔者建议学习阶段最后还是选择简单的工具，例如vi或Notepad++之类的工具，只用一些基本的编辑功能，和能使开发语言中关键字高亮显示即可。这样就可以学习到开发语言的本质，对学习非常有帮助，但还是建议在实际开发中多使用功能齐全的IDE，毕竟能提高一定的开发效率。一些常在学习中使用的网页开发工具如图1所示。 图1 常见的网页开发工具 认识浏览器中的开发者工具 使用浏览器解析HTML代码，就像使用音乐播放器听歌曲，用视频播放器看电影一个原理。对于普通用户来说，使用浏览器就是浏览网页，只用到浏览器最基本的功能。而浏览器的厂商可不光为普通用户考虑，还专为开发者提供了很多调试页面的工具，对网页开发、升级

Is there some way to make Firebug not work at all on a website? Daniel Vassallo If the performance of your website suffers when Firebug is enabled, you may want to display a warning, asking users to switch it off. You can easily detect if Firebug is enabled through JavaScript . WARNING: EXTREME EVIL. NEVER EVER USE THIS CODE. Also, it won't deter someone who is resourceful. setTimeout(checkForFirebug, 100); function checkForFirebug() { if (window.console && window.console.firebug) { while(true); //Firebug is enabled } setTimeout(checkForFirebug, 100); } EDIT: I figured I would provide an