encryption

问题 I have an OpenPGP encrypted file and its private key in a text file and know its passphrase. I tried this below code: import pgpy emsg = pgpy.PGPMessage.from_file('PGPEcrypted.txt') key,_ = pgpy.PGPKey.from_file('PrivateKey.txt') with key.unlock('passcode!'): print (key.decrypt(emsg).message) But while trying to execute I am getting following error: Traceback (most recent call last): File "D:\Project\PGP\pgp_test.py", line 4, in <module> key,_ = pgpy.PGPKey.from_file('SyngentaPrivateKey.txt')

问题 I have an OpenPGP encrypted file and its private key in a text file and know its passphrase. I tried this below code: import pgpy emsg = pgpy.PGPMessage.from_file('PGPEcrypted.txt') key,_ = pgpy.PGPKey.from_file('PrivateKey.txt') with key.unlock('passcode!'): print (key.decrypt(emsg).message) But while trying to execute I am getting following error: Traceback (most recent call last): File "D:\Project\PGP\pgp_test.py", line 4, in <module> key,_ = pgpy.PGPKey.from_file('SyngentaPrivateKey.txt')

问题 I am using Crypt:: for registration and login. My registration is successful but login is not successful. Please check the code and help me. public function Login(Request $request) { $this->validate($request, [ 'email' => 'required', 'password' => 'required', ]); $userdata = array( 'email' => $request->email, 'password' => \Crypt::encrypt($request->password) ); if (Auth::attempt($userdata) { echo "success";die(); } return "Ops! snap! seems like you provide an invalid login credentials"; } 回答1

问题 I have 2 specific questions about Amazon EBS Encryption. What is the benefit of using encrypted EBS? If create encrypted EBS and attached to the instance, will i able to read the data if i login using ssh? Appreciate if you could explain in brief. Thanks and Regards, Vady 回答1: AWS employees with direct access to the underlying hardware cannot view your data. That's really the only advantage. You might have to do this for meeting security compliance requirements such as PCI or HIPAA. If not,

问题 Innocently， I thought "SHA1withRSA algorithm" was simply operating the plainText with "SHA1", and use RSA/pkcs1padding to encrypt the result of "SHA1"。However, I found I was wrong until I wrote some java code to test what I thought. I use RSA publickey to decrypt the signature which I use the corresponding privatekey to sign with "SHA1withRSA algorithm" . But I found the result is not equal to "SHA1(plainText)", below is my java code: String plaintext= "123456"; Signature signature=Signature

问题 I am using AES 256 cbc method to encrypt my files. The column which I am encrypting is called 'Name'. previously before encrypting I had set the varchar length in phpmyadmin for 'Name' to be 20. when I was trying to encrypt , I saw it was short and the entire encrypted string was not getting inserted in the database. So I changed the size of varchar to 50 but still the length is small. I have to do this for other column as well. How do I determine efficient length for 'Name' column. I am

问题 I want to encrypt data in an image but the resulting ciphertext to still be a valid image. I encrypt the image with AES in python and then, I replace header in the files, but windows can't open the encrypted image. Code def encrypt_file(self, in_filename, out_filename): filesize = os.path.getsize(in_filename) iv = Random.new().read(AES.block_size) cipher = AES.new(self.key, AES.MODE_ECB, iv) chunksize = 64 * 1024 with open(in_filename, 'rb') as infile: with open(out_filename, 'wb') as outfile

问题 Using the variables alpha and key, encrypt ptext into a variable named ctext. Using substitution cipher So I have a text file separated in a vector ptext <- strsplit(ptext,split = "", fixed = TRUE) ptext <- unlist(ptext) I also created a key for this cipher key <- "ZGYHXIWJVKULTMSARBQCPDOENF" key <- unlist(strsplit(key,"")) and an Alphabet vector for the key alpha <- "ABCDEFGHIJKLMNOPQRSTUVWXYZ" alpha <= toupper(alpha) alpha <- unlist(strsplit(alpha,"")) Now my goal is to try to replace all

问题 I'm looking at an C# AES asymmetric encryption and decryption example here and not sure if i should store the IV in a safe place (also encrypted??). Or i can just attach it to the encrypted text for using later when i with to decrypt. From a short reading about AES it seems it's not needed at all for decryption but i'm not sure i got it right and also the aes.CreateDecryptor(keyBytes, iv) need it as parameter. I use a single key for all encryptions. 回答1: It's fairly standard to transmit the

问题 I created this program but I'm getting errors on CS50 showing that I didn't do any of it correctly. The requirements are as follows: Implement your program in a file called caesar.c in a directory called caesar. Your program must accept a single command-line argument, a non-negative integer. Let’s call it k for the sake of discussion. If your program is executed without any command-line arguments or with more than one command-line argument, your program should print an error message of your