expression

问题 I want to have three curves on the same plot with different parameter alpha. curve(sin(x), from = 1, to = 3, lty = 1, ylim = c(-1, 1)) curve(sin(2 * x), add = TRUE, lty = 2) curve(sin(3 * x), add = TRUE, lty = 3) legend("topright", legend = expression(paste(alpha, " = ", c(1, 2, 3))), lty = 1:3) In the legend, I want to have three lines with alplha = 1, alpha = 2, alpha = 3. How do I make it correct? 回答1: The better, looped answer comes from here and user20650. Solution with sapply The

问题 I have this two classes: public class Contratos { //... public int EntidadeFinanceiraId { get; set; } [Column("Nome")] public EntidadesFinanceiras entidadeFinanceira { get; set; } //... } public class EntidadesFinanceiras { [Key] public int ID { get; set; } public string Nome { get; set; } //... } and want to dinamically filter a List of Contratos based on Contratos.entidadeFinanceira.Nome. This is part of a Method that filters the list based on a property selected by the user. public

问题 Most examples deal with the book store example from Stefan Gössner, however I'm struggling to define the correct JsonPath expression for a simple object (no array): { "Id": 1, "Name": "Test" } To check if this json contains Id = 1 . I tried the following expression: $..?[(@.Id == 1]) , but this does find any matches using Json.NET? Also tried Manatee.Json for parsing, and there it seems the jsonpath expression could be like $[?($.Id == 1)] ? 回答1: The path that you posted is not valid. I think

问题 Java spring - I have following cron expression for cron job. 0 0/35 * * * ? But above mentioned cron expression fires once in an hour and like as follows 1:35 2:35 3:35 4:35 I want to fire every after 35 mins instead once in an hour any quick suggestion ? 回答1: Cron syntax is sec min hour day day_of_month month day_of_week year So what you would want is 0 0,35 * * * * ? So it will fire on minutes 0 and 35 of each hour. See the Quartz docs for this, as Spring is using Quartz as scheduler here.

问题 So, for those who have not been involved in my earlier question on this topic, I have some C# types to represent Sequence s, like in math, and I store a formula for generating the nth-term as Func NTerm; Now, I would like to compare one Sequence 's nth-term formula to another for mathematical equality. I have determined that practically, this requires a limitation to five simple binary operators: +,-,/,*,%. With tremendous help from Scott Chamberlain on the OP, I've managed to get here. I'm

问题 quick question. I'd like to remove the sup tag from the following string, and all content within it. $string = "Priority Mail^® International"; How would I do that? 回答1: I imagine something like this would work: preg_replace("(<([a-z]+)>.*?</\\1>)is","",$input); 回答2: $string = preg_replace ("/<sup>(.*?)<\/sup>/i", "", $string); You should know that (.*?) can't deal with \n or \r, so filter them first. 来源： https://stackoverflow.com/questions/10508801/php-preg-expression-to-remove

问题 I am creating a field from tables with our shoretel phone system and i am intergrating reports via SSRS and i need some assisstance with an expression. =if(Fields!ExitReason.Value 7, then if (Fields!ExitReason.Value 1, else if (Fields!ExitReason.Value 0,))) Definition results should be: =if(Fields!ExitReason.Value) = 7 then 1 else 0 I am try to get the field to give me 7, 1 else 0. Any assistance would be great. Thanks, Arron 回答1: You should be able to use IIF(Fields!ExitReason.Value = 7, 1,

问题 I'm currently analyzing the Javascript language a bit. It looks like you could group at lot of the concepts into a base type called expression. Even function arguments and definitions fit into that group, as well as strings, numbers and mathematical expressions. The only illogical exception was the curly bracket object notation in a nonsense alike context. As functions consist of several expressions the following code is valid: function valid(){ /\W/; "ahll"; var alpha; alpha; alpha={"first":

问题 I need to get two fields from a database table (retrieved using linq-to-sql), one field is a datetime (and is a fixed field) and the other is always a decimal, but the field can be different. The table holds currency data which is processed twice a day and in different currencies so could have fields such as AM_USD, PM_USD, AM_EUR etc. And I need to get data such as a list of the date against PM_USD or the date against AM_EUR. I would like to be able to call the data using a lambda expression

问题 I have 2 questions about regex in bash expression. 1.non-greedy mode local temp_input='"a1b", "d" , "45"' if [[ $temp_input =~ \".*?\" ]] then echo ${BASH_REMATCH[0]} fi The result is "a1b", "d" , "45" In java String str = "\"a1b\", \"d\" , \"45\""; Matcher m = Pattern.compile("\".*?\"").matcher(str); while (m.find()) { System.out.println(m.group()); } I can get the result below. "a1b" "d" "45" But how can I use non-greedy mode in bash? I can understand why the \"[^\"] \" works. But I don't