fibonacci

I see lot of examples of generator functions, but I want to know how to write generators for classes. Lets say, I wanted to write Fibonacci series as a class. class Fib: def __init__(self): self.a, self.b = 0, 1 def __next__(self): yield self.a self.a, self.b = self.b, self.a+self.b f = Fib() for i in range(3): print(next(f)) Output: <generator object __next__ at 0x000000000A3E4F68> <generator object __next__ at 0x000000000A3E4F68> <generator object __next__ at 0x000000000A3E4F68> Why is the value self.a not getting printed? Also, how do I write unittest for generators? How to write a

I need to make a program that asks for the amount of Fibonacci numbers printed and then prints them like 0, 1, 1, 2... but I can't get it to work. My code looks the following: a = int(raw_input('Give amount: ')) def fib(): a, b = 0, 1 while 1: yield a a, b = b, a + b a = fib() a.next() 0 for i in range(a): print a.next(), I would use this method: Python 2 a = int(raw_input('Give amount: ')) def fib(n): a, b = 0, 1 for _ in xrange(n): yield a a, b = b, a + b print list(fib(a)) Python 3 a = int(input('Give amount: ')) def fib(n): a, b = 0, 1 for _ in range(n): yield a a, b = b, a + b print(list

I am trying to find complexity of Fibonacci series using a recursion tree and concluded height of tree = O(n) worst case, cost of each level = cn , hence complexity = n*n=n^2 How come it is O(2^n) ? The complexity of a naive recursive fibonacci is indeed 2ⁿ. T(n) = T(n-1) + T(n-2) = T(n-2) + T(n-3) + T(n-3) + T(n-4) = = T(n-3) + T(n-4) + T(n-4) + T(n-5) + T(n-4) + T(n-5) + T(n-5) + T(n-6) = ... In each step you call T twice, thus will provide eventual asymptotic barrier of: T(n) = 2⋅2⋅...⋅2 = 2ⁿ bonus : The best theoretical implementation to fibonacci is actually a close formula , using the

I'm new to Javascript and was reading up on it, when I came to a chapter that described function recursion. It used an example function to find the nth number of the Fibonacci sequence. The code is as follows: function fibonacci(n) { if (n < 2){ return 1; }else{ return fibonacci(n-2) + fibonacci(n-1); } } console.log(fibonacci(7)); //Returns 21 I'm having trouble grasping exactly what this function is doing. Can someone explain what's going on here? I'm getting stuck on the 5th line, where the function calls itself. What's happening here? You're defining a function in terms of itself. In

I am interested in an iterative algorithm for Fibonacci numbers, so I found the formula on wiki...it looks straight forward so I tried it in Python...it doesn't have a problem compiling and formula looks right...not sure why its giving the wrong output...did I not implement it right ? def fib (n): if( n == 0): return 0 else: x = 0 y = 1 for i in range(1,n): z = (x + y) x = y y = z return y for i in range(10): print (fib(i)) output 0 None 1 1 1 1 1 1 The problem is that your return y is within the loop of your function. So after the first iteration, it will already stop and return the first

var x=0, var y=1; var z; fib[0] = 0; fib[1] = 1; for(i=2; i<=10; i++) { alert(x+y); fib[i]=x+y; x=y; z=y; } I'm trying to get to generate a simple Fibonacci sequence but there no output. Can anybody let me know what's wrong? Rob W You have never declared fib to be an array. Use var fib = []; to solve this. Also, you're never modifying the y variable, neither using it. The code below makes more sense, plus, it doesn't create unused variables: var i; var fib = []; // Initialize array! fib[0] = 0; fib[1] = 1; for (i = 2; i <= 10; i++) { // Next fibonacci number = previous + one before previous //