endianness

问题 How can I figure out whether it's a big-endian or little-endian file? I just tried to write a big-endian file with matlab but probably it didn't work. Now I want to learn if it is possible to learn what type it is. Any suggestion? 回答1: Use FOPEN: fileID = fopen(fileName) [filename, permission, machineformat] = fopen(fileID) The third output, machineformat , tells you whether it's big endian ( 'b' ) or little endian ( 'l' ). 回答2: There's no way in general to know whether a given data file was

问题 I'm not realizing what is wrong with my code, take a look: C# code: const int MOVE = 112; MemoryStream m = new MemoryStream(); m.SetLength(4 + 1 + (1 + 1 + 1 + 1)); BinaryWriter bw = new BinaryWriter(m); int id_ = getId(); bw.Write(Converter.GetBigEndian(id_)); sbyte eventMove = MOVE; sbyte rowFromByte = 4; sbyte colFromByte = 2; sbyte rowToByte = 1; sbyte colToByte = 3; bw.Write(eventMove); bw.Write(rowFromByte); bw.Write(colFromByte); bw.Write(rowToByte); bw.Write(colToByte); When I read on

问题 I heard in little endian, the LSB is at starting address and in Big endian MSB is at starting address. SO I wrote my code like this. If not why ? void checkEndianess() { int i = 1; char c = (char)i; if(c) cout<<"Little Endian"<<endl; else cout<<"Big Endian"<<endl; } 回答1: No, you're taking an int and are casting it to a char, which is a high-level concept (and will internally most likely be done in registers). That has nothing to do with endianness, which is a concept that mostly pertains to

问题 I currently have a Java ByteBuffer that already has the data in Big Endian format. I then want to write to a binary file as Little Endian. Here's the code which just writes the file still in Big Endian: public void writeBinFile(String fileName, boolean append) throws FileNotFoundException, IOException { FileOutputStream outStream = null; try { outStream = new FileOutputStream(fileName, append); FileChannel out = outStream.getChannel(); byteBuff.position(byteBuff.capacity()); byteBuff.flip();

问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 6 years ago . I'm having some trouble in iOS. I have been trying to convert a base10 decimal value into a little endian , hexadecimal string. So far I am unable to do so. For example I would like to convert the following

问题 I've seen by using gdb that when bytes are copied from memory into registers they are reversed, if the system in use adopts the little endian approach. Since, at the best of my knowledgs, the x86 assembly instruction set does not allow operations whose operands are both in memory, I was wondering: is there any operation which is performed directly on little endian values without being reversed first? 回答1: This answer may appear a little bit strange to the experienced folks, but what the

问题 I am working with a device that supports little endian byte order. How do I do this in Java? I have created a byte stream from the hex data and wrote it to the socket output stream. I am supposed to send data in the following format. Protocol-Version: 0x0001 Request_Code: 0x0011 Request_Size: 0x00000008 String s = "0001001100000008"; byte[] bytes = hexStringToByteArray(s); socket.getOutputStream().write(bytes); public static byte[] hexStringToByteArray(String s) { int len = s.length(); byte[]

问题 I have found the following function from MSDN which converts an unsigned long from network byte to unsigned long in host byte order i.e. in little-endian defined as: u_long WSAAPI ntohl( _In_ u_long netlong ); The MSDN document says that it can convert a 32 bits number. But since in C++ as I have read that long and int are not the same i.e. long is not guaranteed to be 32 bits or the same size of an integer INT_MAX . So, I wonder if there is a a similar function which takes a 32 bits values

问题 Kindly clarify my doubt as i got so confused with the below stuff and i couldnt get a clean anwser any where else on net. #include<stdio.h> int main() { int a = 0x44332211; printf("Network - 0x%x\n", htonl(a));// Host to network printf("Host - 0x%x\n", ntohl(a));// Network to host return 0; } Output: Network - 0x11223344 Host - 0x11223344 Here htonl(0x44332211) => i am converting little endian(LE) to BE. So output will be 0x11223344 . That i understood. My problem is with ntoh() . Now ntohl

问题 I have a python bluetooth server (using PyBluez) running on a raspberry pi. The uuid I use in the server is: 8f86d132-4ab8-4c15-b8df-0b70cf10ea56 I am calling device.fetchUuidsWithSdp() on the bluetooth server in my Android app. When it eventually fetches the uuids, they have been reversed in groups of two (it seems the endianness has changed). In the broadcast receiver: Parcelable[] uuids = intent.getParcelableArrayExtra(BluetoothDevice.EXTRA_UUID); if (uuids != null) { if (uuids.length > 0)