extend

Laravel extend Form class

由 依然范特西╮ 提交于 2019-11-27 14:13:09
I'm trying to extend the Form class in L4.1 but I seem to be missing something. My file is named FormBuilder.php based on the API and is saved in app/libraries/extended/FormBuilder.php . <?php namespace Extended; class FormBuilder extends \Illuminate\Html\FormBuilder { /** * Create a text input field. * * @param string $name * @param string $value * @param array $options * @return string */ public function text($name, $value = null, $options = array()) { $options = $options + array('id'=>"field-{$name}"); return $this->input('text', $name, $value, $options); } } This is actually the first time

Is it possible to extend enum in Java 8?

由 假如想象 提交于 2019-11-27 11:57:54
问题 Just playing and came up with a sweet way to add functionality to enum s in Java Enum toString() method with this. Some further tinkering allowed me to nearly also add a tidy (i.e. not throwing an exception) reverse look-up but there's a problem. It's reporting: error: valueOf(String) in X cannot implement valueOf(String) in HasValue public enum X implements PoliteEnum, ReverseLookup { overriding method is static Is there a way? The aim here is to silently add (via an interface implementation

Extending a java ArrayList

由 こ雲淡風輕ζ 提交于 2019-11-27 11:42:41
问题 I'd like to extend ArrayList to add a few methods for a specific class whose instances would be held by the extended ArrayList. A simplified illustrative code sample is below. This seems sensible to me, but I'm very new to Java and I see other questions which discourage extending ArrayList, for example Extending ArrayList and Creating new methods. I don't know enough Java to understand the objections. In my prior attempt, I ending up creating a number of methods in ThingContainer that were

Ways to extend Array object in javascript

由 核能气质少年 提交于 2019-11-27 11:08:15
问题 i try to extend Array object in javascript with some user friendly methods like Array.Add() instead Array.push() etc... i implement 3 ways to do this. unfortunetly the 3rd way is not working and i want to ask why? and how to do it work. //------------- 1st way Array.prototype.Add=function(element){ this.push(element); }; var list1 = new Array(); list1.Add("Hello world"); alert(list1[0]); //------------- 2nd way function Array2 () { //some other properties and methods }; Array2.prototype = new

Can I extend the console object (for rerouting the logging) in javascript?

由 烂漫一生 提交于 2019-11-27 08:34:43
Is it possible to extend the console object? I tried something like: Console.prototype.log = function(msg){ Console.prototype.log.call(msg); alert(msg); } But this didn't work. I want to add additional logging to the console object via a framework like log4javascript and still use the standard console object (in cases where log4javascript is not available) in my code. Thanks in advance! Try following: (function() { var exLog = console.log; console.log = function(msg) { exLog.apply(this, arguments); alert(msg); } })() Mike Gleason jr Couturier Use the proxy pattern, see my answer for a similar

Does LESS have an “extend” feature?

由 泄露秘密 提交于 2019-11-27 06:35:10
SASS has a feature called @extend which allows a selector to inherit the properties of another selector, but without copying the properties (like mixins). Does LESS have this feature as well? jonschlinkert Yes, Less.js introduced extend in v1.4.0 . :extend() Rather than implementing the at-rule ( @extend ) syntax used by SASS and Stylus, LESS implemented the pseudo-class syntax, which gives LESS's implementation the flexibility to be applied either directly to a selector itself, or inside a statement. So both of these will work: .sidenav:extend(.nav) {...} or .sidenav { &:extend(.nav); ... }

How to add a method to an existing class in PHP?

由 这一生的挚爱 提交于 2019-11-27 05:37:06
问题 I'm using WordPress as a CMS, and I want to extend one of its classes without having to inherit from another class; i.e. I simply want to "add" more methods to that class: class A { function do_a() { echo 'a'; } } then: function insert_this_function_into_class_A() { echo 'b'; } (some way of inserting the latter into A class) and: A::insert_this_function_into_class_A(); # b Is this even possible in tenacious PHP? 回答1: If you only need to access the Public API of the class, you can use a

Python extend with an empty list bug? [duplicate]

由 孤者浪人 提交于 2019-11-27 04:58:47
This question already has an answer here: Why does list.append evaluate to false in a boolean context? [duplicate] 7 answers Why does python 2.5.2 have the following behavior >>>[2].extend([]) == [2] False >>> [2].extend([]) == None True $ python --version Python 2.5.2 I assume I'm not understanding something here, but intuitively I'd think that [2].extend([]) should yield [2] Extend is a method of list, which modifies it but doesn't return self (returning None instead). If you need the modified value as the expression value, use + , as in [2]+[] . Exactly. >>> x = [2] >>> x.extend([]) #

Merge JS objects without overwriting

由 萝らか妹 提交于 2019-11-27 03:28:29
问题 Suppose you have two objects: var foo = { a : 1, b : 2 }; var bar = { a : 3, b : 4 } What's the best way to merge them (and allow deep merging) to create this: var foobar = { a : [1, 3], b : [2, 4] } Edit for question clarification: Ideally, in the case of an existing property in one and not the other, I would expect an array to still be created, for normalization purposes and to allow for further reduction of the map, however the answers I'm seeing below are more than sufficient. For the

Extending an existing jQuery function

由 浪子不回头ぞ 提交于 2019-11-27 03:17:52
I am trying to write a plugin that will extend an existing function in jQuery, e.g. (function($) { $.fn.css = function() { // stuff I will be extending // that doesn't affect/change // the way .css() works }; })(jQuery); There are only a few bits I need to extend of the .css() function. Mind me for asking, I was thinking about PHP classes since you can className extend existingClass , so I'm asking if it's possible to extend jQuery functions. Test Employee 1 Sure... Just save a reference to the existing function, and call it: (function($) { // maintain a reference to the existing function var
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