extend

jquery extend vs angular extend

◇◆丶佛笑我妖孽 提交于 2019-11-28 16:10:45
问题 What is the difference between these two extend functions? angular.extend(a,b); $.extend(a,b); While the jquery.extend is well documented the angular.extend lacks details and the comments there provide no answers. (https://docs.angularjs.org/api/ng/function/angular.extend). Does angular.extend also provide deep copy? 回答1: angular.extend and jQuery.extend are very similar. They both do a shallow property copy from one or more source objects to a destination object. So for instance: var src =

PHP : Does extending class need another 'use' to call namespace?

巧了我就是萌 提交于 2019-11-28 11:55:36
I'm wondering whether in the situation where I'm extending a class that has already 'use' keyword above it to use specific namespace - do I need to add another 'use' above the inheriting class to use the same namespace? Situation like this: namespace Core; use System\Plugin; class Front extends Application { } and now in the Controller, which is called directly without the namespace (using full path): use System\Plugin; class PageController extends Front { } or would it work without 'use' as well and allow me to use the System\Plugin namespace: class PageController extends Front { } ? No, you

Python - Extending a list directly results in None, why?

让人想犯罪 __ 提交于 2019-11-28 10:31:52
问题 x=[1,2,3] x.extend('a') Output: x is [1,2,3,'a'] But when I do the following: [1,2,3].extend('a') Output: None Why does extend work on a list reference, but not on a list? 2nd Part: I found this because I was trying to append a listB to a listA while trying to extend listC to listB. listA.append([listB[15:18].extend(listC[3:12])]) Supposing lists cannot be directly appended / extending. What is the most popular work around form for resolving this issue? 回答1: list.extend modifies the list in

Element.prototype in IE7?

你离开我真会死。 提交于 2019-11-28 10:14:55
I'm trying to extend all dom elements so i can get and remove their children. The function is below (works in FF and Chrome). Is there an equivalent in IE7 to extend the base dom object? if (!Element.get) { Element.prototype.get = function(id) { for (var i = 0; i < this.childNodes.length; i++) { if (this.childNodes[i].id == id) { return this.childNodes[i]; } if (this.childNodes[i].childNodes.length) { var ret = this.childNodes[i].get(id); if (ret != null) { return ret; } } } return null; } } Element.prototype.removeChildren = function() { removeChildren(this); } Thanks! No. There will be some

Default class that is extended by all classes in java

99封情书 提交于 2019-11-28 08:36:48
问题 Is there any Default Class that is extended by all the classes by default in Java? Example: If I have a simple class like: Class A { String a; } Is this class extending a class by default? 回答1: java.lang.Object class is superclass of all classes. Class Object is the root of the class hierarchy. Every class has Object as a superclass. All objects, including arrays, implement the methods of this class. You can test it : A a = new A(); if(a instanceof Object){ System.out.println("Object is

LESS: Extend a previously defined nested selector

谁说我不能喝 提交于 2019-11-28 07:51:45
问题 I've been trying like a mad man to get the following LESS statement to work, but now i am fearing that it's not gonna happen :/ So I am turning now to you guys in the end for help! I have the following statement: .top{ &-first{ background:black; &-item{ color:white; } } &-second{ background:green; &-item:extend(.top-first-item){} } } I was hoping for to achive the following output: .top-first { background: black; } .top-first-item, .top-second-item{ color: white; } .top-second { background:

What's the difference between mixin() and extend() in Javascript libraries

十年热恋 提交于 2019-11-28 06:56:38
I'm looking through various libraries, and seeing extend() pop up a lot, but I'm also seeing mixin() show up. YUI has both mixins and extensions. What's the difference between these two concepts? When would I decide between a mixin and extending an object? Thanks, Matt Mixins don't work with instanceof but extends do. Mixins allow multiple inheritance but by faking it, not by properly chaining the prototypes. I'll show an Ext-JS example but the concept applies to any class library that provides mixins, they all just copy properties to the object instead of chaining the prototype. Ext.define(

Can you extend ArrayList in Java?

这一生的挚爱 提交于 2019-11-28 06:48:28
Is it possible to make a child class that extends ArrayList? If so, how? You can extend any class that is not final in Java. Having said that, you should avoid inheritance if there is no true is-a relationship. Consider composition for reuse. Read about Liskov substitution principle helloworld922 Yes you can. public class MyArrayList<E> extends ArrayList<E> { } However, I'm not sure why you would want to do this. As many other have said, yes, you can extend class ArrayList , but it is not something that you should normally do; it is not considered good practice in Java. I'm mainly a Java

How to add a method to an existing class in PHP?

半世苍凉 提交于 2019-11-28 06:29:18
I'm using WordPress as a CMS, and I want to extend one of its classes without having to inherit from another class; i.e. I simply want to "add" more methods to that class: class A { function do_a() { echo 'a'; } } then: function insert_this_function_into_class_A() { echo 'b'; } (some way of inserting the latter into A class) and: A::insert_this_function_into_class_A(); # b Is this even possible in tenacious PHP? If you only need to access the Public API of the class, you can use a Decorator : class SomeClassDecorator { protected $_instance; public function myMethod() { return strtoupper( $this

Extending or adding new classes at runtime in Java

巧了我就是萌 提交于 2019-11-28 04:28:13
问题 Is there a way to add (or extend existing) classes at runtime in java. I'm stuck on a problem, in which I have to extend an existing class at runtime and add this to the classpath, so that this new class get picked up. thanks, 回答1: There are a number of ways you could do this. Compile source code at runtime using the javax.tools package and then load them using a ClassLoader. If you are writing to interfaces, you can decorate classes with a Proxy. Take the more complicated route of bytecode