ecmascript-6

问题 Template literals make string manipulation much easier. However: What can and what can't they do in comparison to template libraries such as mustache and handlebars? I found it difficult to find an answer to these questions: Can they handle conditions? Can they handle loops? Can they handle functions? 回答1: The name is a bit ambiguous, but template literals do not replace template engines. They role is only to provide a more convenient syntax to work with strings. In fact, the objective was to

问题 I am simply trying to simulate a small click and drag on a draggable div elem — I've found several similar questions here on SO but all involving the use of additional plugins... Is there a plain JavaScript or jQuery ability to handle specifically the drag? as I know .click(); or mouse down can be called to initiate. I am not trying to create the ability of a drag and drop, I already have that. I am trying to create a small function that simulates this event automatically. click > hold > drag

问题 In the React documentation for hooks they say: "This also allows you to handle out-of-order responses with a local variable inside the effect" useEffect(() => { let ignore = false; async function fetchProduct() { const response = await fetch('http://myapi/product/' + productId); const json = await response.json(); if (!ignore) setProduct(json); } fetchProduct(); return () => { ignore = true }; }, [productId]); Demo app Please help me understand this better by explaining: Why is the return a

问题 In the React documentation for hooks they say: "This also allows you to handle out-of-order responses with a local variable inside the effect" useEffect(() => { let ignore = false; async function fetchProduct() { const response = await fetch('http://myapi/product/' + productId); const json = await response.json(); if (!ignore) setProduct(json); } fetchProduct(); return () => { ignore = true }; }, [productId]); Demo app Please help me understand this better by explaining: Why is the return a

问题 In the React documentation for hooks they say: "This also allows you to handle out-of-order responses with a local variable inside the effect" useEffect(() => { let ignore = false; async function fetchProduct() { const response = await fetch('http://myapi/product/' + productId); const json = await response.json(); if (!ignore) setProduct(json); } fetchProduct(); return () => { ignore = true }; }, [productId]); Demo app Please help me understand this better by explaining: Why is the return a

问题 In the React documentation for hooks they say: "This also allows you to handle out-of-order responses with a local variable inside the effect" useEffect(() => { let ignore = false; async function fetchProduct() { const response = await fetch('http://myapi/product/' + productId); const json = await response.json(); if (!ignore) setProduct(json); } fetchProduct(); return () => { ignore = true }; }, [productId]); Demo app Please help me understand this better by explaining: Why is the return a

问题 I'm not looking for an opinion - just a solid migration strategy. We started to design a new project that designated to be built with Angular as each of our previous, the importance of this project is very high and it's going to live and maintained for at least 3-4 years. Angular 2.0 is coming in the end of 2015 and it seems like everything is about to change, $scope is out, directives are out and the whole DI concept is about to change. Is there a migration path/strategy to be considered in

问题 In es6, how can i simplify the following lines using destructuring?: const array0 = someArray[0].data; const array1 = someArray[1].data; const array2 = someArray[2].data; 回答1: Whether using destructuring would actually be a simplification is debatable but this is how it can be done: const [ { data: array0 }, { data: array1 }, { data: array2 } ] = someArray Live Example: const someArray = [ { data: 1 }, { data: 2 }, { data: 3 } ]; const [ { data: array0 }, { data: array1 }, { data: array2 } ]

问题 In es6, how can i simplify the following lines using destructuring?: const array0 = someArray[0].data; const array1 = someArray[1].data; const array2 = someArray[2].data; 回答1: Whether using destructuring would actually be a simplification is debatable but this is how it can be done: const [ { data: array0 }, { data: array1 }, { data: array2 } ] = someArray Live Example: const someArray = [ { data: 1 }, { data: 2 }, { data: 3 } ]; const [ { data: array0 }, { data: array1 }, { data: array2 } ]

问题 In es6, how can i simplify the following lines using destructuring?: const array0 = someArray[0].data; const array1 = someArray[1].data; const array2 = someArray[2].data; 回答1: Whether using destructuring would actually be a simplification is debatable but this is how it can be done: const [ { data: array0 }, { data: array1 }, { data: array2 } ] = someArray Live Example: const someArray = [ { data: 1 }, { data: 2 }, { data: 3 } ]; const [ { data: array0 }, { data: array1 }, { data: array2 } ]