firebase-dynamic-links

How to get long-link from dynamic link when opening app for the first time?

我只是一个虾纸丫 提交于 2019-12-24 20:00:31
问题 When I click on a dynamic link I will be redirected to the appstore and from there I download the app. What I really need is the long link of the dynamic link because I got data in it which I need to extract. This method will be opened when I start the app for the first time: -(Bool)application:(UIApplication *)application openURL:(NSURL *)url options:(NSDICtionarry<NSString *, id>options). 回答1: Clarification of terms here: deep link -> this is what you will put inside dynamic link; long

opening an Instant App by a Firebase Dynamic Link with custom parameters (App Links)

倖福魔咒の 提交于 2019-12-24 19:07:01
问题 I'm searching for a way to open an Android Instant app in a mobile browser. The app supports app links (deep linking in http/https). My Android app is working as an instant app and can be opened by an app link in different apps that are not browsers (Gmail, Whatsapp, etc.). I have concluded that the only way to be able to have an instant experience in browser apps is by using Firebase Dynamic Links. The only way it works is by using short Firebase Dynamic Links (without app parameters in the

IOS10 Firebase Dynamic Link Show a Blank Page with Open Button. But Why?

我怕爱的太早我们不能终老 提交于 2019-12-24 08:58:58
问题 blank image show if app not installed I tried to implement firebase dynamic link. It works perfectly if app installed in device but it shows this page if app not installed.It happens every time i try to go to app store. Does anyone have any solution? Please Let me know. Thanks 回答1: This is intentional as a way to help you get around the fact that some apps prefer to show all web content inside of their own in-app WebView and make it difficult for JavaScript redirects (like what Firebase

Is there a way to recognize, that the app was installed thru firebase dynamic link in didFinishLaunchingWithOptions?

雨燕双飞 提交于 2019-12-24 07:17:29
问题 I am implementing firebase dynamic links in my iOS app and I can already parse the link, redirect to AppStore etc. Now I want to distinguish the first run of the app, when user installs it from the dynamic link - I want to skip the intro and show him the content that is expected to be shown. Is there some parameter, that I could catch in application(_:didFinishLaunchingWithOptions:) so I could say that it was launched thru the dynamic link? The method application(_:continueUserActivity

Firebase dynamic linking - Continueuseractivity not returning dynamic link url

我是研究僧i 提交于 2019-12-24 01:19:09
问题 My requirement is to handle universal links on the iOS application. But the dynamic link.url seems to be returning an error as below - "@"error" : @"unauthorized user: username=social-app-invite methodName=/FirebaseLookupService.LookupAppsSummary protocol=loas securityLevel=integritY" When i click on a dynamic link (https://****.app.goo.gl/****) from the notes app, my ios app will be directed to the following callback -> In this function i have the following code - - (BOOL)application:

Remove/delete Firebase dynamic links

家住魔仙堡 提交于 2019-12-23 17:11:04
问题 I have created the dynamic links using Firebase console. But there are no option to remove or delete or edit options. I want to delete dynamic links from the console. Any help appreciate. 回答1: This is not possible. Deleting links would be a problem since that could lead to broken data and user experiences. At Branch.io (full disclosure: I'm on the Branch team), we don't allow link deletion either (you can 'Archive' the link to get it off the screen, but that does not make the URL inactive).

How can I test Firebase Dynamic Links if my app is not in the App Store?

那年仲夏 提交于 2019-12-20 12:06:42
问题 I'd like to be able to open the app and print the parameters when I click on the dynamic link (even though it's not published). Is there a way to do this? 回答1: Yes! In fact, I go through this exact process in the getting started videoS (part 1), (part 2), which I recommend you check out if you haven't yet. But, generally speaking, you can test the "Open my app if I have it installed" flow simply by clicking on a dynamic link. If your app is installed on the device, it should open up just fine

How to create a Dynamic link in Firebase programaticaly? Swift

那年仲夏 提交于 2019-12-20 05:54:34
问题 I would like to create a firebase dynamic, but I can't get error in components.shorten The operation couldn’t be completed. Long link is not parsable. I am following the firebase docs, but I can get the desired outcome. @IBAction func createGroupAction(_ sender: Any) { let dynamicLinkDomain = "https://a5481.app.goo.gl/" let appBundleID = "com.vividapartments.myStr.com" let params:[String : String] = [ "ibi": appBundleID, "isi": "1222420082", "efr":"1", "groupID":"-LDSfWKKbWjyrXiFljT3",

How to create a Dynamic link in Firebase programaticaly? Swift

牧云@^-^@ 提交于 2019-12-20 05:54:02
问题 I would like to create a firebase dynamic, but I can't get error in components.shorten The operation couldn’t be completed. Long link is not parsable. I am following the firebase docs, but I can get the desired outcome. @IBAction func createGroupAction(_ sender: Any) { let dynamicLinkDomain = "https://a5481.app.goo.gl/" let appBundleID = "com.vividapartments.myStr.com" let params:[String : String] = [ "ibi": appBundleID, "isi": "1222420082", "efr":"1", "groupID":"-LDSfWKKbWjyrXiFljT3",

Navigation component seems just working with short dynamic link (firebase)

老子叫甜甜 提交于 2019-12-20 03:29:14
问题 Navigation component seems just working with short dynamic link Example: Long Dynamic Link https://domaindebug.page.link/?link=https://www.website.com&apn=com.x.debug&isi=122...6&ibi=com.ios.x.debug&efr=1 Short Dynamic Link https://domaindebug.page.link/register <fragment android:id="@+id/fragment_register" android:name="com.x.presentation.feature.identification.view.RegisterFragment" tools:layout="@layout/fragment_register"> <action ... /> <argument android:name="code" android:defaultValue="