exception

Newtonsoft.Json.JsonReaderException does not recognize left square bracket “[”

家住魔仙堡 提交于 2021-02-17 07:10:10
问题 I'm trying to use DeserializeObject from the NewtonSoft library but I encoutered a problem that bothers me a lot. I'm quite new with that Library so to understand it better I took a look at the following example from the official website. Using that ressource, I modified it to fit my needs, here is my class : public class Project { [JsonProperty ("team")] public string Team{ get; set; } [JsonProperty("details")] public string Details { get; set;} } Here is the code : Project project = new

PyTube: PrivateVideo exception not working

一个人想着一个人 提交于 2021-02-17 05:29:24
问题 I wrote a code that will print all videos' name on the playlist. The problem is when it tries to print the name of the video that is private. I wrote an exception from Github that the owner wrote but it still doesn't work. It should skip this one video and go to another one but it doesn't and the program crashes. Here is my code: import pytube from pytube.exceptions import VideoPrivate pl = pytube.Playlist("https://www.youtube.com/playlist?list=PLB1PGaMZkETOixDfsnKIOkfJS_cToCHSt") for video

How to convert Console.ReadLine() to double in simple calculator ? C# Problem with exception

浪子不回头ぞ 提交于 2021-02-17 05:20:30
问题 I used double.Parse and Convert.ToDouble and got the same error System.FormatException: Input string was not in a correct format. When I write in console 10.2 or any other double number. I learnt from a tutorial and I followed it step by step but I have no idea how to solve this. Also I am using Visual Studio. Console.WriteLine("Enter a number: "); double num1 = double.Parse(Console.ReadLine()); Console.Write("Enter operator: "); string op = Console.ReadLine(); Console.WriteLine("Enter a

How to convert Console.ReadLine() to double in simple calculator ? C# Problem with exception

孤者浪人 提交于 2021-02-17 05:20:08
问题 I used double.Parse and Convert.ToDouble and got the same error System.FormatException: Input string was not in a correct format. When I write in console 10.2 or any other double number. I learnt from a tutorial and I followed it step by step but I have no idea how to solve this. Also I am using Visual Studio. Console.WriteLine("Enter a number: "); double num1 = double.Parse(Console.ReadLine()); Console.Write("Enter operator: "); string op = Console.ReadLine(); Console.WriteLine("Enter a

exception in for loop? [duplicate]

烂漫一生 提交于 2021-02-17 05:15:38
问题 This question already has answers here : EXC_BAD_ACCESS when using strcpy()? (3 answers) Why Can I not modify a string literal in c? (1 answer) Closed 7 months ago . Why my code returns: Exception: EXC_BAD_ACCESS (code=2, address=0x10d637fa2) in the first time it enters the for loops? void unAnnoyWord(char *str) { char *out = str, mostAnnoying = 'a'; do { if (*str != mostAnnoying) { *out = *str; } } while (*str++); } char *str = "hakuna matata"; unAnnoyWord(str); 回答1: Perhaps this is what you

C++ exception return type why char*

我的梦境 提交于 2021-02-16 17:57:22
问题 Could someone explain why self-written C++ exception, that inherit from exception return a char * and not a string? class myexception: public exception { virtual const char* what() const throw() { return "My exception happened"; } } myex; Source : http://www.cplusplus.com/doc/tutorial/exceptions/ 回答1: Since std::exception was designed as a base class for all exceptions, the interface is written in such a way that specializations do not require code that may throw. They may use it, but they do

How to get IO error messages when creating a file in C++?

走远了吗. 提交于 2021-02-16 14:26:08
问题 One of the ancient anti-pattern is people checking error status and then returning fairly useless messages like "operation failed" instead of "operation failed because ...". I want C++ file I/O operations to fail with exception and get the error message on why it failed. Specifically I want ofstream object to raise exception when file creation fails and get bit more useful message such as "permission denied" or "No file or path". This is trivial to do in languages such as C# or Java or Python

Unhandled IOException Inside Java List.stream.forEach Lambda Expression

谁都会走 提交于 2021-02-16 09:10:17
问题 I am using the Stream API introduced in Java 8 to run a method for each string in a list. public boolean initFile() throws IOException { if (this.outFile.exists()) { this.outFile.delete(); } return this.outFile.createNewFile(); } public void writeStringToFile(String str, boolean addNewLine) throws IOException { if (this.mode != FileMode.READ) { if (this.initFile()) { FileWriter fileWriter; if (this.mode == FileMode.APPEND) fileWriter = new FileWriter(outFile.getAbsolutePath(), true); else

Unhandled IOException Inside Java List.stream.forEach Lambda Expression

回眸只為那壹抹淺笑 提交于 2021-02-16 09:01:20
问题 I am using the Stream API introduced in Java 8 to run a method for each string in a list. public boolean initFile() throws IOException { if (this.outFile.exists()) { this.outFile.delete(); } return this.outFile.createNewFile(); } public void writeStringToFile(String str, boolean addNewLine) throws IOException { if (this.mode != FileMode.READ) { if (this.initFile()) { FileWriter fileWriter; if (this.mode == FileMode.APPEND) fileWriter = new FileWriter(outFile.getAbsolutePath(), true); else

Asyncio: Weirdness of Task exception was never retrieved

杀马特。学长 韩版系。学妹 提交于 2021-02-15 03:51:36
问题 Lets assume I have a simple code: import asyncio async def exc(): print(1 / 0) loop = asyncio.get_event_loop() loop.create_task(exc()) try: loop.run_forever() except KeyboardInterrupt: loop.stop() loop.close() If I run it, I get error message immediately Task exception was never retrieved future: <Task finished coro=<exc() done, defined at qq.py:4> exception=ZeroDivisionError('division by zero',)> Traceback (most recent call last): File "qq.py", line 5, in exc print(1 / 0) ZeroDivisionError: