finite-automata

DFA vs NFA engines: What is the difference in their capabilities and limitations?

由 徘徊边缘 提交于 2019-11-27 17:15:30
I am looking for a non-technical explanation of the difference between DFA vs NFA engines, based on their capabilities and limitations. David Thornley Deterministic Finite Automatons (DFAs) and Nondeterministic Finite Automatons (NFAs) have exactly the same capabilities and limitations. The only difference is notational convenience. A finite automaton is a processor that has states and reads input, each input character potentially setting it into another state. For example, a state might be "just read two Cs in a row" or "am starting a word". These are usually used for quick scans of text to

Practical non-Turing-complete languages?

由 余生长醉 提交于 2019-11-27 17:01:38
Nearly all programming languages used are Turing Complete , and while this affords the language to represent any computable algorithm, it also comes with its own set of problems . Seeing as all the algorithms I write are intended to halt, I would like to be able to represent them in a language that guarantees they will halt. Regular expressions used for matching strings and finite state machines are used when lexing , but I'm wondering if there's a more general, broadly language that's not Turing complete? edit: I should clarify, by 'general purpose' I don't necessarily want to be able to

What is the language of this deterministic finite automata?

由 时光怂恿深爱的人放手 提交于 2019-11-27 04:55:33
Given: I have no idea what the accepted language is. From looking at it you can get several end results: 1.) bb 2.) ab(a,b) 3.) bbab(a, b) 4.) bbaaa Grijesh Chauhan How to write regular expression for a DFA In any automata, the purpose of state is like memory element. A state stores some information in automate like ON-OFF fan switch. A Deterministic-Finite-Automata(DFA) called finite automata because finite amount of memory present in the form of states. For any Regular Language(RL) a DFA is always possible. Let's see what information stored in the DFA (refer my colorful figure). ( note: In

To make sure: Pumping lemma for infinite regular languages only?

由 梦想的初衷 提交于 2019-11-27 02:50:37
问题 So this is not about the pumping lemma and how it works, it's about a pre-condition. Everywhere in the net you can read, that regular languages must pass the pumping lemma, but noweher anybody talks about finite languages, which actually are a part of regular languages. So we might all aggree, that the following language is a finite language as well as it's a regular one, but it definitely does not pass the pumping lemma: L = {'abc', 'defghi'} Please, tell me if simply no one writes about it

Need Regular Expression for Finite Automata: Even number of 1s and Even number of 0s

由 别来无恙 提交于 2019-11-27 01:05:13
My problem may sounds different to you. I am a beginner and I am learning Finite Automata. I am googing over Internet to find the Regular Expression for Finite Automata of Given Machine Below. Can anyone help me to write "Regular Expression for Finite Automata" of above machine Any help will be appreciated Grijesh Chauhan How to write regular expression for a DFA using Arden theorem Lets instead of language symbols 0 , 1 we take Σ = {a, b} and following is new DFA. Notice start state is Q 0 You have not given but In my answer initial state is Q 0 , Where final state is also Q 0 . Language

DFA vs NFA engines: What is the difference in their capabilities and limitations?

由 瘦欲@ 提交于 2019-11-26 18:55:13
问题 I am looking for a non-technical explanation of the difference between DFA vs NFA engines, based on their capabilities and limitations. 回答1: Deterministic Finite Automatons (DFAs) and Nondeterministic Finite Automatons (NFAs) have exactly the same capabilities and limitations. The only difference is notational convenience. A finite automaton is a processor that has states and reads input, each input character potentially setting it into another state. For example, a state might be "just read

Practical non-Turing-complete languages?

由 老子叫甜甜 提交于 2019-11-26 18:49:34
问题 Nearly all programming languages used are Turing Complete, and while this affords the language to represent any computable algorithm, it also comes with its own set of problems. Seeing as all the algorithms I write are intended to halt, I would like to be able to represent them in a language that guarantees they will halt. Regular expressions used for matching strings and finite state machines are used when lexing, but I'm wondering if there's a more general, broadly language that's not

What is the language of this deterministic finite automata?

由 戏子无情 提交于 2019-11-26 11:25:32
问题 Given: I have no idea what the accepted language is. From looking at it you can get several end results: 1.) bb 2.) ab(a,b) 3.) bbab(a, b) 4.) bbaaa 回答1: How to write regular expression for a DFA In any automata, the purpose of state is like memory element. A state stores some information in automate like ON-OFF fan switch. A Deterministic-Finite-Automata(DFA) called finite automata because finite amount of memory present in the form of states. For any Regular Language(RL) a DFA is always

Need Regular Expression for Finite Automata: Even number of 1s and Even number of 0s

由 点点圈 提交于 2019-11-26 09:34:19
问题 My problem may sounds different to you. I am a beginner and I am learning Finite Automata. I am googing over Internet to find the Regular Expression for Finite Automata of Given Machine Below. Can anyone help me to write \"Regular Expression for Finite Automata\" of above machine Any help will be appreciated 回答1: How to write regular expression for a DFA using Arden theorem Lets instead of language symbols 0 , 1 we take Σ = {a, b} and following is new DFA. Notice start state is Q 0 You have

Is there a typical state machine implementation pattern?

由 我只是一个虾纸丫 提交于 2019-11-26 06:51:13
问题 We need to implement a simple state machine in C . Is a standard switch statement the best way to go? We have a current state (state) and a trigger for the transition. switch(state) { case STATE_1: state = DoState1(transition); break; case STATE_2: state = DoState2(transition); break; } ... DoState2(int transition) { // Do State Work ... if(transition == FROM_STATE_2) { // New state when doing STATE 2 -> STATE 2 } if(transition == FROM_STATE_1) { // New State when moving STATE 1 -> STATE 2 }
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