Why does PHP filter_var say that this is a valid email address?
问题 I use the filter_var PHP function to validate email address when a user signs up to my site. I use this code from the post: $email = filter_var($_POST['email'], FILTER_VALIDATE_EMAIL); then later I do: if(!$email) { // return to the form } else { // send registration info } now when I var_dump($email) , I get the output: string(23) "user."name"@example.com" I would like to know why this does not return false. I think the double quotes are not acceptable, so why does PHP say it’s valid? 回答1: