factories

In FactoryBoy, how do I set a many-to-many field in my factory?

由 痴心易碎 提交于 2020-06-17 09:34:06
问题 I'm using Django 2.2 and FactoryBoy to attempt to create some factories to produce the following models ... class CoopType(models.Model): name = models.CharField(max_length=200, null=False) objects = CoopTypeManager() class Meta: # Creates a new unique constraint with the `name` field constraints = [models.UniqueConstraint(fields=['name'], name='coop_type_unq')] class Coop(models.Model): objects = CoopManager() name = models.CharField(max_length=250, null=False) types = models.ManyToManyField

Creating a Factory association that defaults to nil?

由 久未见 提交于 2020-01-04 06:53:48
问题 Using the FactoryGirl gem, inside the factories.rb file, how can I create a factory with an association that defaults to nil? I am thinking something along these lines: Factory.define :user do |factory| factory.association :post factory.association :comment, :default => nil end Would that be right and would that be ok to do? 回答1: Factory.define :user do |factory| factory.association :post factory.comment_id nil end 回答2: FactoryGirl now benefits from a :null strategy. Therefore, you can define

Symfony web debug tool bar disappears when using sfNoLogger

由 自闭症网瘾萝莉.ら 提交于 2019-12-11 20:34:08
问题 Why does the web debug tool bar disappear when I use sfNoLogger in the factories.yml: dev: logger: class: sfNoLogger param: level: err loggers: ~ When I remove these lines the tool bar appears. 回答1: Because the sf*No*Logger does not log anything. It's usually used for production. 来源： https://stackoverflow.com/questions/5119955/symfony-web-debug-tool-bar-disappears-when-using-sfnologger

How to create 2 instances using factorymethod

由 淺唱寂寞╮ 提交于 2019-12-11 15:36:12
问题 I am trying to write a test for my rails application using rspec, I basically want to create two instances 1)a user with counter value 0 2)a user with counter value 5 or more Here is my factory user code FactoryBot.define do factory :user do sequence(:email) { |n| "user#{n}@abc.com" } name 'rishabh agarwal' password '12345678' counter 0 end end In user_controller_spec file I have written context 'get#redeem' do it 'should not redeem the account for points lesser than 5' do get :redeem, format

Use a factory's sequence to generate unique phone numbers

由 霸气de小男生 提交于 2019-12-11 02:59:41
问题 I'm new to TDD, RSpec and factories, and trying to understand how to test that each User's phone number attribute is unique. To do so, I'm trying to use a sequence in my User factory. I'm not having much luck with the following: FactoryGirl.define do factory :user do number = 123456789 sequence(:phone_number) {|n| (number + n).to_s } end end Any thoughts on the best way to accomplish this? Also, what kind of test would make sense for something like this where ultimately I would want to add

DDD - How to implement factories [closed]

由 心不动则不痛 提交于 2019-12-10 13:29:23
问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 6 years ago . I would like to know how to implement factories in domain driven design. (examples) Where should be placed interfaces and implementations of factories ? Do I need to create interfaces for Domain objects which

How to send KendoUI data source OData parameters to an abstract RESTful AngularJS data factory?

由 久未见 提交于 2019-12-06 05:19:14
问题 Some time ago, I setup an abstract data factory in AngularJS, and need a hint on how to simplify its use. I was initially under the impression that I would create another factory per entity that would be called from an AngularJS controller. Turns out it just looks too complicated and I would like to remove the intermediary entity factory ( ContentTypesFactory ), and simply call the abstract factory directly from the AngularJS controller. In the following example I'm wiring up a KendoUI

What is a Factory Design Pattern in PHP?

由 你。 提交于 2019-11-26 19:26:34
This confuses me, in the most simplest terms what does it do? Pretend you are explaining to your mother or someone almost please. Tyler Carter A factory creates an object. So, if you wanted to build class A{ public $classb; public $classc; public function __construct($classb, $classc) { $this->classb = $classb; $this->classc = $classc; } } You wouldn't want to rely on having to do the following code everytime you create the object $obj = new ClassA(new ClassB, new Class C); That is where the factory would come in. We define a factory to take care of that for us: class Factory{ public function

What is a Factory Design Pattern in PHP?

由 跟風遠走 提交于 2019-11-26 06:58:27
问题 This confuses me, in the most simplest terms what does it do? Pretend you are explaining to your mother or someone almost please. 回答1: A factory creates an object. So, if you wanted to build class A{ public $classb; public $classc; public function __construct($classb, $classc) { $this->classb = $classb; $this->classc = $classc; } } You wouldn't want to rely on having to do the following code everytime you create the object $obj = new ClassA(new ClassB, new Class C); That is where the factory
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