double

问题 i want to do some thing like instagram app when user double tab on photo it make like and while he just tab one time it open as full screen 回答1: I think this answers to Your question as well. Check this link: how to implement double click in android 回答2: If you don't need to prevent single click to be fired, you can do much more simple: @Override public void onItemClick(AdapterView<?> adapterView, View view, int position, long l) { long currTime = System.currentTimeMillis(); if (currTime -

问题 Is there any reason the fallowing code would give A compile error ? Import java.util.*; public class Storageclass // class used to store the Student data { // creates the private array list needed. private ArrayList<String> nameList = new ArrayList<String>(); private ArrayList<double> GPAList = new ArrayList<double>(); private ArrayList<double> passedList = new ArrayList<double>(); } this is in a class access by a main file there is more in the class by it not part of this error. when I run

问题 double d=1/0.0; System.out.println(d); It prints Infinity , but if we will write double d=1/0; and print it we'll get this exception: Exception in thread "main" java.lang.ArithmeticException: / by zero at D.main(D.java:3) Why does Java know in one case that diving by zero is infinity but for the int 0 it is not defined? In both cases d is double and in both cases the result is infinity. 回答1: Floating point data types have a special value reserved to represent infinity, integer values do not.

问题 I ve got a function that takes 3 parameteres, first one is **double. normalizeDataZeroMeanUnitSD(double ** trainingActions, int numberOfTrainingActions, int descriptorDimension) When I call it from main, I am trying to use normalizeDataZeroMeanUnitSD(data, 681, 24); however, I am receiving cannot convert parameter 1 from 'double [681][24]' to 'double **' This is how I construct the data array: fstream infile; infile.open("gabor\\Data.txt"); double data[681][24]; while (!infile.eof()) { for

问题 #include<stdio.h> main() { float x=2; float y=4; printf("\n%d\n%f",x/y,x/y); printf("\n%f\n%d",x/y,x/y); } Output: 0 0.000000 0.500000 0 compiled with gcc 4.4.3 The program exited with error code 12 回答1: As noted in other answers, this is because of the mismatch between the format string and the type of the argument. I'll guess that you're using x86 here (based on the observed results). The arguments are passed on the stack, and x/y , although of type float , will be passed as a double to a

问题 So its been a while since I took courses on c and c++ and I'm curious on c pointers (im going to use the new keyword in my examples even thought I know malloc is the C way). I always recall my teacher always forcing us to use pointer, she would never take assignments with arrays, she proved to us that there are less commands needed in assembly language when you used pointers rather then used arrays. I want to continue this good practice but I seem to be struggling to use pointers,

问题 Sorry if this is a noob question :( . Piece of C code. int array[5]; int cnt; for(cnt = 0; cnt <= 10; cnt+=1) { array[cnt] = cnt; } Should give an error, right? No! Works fine! But why is that? It seems that -in the first line- an array of more than the double size (11) is defined. You can even access array[5 to 10] later on. And that is confusing me. It stops working when you define array[4 or less] ... Thanks in advance. 回答1: It may happen to work with your particular compiler and computer,

问题 I am trying to get user input, parse it and then display with String.Format(), formatting thousands with comas. So, if user provides 1000 I will display 1,000 1000.00 => 1,000.00 1000.0 => 1,000.0 1,000.5 => 1,000.5 Basically I want to keep all decimals(including trailing zeroes) that were provided and just add formatting for thousands. I tried: String.Format("{0:#,0.######}" , Decimal.Parse(input)); String.Format("{0:#,0.######}" , Double.Parse(input); 回答1: double.Parse(input) is a no go, as

问题 I have a database where one of the tables stores a blob ( bytea ) of all kinds of generic data collected from another system. The bytea field can have anything in it. In order to know how to interpret the data, the table also has a format field. I wrote a Java application to read the bytea field from the database as a byte[] and then I can easily convert it to double[] or int[] or whatever the format field says by using ByteBuffer and the various views ( DoubleBuffer , IntBuffer , etc.). Now

问题 Hello i have a problem with c# Arrays. I need a array to store some data in there... My Code is that double[] ATmittelMin; ATmittelMin[zaehlMittel] = Gradient(x, xATmax, y, yATmax); But the compiler says: not defined var How can i define a double array without a fixed size ? Thanks a lot! 回答1: Arrays are always fixed in size, and have to be defined like so: double[] items1 = new double[10]; // This means array is double[3] and cannot be changed without redefining it. double[] items2 = {1.23,