find

JQuery: How to find out how many children an element has?

由 巧了我就是萌 提交于 2019-12-19 17:44:10
问题 How can I use jQuery to find out how many children an element has? Say I have the following structure: <div id="container"> <div id="column1"> <div id="asset1"></div> <div id="asset2"></div> </div> <div id="column2"> <div id="asset1"></div> <div id="asset2"></div> </div> </div> I want to find out how many children the div element: container, has. In this case it would return 2... 回答1: Use children and length: $("#container").children().length 回答2: Use the direct children selector (>) and the

How to find the first and last non-zero values for column and row in an image?

由 元气小坏坏 提交于 2019-12-19 10:58:11
问题 I'm having trouble, because I have this image, what I want to do is just work with the pixels that aren't black. But I have to find the first and last nonzero values to define the boundaries were I will work, the problem is that I can find the first nonzero values(rowandcolumn), but in the last for the column appears the value 1799,and my image is 499x631x3 uint8 , and it should be 533. What is the problem?? My code below: %Find where the image begins and starts [r_min, c_min]=find

Ajax Response Finding HTML Fragments Using Find

由 旧时模样 提交于 2019-12-19 08:52:48
问题 I was doing some test with JQuery find , I have an html response coming from an AJAX request, so initially the result would be this. <!DOCTYPE html> <html> <body> <div id="dashboard"> <div id="dash2"> <h1>Hi</h1> </div> </div> </body> </html> In My Ajax Success code is this.. success : function(response,status) { console.log( $(response).find('#dashboard').html() ); } Upon printing it on the console that gives me an undefined . However when I modify the response page(I created a nesting div)

Get element CSS3 background-color gradient with JS

由 旧时模样 提交于 2019-12-19 08:29:18
问题 At the moment I use the following JS (jQuery) to find the background color (as rgb) of several other divs: $theColor = $(this).css("background-color"); It works perfectly, except with CSS3 gradients. As an example, I have the following css to make the background of a div look similar to a post-it note: background: #FFFAAD; /* old browsers */ background: -moz-linear-gradient(top, #FFFAAD 0%, #FFF47D 100%); /* firefox */ background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,

Why does find . -not -name “.*” not exclude hidden files?

由 时光总嘲笑我的痴心妄想 提交于 2019-12-19 08:17:16
问题 I want to ignore all hidden files, but especially .git and .svn ones when searching (and later replacing) files, not I have found that the most basic way to exclude such hidden files described in many online tutorials doesn't work here. find . -not -name ".*" will also print hidden files. The script I'm trying to write is replace() { if [ -n "$3" ]; then expr="-name \"$3\""; fi find . -type f \( $expr -not -name ".*" \) -exec echo sed -i \'s/$1/$2/g\' {} \; unset expr } 回答1: The thing is -not

Finding the position of a word in a string

由 不问归期 提交于 2019-12-19 08:06:55
问题 With: sentence= input("Enter a sentence") keyword= input("Input a keyword from the sentence") I want to find the position of the keyword in the sentence. So far, I have this code which gets rid of the punctuation and makes all letters lowercase: punctuations = '''!()-[]{};:'"\,<>./?@#$%^&*_~'''#This code defines punctuation #This code removes the punctuation no_punct = "" for char in sentence: if char not in punctuations: no_punct = no_punct + char no_punct1 =(str.lower (no_punct) I know need

Finding the position of a word in a string

由 ≯℡__Kan透↙ 提交于 2019-12-19 08:06:10
问题 With: sentence= input("Enter a sentence") keyword= input("Input a keyword from the sentence") I want to find the position of the keyword in the sentence. So far, I have this code which gets rid of the punctuation and makes all letters lowercase: punctuations = '''!()-[]{};:'"\,<>./?@#$%^&*_~'''#This code defines punctuation #This code removes the punctuation no_punct = "" for char in sentence: if char not in punctuations: no_punct = no_punct + char no_punct1 =(str.lower (no_punct) I know need

Solution to error 'find: missing argument to -exec' with find -exec cp {} TARGET_DIR + [closed]

由 霸气de小男生 提交于 2019-12-19 07:11:31
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . I was getting ready to post this as a question, but after fiddling around with it a little longer, I found the solution. So I thought I would go ahead and post it here in case it helps someone else. I had trouble with find -exec cmd +. I got the error: $ find ./ -name "*JIM*" -exec cp {} $TARGET_DIR + find:

Solution to error 'find: missing argument to -exec' with find -exec cp {} TARGET_DIR + [closed]

由 倖福魔咒の 提交于 2019-12-19 07:11:06
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . I was getting ready to post this as a question, but after fiddling around with it a little longer, I found the solution. So I thought I would go ahead and post it here in case it helps someone else. I had trouble with find -exec cmd +. I got the error: $ find ./ -name "*JIM*" -exec cp {} $TARGET_DIR + find:

add filename to beginning of file using find and sed

由 僤鯓⒐⒋嵵緔 提交于 2019-12-19 06:30:17
问题 using the following I add the file name to the front of each line and send the output to a single file. ls | while read file; do sed -e "s/^/$file/g" $file > out; done I want to perform the same sed replacement but using a find and exec or xargs command - find . -type f -exec sed "s/^/{}/g" {} > out + but I get an error - find: Only one instance of {} is supported with -exec ... + Input files are like this - fileA.txt A1 A2 fileB.txt B1 B2 desired output fileA.txt A1 fileA.txt A2 fileB.txt B1
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