file-get-contents

how can I display an image retrieved using file_get_contents in php? Do i need to modify the headers and just echo it or something? Thanks! Do i need to modify the headers and just echo it or something? exactly. Send a header("content-type: image/your_image_type"); and the data afterwards. robjmills You can use readfile and output the image headers which you can get from getimagesize like this: $remoteImage = "http://www.example.com/gifs/logo.gif"; $imginfo = getimagesize($remoteImage); header("Content-type: {$imginfo['mime']}"); readfile($remoteImage); The reason you should use readfile here

I use file_get_contents function to get and show external links on my specific page. In my local file everything is okay, but my server doesn't support the file_get_contents function, so I tried to use cURL with the below code: function file_get_contents_curl($url) { $ch = curl_init(); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_URL, $url); $data = curl_exec($ch); curl_close($ch); return $data; } echo file_get_contents_curl('http://google.com'); But it returns a blank page. What is wrong? try this: function file_get_contents_curl(

I realise I can do this with CURL very easily, but I was wondering if it was possible to use file_get_contents() with the http stream context to upload a file to a remote web server, and if so, how? First of all, the first rule of multipart Content-Type is to define a boundary that will be used as a delimiter between each part (because as the name says, it can have multiple parts). The boundary can be any string that is not contained in the content body . I will usually use a timestamp: define('MULTIPART_BOUNDARY', '--------------------------'.microtime(true)); Once your boundary is defined,