duplicates

How to detect duplicate words from a String in Java?

我的梦境 提交于 2019-11-28 02:23:11
问题 What are the ways by which duplicate word in a String can be detected? e.g. "this is a test message for duplicate test" contains one duplicate word test. Here, the objective is to detect all duplicate words which occur in a String. Use of regular expression is preferable to achieve the goal. 回答1: The best you can do with regexes is O(N^2) search complexity. You can easily achieve O(N) time and space search complexity by splitting the input into words and using a HashSet to detect duplicates.

Remove duplicate and original from list - python

时光总嘲笑我的痴心妄想 提交于 2019-11-28 02:15:26
given a list of string (i am not aware of list), i want to remove the duplicate and original word. for example: lst = ['a', 'b', 'c', 'c', 'c', 'd', 'e', 'e'] the output should should remove the duplicates so something like this ['a', 'b', 'd'] I do not need to preserve the order. Use a collections.Counter() object , then keep only those values with a count of 1: from collections import counter [k for k, v in Counter(lst).items() if v == 1] This is a O(N) algorithm; you just need to loop through the list of N items once, then a second loop over fewer items (< N) to extract those values that

row not consolidating duplicates in R when using multiple months in Date Filter

谁都会走 提交于 2019-11-28 02:03:19
I am using the following code to summarize my data by a column library(data.table, warn.conflicts = FALSE) library(lubridate, warn.conflicts = FALSE) ################ ## PARAMETERS ## ################ # Set path of major source folder for raw transaction data in_directory <- "C:/Users/NAME/Documents/Raw Data/" # List names of sub-folders (currently grouped by first two characters of CUST_ID) in_subfolders <- list("AA-CA", "CB-HZ") # Set location for output out_directory <- "C:/Users/NAME/Documents/YTD Master/" out_filename <- "OUTPUT.csv" # Set beginning and end of date range to be collected -

R finding duplicates in one column and collapsing in a second column

試著忘記壹切 提交于 2019-11-28 01:58:05
问题 I have a data frame with two columns contacting character strings. in one column (named probes ) I have duplicated cases (that is, several cases with the same character string). for each case in probes I want to find all the cases containing the same string, and then merge the values of all the corresponding cases in the second column (named genes ) into a single case. for example, if I have this structure: probes genes 1 cg00050873 TSPY4 2 cg00061679 DAZ1 3 cg00061679 DAZ4 4 cg00061679 DAZ4

Detect duplicate values in primitive Java array

馋奶兔 提交于 2019-11-28 01:49:14
问题 I want to detect duplicate values in a Java array. For example: int[] array = { 3, 3, 3, 1, 5, 8, 11, 4, 5 }; How could I get the specific duplicated entry and how many times it occurs? 回答1: I'll have a Map<Integer, Integer> where the first integer is the value of the number that occurs in the array and the second integer is the count (number of occurrence). Run through the array.length in a loop for each item in the array, do a map.containsKey(array[i]) . If there exists a number in a map,

Remove duplicate values from an array of objects in javascript

五迷三道 提交于 2019-11-28 01:46:45
i have an array of objects like this: arr = [ {label: Alex, value: Ninja}, {label: Bill, value: Op}, {label: Cill, value: iopop} ] This array is composed when my react component is rendered. The i user Array.prototype.unshift for adding a desired element in the top of my array. So i write arr.unshift({label: All, value: All}) . When my component first rendered my array is successfully created as i desire. But when i rerender it it shows me the array with the value {label: All, value: All} as duplicate. To be more specific it is shown something like this: arr = [ {label: All, value: All},

How do I remove consecutive duplicates from a list?

拜拜、爱过 提交于 2019-11-28 01:15:38
问题 How do I remove consecutive duplicates from a list like this in python? lst = [1,2,2,4,4,4,4,1,3,3,3,5,5,5,5,5] Having a unique list or set wouldn't solve the problem as there are some repeated values like 1,...,1 in the previous list. I want the result to be like this: newlst = [1,2,4,1,3,5] Would you also please consider the case when I have a list like this [4, 4, 4, 4, 2, 2, 3, 3, 3, 3, 3, 3] and I want the result to be [4,2,3,3] rather than [4,2,3] . 回答1: itertools.groupby() is your

Removing redundant line breaks with regular expressions

廉价感情. 提交于 2019-11-28 00:53:57
I'm developing a single serving site in PHP that simply displays messages that are posted by visitors (ideally surrounding the topic of the website). Anyone can post up to three messages an hour. Since the website will only be one page, I'd like to control the vertical length of each message. However, I do want to at least partially preserve line breaks in the original message. A compromise would be to allow for two line breaks, but if there are more than two, then replace them with a total of two line breaks in a row. Stack Overflow implements this. For example: "Porcupines\nare\n\n\n

pandas: drop duplicates in groupby 'date'

风流意气都作罢 提交于 2019-11-28 00:43:51
问题 In the dataframe below, I would like to eliminate the duplicate cid values so the output from df.groupby('date').cid.size() matches the output from df.groupby('date').cid.nunique() . I have looked at this post but it does not seem to have a solid solution to the problem. df = pd.read_csv('https://raw.githubusercontent.com/108michael/ms_thesis/master/crsp.dime.mpl.df') df.groupby('date').cid.size() date 2005 7 2006 237 2007 3610 2008 1318 2009 2664 2010 997 2011 6390 2012 2904 2013 7875 2014

Finding unique combinations irrespective of position [duplicate]

做~自己de王妃 提交于 2019-11-28 00:39:30
问题 This question already has an answer here: pair-wise duplicate removal from dataframe [duplicate] 4 answers I'm sure it's something simple, but I have a data frame df <- data.frame(a = c(1, 2, 3), b = c(2, 3, 1), c = c(3, 1, 4)) And I want a new data frame that contains the unique combinations of values in the rows, irrespective of which column they're in. So in the case above I'd want a b c 1 2 3 3 1 4 I've tried unique(df[c('a', 'b', 'c')]) but it sees (1, 2, 3) as unique from (2, 3, 1),