find-occurrences

问题 I know how to go through whole array, but I only need number of duplicate occurrences. I'm at beginners level, so just basic use of loops and arrays. int[] array = {12, 23, -22, 0, 43, 545, -4, -55, 43, 12, 0, -999, -87}; for (int i = 0; i < array.length; i++) { int count = 0; for (int j = 0; j < array.length; j++) { count++; } System.out.println(array[i] + "\toccurs\t" + count + "X"); } 回答1: You can do better if you use more than just loops and arrays, but a simple algorithm would be to use

问题 I know how to go through whole array, but I only need number of duplicate occurrences. I'm at beginners level, so just basic use of loops and arrays. int[] array = {12, 23, -22, 0, 43, 545, -4, -55, 43, 12, 0, -999, -87}; for (int i = 0; i < array.length; i++) { int count = 0; for (int j = 0; j < array.length; j++) { count++; } System.out.println(array[i] + "\toccurs\t" + count + "X"); } 回答1: You can do better if you use more than just loops and arrays, but a simple algorithm would be to use

问题 I want to find out how many time a specific words occur in a String JavaScript, or we can say the total amount of matched/match word with the complete sentence string in JavaScript. query = "fake"; var inputString = "fakefakefakegg fake 00f0 221 Hello wo fake misinfo fakeddfakefake , wo misinfo misinfo co wo fake , fake fake fake "; expected result = 13 (there is 13 fake in the above sentence) 回答1: Here are two methods to find the total number of occurrence match words in the string. The

问题 I want to find out how many time a specific words occur in a String JavaScript, or we can say the total amount of matched/match word with the complete sentence string in JavaScript. query = "fake"; var inputString = "fakefakefakegg fake 00f0 221 Hello wo fake misinfo fakeddfakefake , wo misinfo misinfo co wo fake , fake fake fake "; expected result = 13 (there is 13 fake in the above sentence) 回答1: Here are two methods to find the total number of occurrence match words in the string. The

问题 Update Thanks to @jazzurro for his anwer. It made me realize that the duplicates may just complicate things. I hope by keeping only unique values/row simplifies the task.* df <- data.frame(ID = c(1,2,3,4,5), CTR1 = c("England", "England", "England", "China", "Sweden"), CTR2 = c("England", "China", "China", "England", NA), CTR3 = c("USA", "USA", "USA", "USA", NA), CTR4 = c(NA, NA, NA, NA, NA), CTR5 = c(NA, NA, NA, NA, NA), CTR6 = c(NA, NA, NA, NA, NA)) ID CTR1 CTR2 CTR3 CTR4 CTR5 CTR6 1

问题 I have a string foo-bar-bat.bla I wish to match only foo My flawed pattern matches both foo and bar \w+(?=-.*\.bla) How do I discard bar ? Or maybe even better, how could I stop matching stuff after foo ? 回答1: You could use the following pattern (as long as your strings are always formatted the way you said) : ^\w+(?=-.*\.bla) Edit live on Debuggex The ^ sign matches the beginning of the string. And thus will take the very first match of the string. The ?= is meant to make sure the group

问题 I would like to count the occurrences of "1" in the sliced array of "col3". "y = (arr[row-x:row2]).sum()" is just an example that the codes run! Here i obtain something like: "y = (arr[row-x:row, 2]).count(1)" to count a dynamic array of row 2, how often "1" occurred. #Stackoverflow example from numba import njit import pandas as pd d = {'col1': [20, 23, 25, 44, 46, 47, 48, 49, 50, 50, 52, 55, 56, 69, 70], 'col2': [39, 32, 42, 50, 63, 67, 64, 68, 68, 74, 59, 75, 58, 71, 66], 'col3': [1, 1, 1,

问题 I want to count the occurrences of a specific value (in my case -1 ) in a numpy array and delete them at the same time. I could do that so here is what I've done: a = np.array([1, 2, 0, -1, 3, -1, -1]) b = a[a==-1] a = np.delete(a, np.where(a==-1)) print("a -> ", a) # a -> [1 2 0 3] print("b -> ", b) # b -> 3 Is there any more optimised way to do it ? 回答1: Something like this ? Using numpy like you did is probably more optimized though. a = [x for x in a if x != -1] 回答2: First, a list in

问题 I'm a rookie in R and currently working with collaboration data in the form of an edge list with 32 columns and around 200.000 rows. I want to create a (co-)occurrence matrix based on the interaction between countries. However, I want to count the number of interactions by the total number of an object. Basic Example of Aspired Outcome If in one row "England" occurs three times and "China" only one time, the result should be the following matrix. England China England 3 3 China 3 1

问题 I want to update all fields of a column, a lot of them have a desired string in there, but I want this string to be in only each field once, for instance : "MyString OtherString MyString AnotherString AndAnother MyString" to "MyString OtherString AnotherString AndAnother" would you have any idea on how to achieve this ? 回答1: If "MyString" will always occur as the first term in the field, this would work: update MyTable set MyField = replace(MyField, ' MyString','') The key point above is that