double

问题 I am having an unexpected problem passing var's through Segue to a VC. Worked fine in Objective C and early version of Swift. Here is what I am doing: I'm extracting a set of variables from a downloaded json file to populate a TableViewCell, then to pass the Cell displayed variables plus the other vars relating to that Cell selection to a DetailViewController. This is through prepare for Segue, setting up vars on the DetialViewController. Then destination.myVarToSend = myVar ..... That all

问题 DBL_MAX is 179769313486231570814527423731704356798070567525844996598917476803157260 780028538760589558632766878171540458953514382464234321326889464182768467 546703537516986049910576551282076245490090389328944075868508455133942304 583236903222948165808559332123348274797826204144723168738177180919299881 250404026184124858368.000000 But if I do: double a=1234567890123456789.0; printf("%f",a); 1234567890123456768.000000 Here the precision is 17 digits. double a=0.1234567890123456789; printf("%

问题 Sorry, if I am not posting my try. I have no idea how to approach this. I want charArr to be converted to doubleVal: char[] charArr = {'1'','1','.','1','1','1'}; double doubleVal = 11.11; 回答1: here is a hint convert the char array to string. ( see String.valueOf method) convert the string to double value ( see Double.parseDouble) 回答2: Something like this: StringBuilder sb = new StringBuilder(); sb.append(charArr); Double d = Double.parseDouble(sb.toString()); 回答3: Something like that: you can

问题 It give me only 1s int maxVal; int minVal; int wh = w*h; int values[1000]; for(x=0;x<w;x++){ for(y=0;y<h;y++){ double RealColor = cvGetReal2D(source, y, x); values[x*y + y] = RealColor; } } minVal = *min_element(values,(values+wh)); maxVal = *max_element(values,(values+wh)); float dif = maxVal - minVal; float fminVal; fminVal = minVal; for(x=0;x<w;x++){ for(y=0;y<h;y++){ float rc = cvGetReal2D(source, y, x); float normRealColor =(rc - fminVal + 1) / dif; file << normRealColor << " "; } file <

问题 Hi, I want to know how many number of digits are allowed after decimal point for primitive double datatype in java, without actually getting rounded off. 回答1: It depends on the number; read up on floating point representations for more information. Use the BigDecimal class for fixed-scale arithmetic. 回答2: Taken literally, the number is 0. Most decimal fractions with at least one digit after the decimal point get rounded on conversion to double. For example, the decimal fraction 0.1 is rounded

问题 How to round off a float value if the value is like: eg: 1.0 ==> then it should return 1 2.0 ==> then it should return 2 but if the value is like: 1.2 ==> then it should return 1.2 1.90 ==>then it should return 1.9 I have tried to round off it and also tries different solutions but that doesn't worked for me. 回答1: You can create a helper function like this static public void Normalize(String pattern, double value ) { DecimalFormat formatter = new DecimalFormat(pattern); String normalizedValue

问题 How to round off a float value if the value is like: eg: 1.0 ==> then it should return 1 2.0 ==> then it should return 2 but if the value is like: 1.2 ==> then it should return 1.2 1.90 ==>then it should return 1.9 I have tried to round off it and also tries different solutions but that doesn't worked for me. 回答1: You can create a helper function like this static public void Normalize(String pattern, double value ) { DecimalFormat formatter = new DecimalFormat(pattern); String normalizedValue

问题 I'm writing a method that checks to see if the text file being passed into the constructor of my instantiable class contains non-numeric data. Specifically, it matters if the data cannot be represented as a double. That is, chars are not okay, and integers are. What I have so far is: private boolean nonNumeric(double[][] grid) throws Exception { boolean isNonNumeric = false; for (int i = 0; i < grid.length; i++) for (int j = 0; j < grid[i].length; j++) { if (grid[i][j] != ) { isNonNumeric =

问题 I am having trouble parsing "1,234.56" in Java, a similar question recommend using French locale in number formatting, but it is parsing the result incorrectly. Here is what I have: NumberFormat format = NumberFormat.getInstance(Locale.FRANCE); Number number = format.parse("1,234.56"); System.out.println(number.doubleValue()); // Should get 1234.56, got 1.234 instead Number number = format.parse("1,234,567.89"); System.out.println(number.doubleValue()); // Should get 1234567.89 回答1: 1,234.56

问题 Im working on a program, where the user inputs a double, and I split the double up and put it into an array(Then I do some other stuff). The problem is, im not sure how to split up the double by digit, and put it into an int array. Please help? Heres what im looking for: double x = 999999.99 //thats the max size of the double //I dont know how to code this part int[] splitD = {9,9,9,9,9,9}; //the number int[] splitDec = {9,9}; //the decimal 回答1: You can convert the number to String then split