find

问题 I'm stucked with using Find and set as variable. I cannot get the result I need. In first sheet I have a column Test with values x or (x). If the value is x I need to copy the value from column EN. If the value is (x) do not copy. the code copies values from column "EN" no matter x or (x) I must have probably an error in using Set stfound Dim ENcolumn Dim xcolumn Dim secrow Dim lastrow Dim totrow Worksheets("List1").Activate Worksheets("List1").Range("A1:C1").Find(What:="EN", MatchCase:=True,

问题 I'm trying to retrieve a user name to insert into a comment on a blog post using rails if I use <%= comment.user_id %>" it will give me an id but if I try and retrieve the user then call the name it return nil class <%= User.find_by_id(comment.user_id).name %>" why is this not working if I leave .name off it returns a space in memory. #<User:000x00000182fe48> 回答1: Most likely, the dynamic finder is getting confused by the id and is returning the (Ruby) object's id (i.e. object_id ) instead of

问题 I'm trying to retrieve a user name to insert into a comment on a blog post using rails if I use <%= comment.user_id %>" it will give me an id but if I try and retrieve the user then call the name it return nil class <%= User.find_by_id(comment.user_id).name %>" why is this not working if I leave .name off it returns a space in memory. #<User:000x00000182fe48> 回答1: Most likely, the dynamic finder is getting confused by the id and is returning the (Ruby) object's id (i.e. object_id ) instead of

问题 Suppose that I have two arrays of size p ( p is large) that have values from 0,1,2 . I am looking for a way to find the index that both arrays have value 2 at the same entry, the index that one has value 2 and the other one has value 1 , etc (like 2 and 2 , 2 and 1 , `2 and 0 , 1 and 1 , 1 and 0`). Is there a way to achieve this without using the for loop on p ? 回答1: You can use logical arrays, let A and B be your arrays (with consistent sizes): Indices=find((A==2)&(B==2)); Etc. for other

问题 I often use grep twice with find in order to search for two patterns in a file as follows: find . -name \*.xml | xargs grep -l "<beans" | xargs grep singleton Then I ran into files with spaces which of course broke the above command. I modified it as follows to deal with the spaces: find . -name \*.xml -print0 | xargs -0 grep -l "<beans" | xargs grep singleton The option -print0 tells find to use print null as a separator instead of space and -0 tells xargs to expect a null. This works as

问题 I am trying to retrieve files from 3 network drives using list.files and it takes for ever. When I am using find in the shell it returns all results in less then 15 seconds. system.time( jnk <- list.files(c("/Volumes/massspec", "/Volumes/massspec2", "/Volumes/massspec3"), pattern='_MA_.*_HeLa_', recursive=TRUE)) # user system elapsed # 1.567 6.381 309.500 Here is the equivalent shell command. time find /Volumes/masssp* -name *_MA_*_HeLa_* # real 0m13.776s # user 0m0.361s # sys 0m0.620s I need

问题 Is it possible to compare two arrays and remove the values that are equal (if they are at the same index), without iterating through both arrays? Here is an example: $array1 = @(1,2,3,4,5,6,7,23,44) $array2 = @(1,1,3,4,5,7,6,23,45) $array3 = $sudo_compare_function $array1 $array2 where $array3 would now contain an array of indexes where $array2 is different from $array1 array: (1,5,6,8) If there isn't something like this, is there an easy way to do something similar without iterating through

问题 I have more 3000 files in a folder. I want to find and replace text with another one. How can I do that? I'm a newbie in batch script. I can replace it in 1 file but I don't know how to replace in multiple files. FOR /F %%L IN (lala.txt) DO ( SET "line=%%L" SETLOCAL ENABLEDELAYEDEXPANSION set "x=!line:E:\Test=E:\Test\Temp!" echo f | xcopy /E !line! !x! ENDLOCAL ) How can I edit my code to replace the string in all files? Waiting for your help. Thanks 回答1: Install the Find And Replace Text

问题 Using the code below I'm able to look through multiple sheets in a spreadsheet to find the first value that equals the selected cell. The only problem with this bit is: The cell with the value found is highlighted yellow, but the cell with the value found isn't selected. See code below for hopping through sheets. I can't get my head around this :) Funny thing is that the code for highlighting and selecting a value does work when I'm not hopping through the list of sheets, see the best answer:

问题 I have a collection looking somewhat like this: { "colors": ["blue","white"], "items": { "old": { "name": "test" } "current": { "name": "new_test" } } }, { "colors": ["red","green"], "items": { "old": { "name": "test2" } "current": { "name": "new_test2" } } }, Is it possible to use find like this: db.collection.find({"items": { "old": { "name": "test" } } }) So the command would return: { "colors": ["blue","white"], "items": { "old": { "name": "test" } "current": { "name": "new_test" } } } Is