find

问题 I'm looking for user ID #s from a list. However some users no longer exist. I've tried the test method, the on error go to method, and if err.number<> 0 then method. I still receive the Run-time error '91': object variable or with block variable not set . The number does not exist on the the list. Below is my code with a couple of fruitless attempts On Error GoTo errorLn If Err.Number <> 0 Then GoTo errorLn End If Cells.Find(What:=uSSO, After:=ActiveCell, LookIn:=xlFormulas, _ LookAt:=xlPart,

问题 I have logs with some random numbers. What I want to do is find numbers greater than a specific number, eg : find all number > 1234567. Can anybody help? 回答1: A weird regex (not sure it's really usefull) : \d{8,}|123456[8-9]|12345[7-9]\d|1234[6-9]\d{2}|123[5-9]\d{3}|12[4-9]\d{4}|1[3-9]\d{5}|[2-9]\d{6}\b It works only for the number 1234567 you have to modify it for another number. 回答2: You could use Notepad++'s Python Script plugin. Not the best solution, but it works! Install Python Script

问题 Hai guys, I want to find a UL control and then find a LI within that UL and assign a css class to that from a content page.... <ul id="mainMenu" runat="server" style="width:350px;"> <li id="mainHome" runat="server"><a title="Home" href="#" class="home">Home</a></li> <li id="mainManage" runat="server"><a title="Manage" href="#" class="manage">Manage</a></li> <li id="mainEnquiry" runat="server"><a title="Enquiry" href="#" class="enquiry">Enquiry</a></li> <li id="mainReport" runat="server"><a

问题 I'm trying to remove all the dateed logs except the most recent. Before I execute a script to remove the files, I want to of course test my commands to make sure I'm bringing up accurate results. When executing these commands the date is: Sep 1 00:53:44 AST 2014 Directory Listing: Aug 27 23:59 testfile.2014-08-27.log Aug 28 23:59 testfile.2014-08-28.log Aug 29 23:59 testfile.2014-08-29.log Aug 30 23:59 testfile.2014-08-30.log Aug 31 23:59 testfile.2014-08-31.log Sep 1 00:29 testfile.log I

问题 In Python, find and index are very similar methods, used to look up values in a sequence type. find is used for strings, while index is for lists and tuples. They both return the lowest index (the index furthest to the left) that the supplied argument is found. For example, both of the following would return 1 : "abc".find("b") [1,2,3].index(2) However, one thing I'm somewhat confused about is that, even though the two methods are very similar, and fill nearly the same role, just for

问题 I can see the -prune of find not working correctly. I guess -name "efence*" -prune option should select (or find) all files except the one with name efence* right? Or am i wrong in my understanding? The command i executed: find * -maxdepth 0 -name "efence*" -prune Expectation : Select all files at current directory ( maxdepth 0 ) except one with name *efence. Please help me to understand -prune 回答1: Try find * -maxdepth 0 -name "efence*" -prune -o -print The prune option does print matching

问题 In my RichtextBox , if I have written as below. This is my pen, his pen is beautiful. Now I search word "is" then output would be as below. All "is" should be highlighted. 回答1: What about: static class Utility { public static void HighlightText(this RichTextBox myRtb, string word, Color color) { if (word == string.Empty) return; int s_start = myRtb.SelectionStart, startIndex = 0, index; while((index = myRtb.Text.IndexOf(word, startIndex)) != -1) { myRtb.Select(index, word.Length); myRtb

问题 I m doing this def power_two(n, base = -1): result = 2 ** base if result < n: base += 1 power_two(n, base) else: if result == n: print base else: print base - 1 what is the pythonic way to find largest power of two less than X number? EDIT example: power_two(100) return only the power 回答1: Find the logarithm and truncate it: def power_two(n): return int(math.log(n, 2)) 回答2: You could use bit_length(): def power_two(n): return n.bit_length() - 1 By definition for n != 0 : 2**(n.bit_length()-1)

问题 How do I find an object in a sequence satisfying a particular criterion? List comprehension and filter go through the entire list. Is the only alternative a handmade loop? mylist = [10, 2, 20, 5, 50] find(mylist, lambda x:x>10) # Returns 20 回答1: Here's the pattern I use: mylist = [10, 2, 20, 5, 50] found = next(i for i in mylist if predicate(i)) Or, in Python 2.4/2.5, next() is a not a builtin: found = (i for i in mylist if predicate(i)).next() Do note that next() raises StopIteration if no

问题 This question already has answers here : How to get index using LINQ? [duplicate] (7 answers) Closed 5 years ago . I am new to Linq. I have a Customers table.ID,FullName,Organization,Location being the columns. I have a query in Sqlite returning me 2500 records of customers. I have to find the index of the customer where ID=150 for example from this result set. Its a List of Customers. The result set of the query is ordered by organization. I tried with FindIndex and IndexOf but getting