escaping

Jinja2 automatically escapes all HTML tags, but I want to not escape some tags (like img , b , and some others). How can I do it? Alex Morega You can write your own filter. The scrubber library is pretty good at cleaning up HTML. The filter will need to wrap the returned string in jinja2.Markup so the template will not re-escape it. Edit: a code example import jinja2 import scrubber def sanitize_html(text): return jinja2.Markup(scrubber.Scrubber().scrub(text)) jinja_env.filters['sanitize_html'] = sanitize_html Sean Vieira You'll want to parse the input on submission using a white list approach

This question already has an answer here: How to escape single quotes within single quoted strings 21 answers I am trying to take this one step further. How could this work in a standard Bash shell? git commit -m 'cracked enigma's code' Could this simply be done with backslash-escaping like the following? git commit -m 'cracked enigma\'s code' Further, how could double-quotes be used? Also by backslash-escaping? Would that be the best way? Are there any good alternative ways? git commit -m 'cracked the "real" enigma's code' Use double quotes: git commit -m "cracked enigma's code" Or, if your

Ok I am running a public JSONP API which the data is served from my PHP server. I just read this article: JSON: The JavaScript subset that isn't (by Magnus Holm; May 2011) (please read for clarification) Basically if my JSON strings contains a U+2028 character (Unicode line separator) or U+2029 character (Unicode paragraph separator) then this is perfectly valid JSON. However when using JSONP the JSON gets executed as JavaScript and no string in JavaScript can contain a literal U+2028 or a U+2029 as it will break the JavaScript. Apparently this is usually not a problem as long as you use a

My bash-script looks as following: echo "Description:" while [ $finishInput -eq 0 ]; do read tmp desc="$desc"$'\n'"$tmp" if [ -z "$tmp" ]; then finishInput="1" fi done echo -n "Maintainer:" read maintainer It reads to the desc var until a empty line is passed. After that, i want to read in other stuff. When executing my current script it looks like this: Description: Line 1 Line 2 Maintainer: I would like to overwrite the last empty line with the "Maintainer:". I searched for a solution but only found suggestions which were like echo -n "Old line" echo -e "\r new line" which stays on the line

This question already has an answer here: Trying to escape a / for sed on ubuntu 4 answers I'm attempting to use SED through OS X Terminal to perform a find and replace. Imagine I have this string littered throughout the text file: http://www.find.com/page And I want to replace it with this string: http://www.replace.com/page I'm having trouble because I'm not sure how to properly escape or use the "/" character in my strings. For example if I simply wanted to find "cat" and replace with "dog" I've found the following command that works perfectly: sed -i '' 's/cat/dog/g' file.txt Does anyone

I seem to be having issues. I have a query string that has values that can contain single quotes. This will break the query string. So I was trying to do a replace to change ' to \' . Here is a sample code: "This is' it".replace("'", "\'"); The output for this is still: "This is' it". It thinks I am just doing an escape character for the quote. So I tried these two pieces of code: "This is' it".replace("'", "\\'"); // \\ for the backslash, and a ' char "This is' it".replace("'", "\\\'"); // \\ for the backslash, and \' for the ' char Both of the above STILL results in the same output: "This is