dynamic-memory-allocation

There are a few options for acquiring an aligned block of memory but they're very similar and the issue mostly boils down to what language standard and platforms you're targeting. C11 void * aligned_alloc (size_t alignment, size_t size) POSIX int posix_memalign (void **memptr, size_t alignment, size_t size) Windows void * _aligned_malloc(size_t size, size_t alignment); And of course it's also always an option to align by hand. Intel offers another option. Intel void* _mm_malloc (int size, int align) void _mm_free (void *p) Based on source code released by Intel, this seems to be the method of

Can someone give a clear explanation of how the new and delete keywords would behave if called from __device__ or __global__ code in CUDA 4.2? Where does the memory get allocated, if its on the device is it local or global? It terms of context of the problem I am trying to create neural networks on the GPU, I want a linked representation (Like a linked list, but each neuron stores a linked list of connections that hold weights, and pointers to the other neurons), I know I could allocate using cudaMalloc before the kernel launch but I want the kernel to control how and when the networks are

I'm implementing combsort . I'd like to create fixed-size array on the stack, but it shows stack overflow . When I change it to be on the heap (Rust by Example says to allocate in the heap we must use Box ), it still shows stack overflow . fn new_gap(gap: usize) -> usize { let ngap = ((gap as f64) / 1.3) as usize; if ngap == 9 || ngap == 10 { return 11; } if ngap < 1 { return 1; } return ngap; } fn comb_sort(a: &mut Box<[f64]>) { // previously: [f64] let xlen = a.len(); let mut gap = xlen; let mut swapped: bool; let mut temp: f64; loop { swapped = false; gap = new_gap(gap); for i in 0..(xlen -

I am new to MPI. I wrote a simple code to display a matrix using multiple process. Say if I have a matrix of 8x8 and launching the MPI program with 4 processes, the 1st 2 rows will be printed my 1st process the 2nd set of 2 rows will be printed by 2nd thread so on by dividing itself equally. #define S 8 MPI_Status status; int main(int argc, char *argv[]) { int numtasks, taskid; int i, j, k = 0; MPI_Init(&argc, &argv); MPI_Comm_rank(MPI_COMM_WORLD, &taskid); MPI_Comm_size(MPI_COMM_WORLD, &numtasks); int rows, offset, remainPart, orginalRows, height, width; int **a; // int a[S][S]; if(taskid ==

Well, I can't understand when and why it is needed to allocate memory using malloc . Here is my code : #include <stdlib.h> int main(int argc, const char *argv[]) { typedef struct { char *name; char *sex; int age; } student; //Now I can do two things student p; //or student *ptr = (student *)malloc(sizeof(student)); return 0; } Why is it needed to allocate memory when I can just use student p; ? taskinoor malloc is used for dynamic memory allocation. As said, it is dynamic allocation which means you allocate the memory at run time. For example when you don't know the amount of memory during