dynamic-arrays

My project requires a bunch of dynamically-resizable arrays for different objects. An array may hold any number of objects, potentially thousands, of a single class, but not objects of multiple classes. Mostly I will be iterating through arrays, thus use of a keyed collection is not ideal. I think I have two options: The first option is to develop a 'List' class for each object type, with methods for adding objects (and expanding the array), getting the First and Last indexes and the object count, and retrieving an object by index (the latter 4 will include error handling in case the array is

I'm new to C/C++ and I've been cracking my head but still got no idea how to make an "structure" like this It's supposed to be a 3D dynamic array using pointers. I started like this, but got stuck there int x=5,y=4,z=3; int ***sec=new int **[x]; It would be enough to know how to make it for a static size of y and z; Please, I'd appreciate that you help me. Thanks in advance. Manish Shukla To create dynamically 3D array of integers, it's better you understand 1D and 2D array first. 1D array : You can do this very easily by const int MAX_SIZE=128; int *arr1D = new int[MAX_SIZE]; Here, we are

I am currently writing a program to implement an arraylist (or dynamic array) in C. Hmm... I think I have 70 - 80% done with it, however, I found a serious problem with my code when testing them on a couple of machines. Briefly, I inserted a group of strings( char* ) into my arraylist, and tried to get and display them after couples of operations. However, this is what I got: CHECK: 1 CHECK: 2 CHECK: ܗ¿èۗ¿ CHECK: EàEàHAÿE؉Ⱥ CHECK: 5 CHECK: 6 Unfortunately, I still cannot figure out where the problem is in my codes, even though I have reviewed my codes twice. arraylist.h #ifndef _ARRAYLIST_H

Draft C++14 includes both runtime-sized arrays and the std::dynarray container. From what I can tell, the only real difference between the two is that std::dynarray has an STL interface (e.g., begin , end , size , etc.), while runtime-sized arrays do not. So why does C++14 need them both? I understand that runtime-sized arrays are part of the core language, while std::dynarray is part of the standard library, but the proposal for std::dynarray makes clear that the authors expect compilers, in many cases, to offer special support for std::dynarray so that it can be as efficient as possible, i.e

I know that there is no way in C++ to obtain the size of a dynamically created array, such as: int* a; a = new int[n]; What I would like to know is: Why? Did people just forget this in the specification of C++, or is there a technical reason for this? Isn't the information stored somewhere? After all, the command delete[] a; seems to know how much memory it has to release, so it seems to me that delete[] has some way of knowing the size of a . You will often find that memory managers will only allocate space in a certain multiple, 64 bytes for example. So, you may ask for new int[4], i.e. 16

This is sample code my teacher showed us about "How to dynamically allocate an array in C?". But I don't fully understand this. Here is the code: int k; int** test; printf("Enter a value for k: "); scanf("%d", &k); test = (int **)malloc(k * sizeof(int*)); for (i = 0; i < k; i++) { test[i] = (int*)malloc(k * sizeof(int)); //Initialize all the values } I thought in C, to define an array you had to put the [] after the name, so what exactly is int** test ; isn't it just a pointer to a pointer? And the malloc() line is also really confusing me..... Grijesh Chauhan According to declaration int**

I basically want a python equivalent of this in C: int a[x]; but in python I declare an array like: a = [] and the problem is I want to assign random slots with values like: a[4] = 1 but I can't do that with python, since the array is empty. If by "array" you actually mean a Python list, you can use a = [0] * 10 or a = [None] * 10 You can't do exactly what you want in Python (if I read you correctly). You need to put values in for each element of the list (or as you called it, array). But, try this: a = [0 for x in range(N)] # N = size of list you want a[i] = 5 # as long as i < N, you're okay