dynamic-allocation

Is there any existing way to emulate growing array in Fortran? Like vector in C++. I was very surprised when I haven't found anything on this subject on the Internet. As a motivation example, suppose I compute some recurrence relation and I want to store all the intermediate numbers I get. My stopping criterion is the difference between adjacent results so I cannot know beforehand how much memory I should allocate for this. I am sure it has been shown somewhere on this site before, but I cannot find it. First, in Fortran 2003, you can add one element by simple a = [a, item] as commented by

This is such a simple pattern, there has to be a "nice" way of sorting it out. I have a function that needs to generate a dynamically sized byte array containing arithmetic data. // Given that I have a function that kinda looks like this: void dispatch(std::vector<char> data); //Will take possesion of data. // The behavior I want, but this breaks strict aliasing void bad_foo(int c) { std::vector<char> real_data(c * sizeof(float)); float* raw_data = reinterpret_cast<float*>(real_data.data()); //Fill raw_data with usefull stuff... dispatch(std::move(real_data)); } void correct_but_slow_foo(int c

So this may seem like a widely-answered question, but I'm interested more in the internals of what exactly happens differently between the two. Other than the fact that the second example creates not only the memory, but a pointer to the memory , what happens in memory when the following happens: char a[5]; char b* = new char[5]; And more directly related to why I asked this question, how come I can do const int len = 5; char* c = new char[len]; but not const int len = 5; char d[len]; // Compiler error EDIT Should have mentioned I'm getting this compiler error on VC++ (go figure...) 1>.\input

This question already has an answer here: error: function returns address of local variable 7 answers #include <string.h> #include<stdio.h> #include<stdlib.h> char *chktype(char *Buffer, int Size) { char *strng = "Content-Type: "; int sz; char *found = strstr (Buffer, strng); char *found1 = strstr(found, "\r\n"); sz=strlen(found)-strlen(found1); char type[sz]; strncpy(type, found1, sz-1); return(type); } void main(){ char *buffer = "HTTP/1.1 200 OK\r\nDate: Tue, 25 Jun 2013 16:27:16 GMT\r\nExpires: -1\r\nCache-Control: private, max-age=0\r\nContent-Type: text/html; charset=UTF-8\r\nContent