factorial

问题 This question already has answers here : Why does Java think that the product of all numbers from 10 to 99 is 0? (9 answers) Closed 4 years ago . I have created a recursive method to calculate the facortial of a number, however, it is always returning 0, and I can not see why. I have provided my code below: public class projectTwenty { public static void main(String [] args) { int factorialAns = factorial(100); System.out.println(factorialAns); } private static int factorial(int n) { if (n ==

问题 Consider the following implementation of a function to compute factorial: [1] (define fac-tail (lambda (n) (define fac-tail-helper (lambda (n ac) (if (= 0 n) ac (fac-tail-helper (- n 1) (* n ac))))) (fac-tail-helper n 1))) I attempted to rewrite using let for the inner define: (define fac-tail-2 (lambda (n) (let ((fac-tail-helper-2 (lambda (n ac) (if (= 0 n) ac (fac-tail-helper-2 (- n 1) (* n ac)))))) (fac-tail-helper-2 n 1)))) There is no error at define time, but execution results in: #;>

问题 I am trying to calculate the least significant non-zero digit in a factorial. I have the following snippet : $(document).ready(function() { $('#submit').click(function() { var n = $('#number').val(); get_result(n); }); }); function get_result(n) { var factorial = 1; var factorial2 = 1; for (i = 1; i <= n; i++) { factorial = factorial * i; } var count_5 = 0; for (j = 1; j <= n; j++) { if (j % 5 != 0) { factorial2 = factorial2 * (j % 10); factorial2 = factorial2 % 10; } else if (j % 5 == 0) {

问题 I am trying to do Factorial with Recursion and BigIntegers but eclipse is complaining about the BigInteger. I know the program is supposed to be simple but it is giving me headache. Here is the code. import java.util.Scanner; import java.math.BigInteger; public class Factorial { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println("Enter integer"); BigInteger n = input.nextBigInteger(); System.out.println("Factorial of " + n + " is " + fact(n));

问题 I need to calculate the factorial of a big number (<=1.000.000) and I need the result modulo 1000000007. I wrote the following but it generates an error when run (test.exe has stopped working). It works only for small numbers. long long unsigned modulo(long long unsigned nr){ return nr % 1000000007; } long long unsigned fact(long long unsigned nr){ if(nr)return modulo(nr * fact(nr - 1)); else return 1; } UPDATE 1: long long unsigned fact(long long unsigned nr){ long long unsigned r = nr;

问题 This question already has answers here : How can I force division to be floating point? Division keeps rounding down to 0? (11 answers) Closed 4 years ago . Q. ) 1 + 1 / 2! + 1/ 3! + ¼! + …..... The output of the following program is always 1.0. I'm a python beginner. Please tell me what's wrong? Please suggest any other methods to make this program better. No inbuilt functions, please. I want to do this manually. n=int(raw_input("Enter number of terms : ")) d=0 #to sum all terms, initial

问题 I need to write an application that will take a list of files (some large, some small) and fit them onto DVDs (or CDs, or whatever) as efficiently as possible. The whole point of this application is to use up as much of the 1st disc before moving onto the 2nd disc, filling the 2nd disc up as much as possible before moving onto the 3rd disc, etc. (Note: The application doesn't have to do the actual burning to the DVD, it just has to figure out the best possible fit). I initially thought I had

问题 I'm trying to compute the value of 7 factorial and display the answer, but when I tried to look up a way to do this I kept finding code that was written so that a number first had to be put in from the user and then it would factor whatever number the user put in. But I already know what number I need, obviously, so the code is going to be different and I'm having trouble figuring out how to do this. I tried this at first public class Ch4_Lab_7 { public static void main(String[] args) { int

问题 I need a good factorial function. The one I have written here works entirely, except when n gets far too large. This is for a calculator app, and I can return 0 / 0 for values that cannot be factorialed because I have an error checker that will declare that as impossible. However performing the function on a very large number crashes the app. I can't use a range operator because my types are doubles. func factorial(n: Double) -> Double { if n >= 0 { return n == 0 ? 1 : n * self.factorial(n -

问题 As a part of my BigDecimal library, I need to calculate the factorial of any given non negative integer. So I'm using .Net 4.0 's System.Numerics.BigInteger to be able to store huge numbers. Here is the function I'm using: private BigInteger Factorial(BigInteger x) { BigInteger res = x; x--; while (x > 1) { res *= x; x--; } return res; } It's working but not optimized. Now I want to use parallel computing, so here is what I've tried: (I have no experience with parallel programming) public