django-templates

I'm trying to do something like this: class AboutView(TemplateView): template_name = 'about.html' def get_context_data(self, **kwargs): context = super(AboutView, self).get_context_data(**kwargs) context['dahl_books'] = Books.objects.filter(author="Dahl') When I try to access dahl_books in my template like this: {% for book in dahl_books %} dahl_books is not available in the template context, even though the Books QuerySet returned a non-zero number of books. ....am I doing something wrong in either my template or in get_context_data ? I can't test it, but I bet you need return context at the

If fruits is the list ['apples', 'oranges', 'pears'] , is there a quick way using django template tags to produce "apples, oranges, and pears"? I know it's not difficult to do this using a loop and {% if counter.last %} statements, but because I'm going to use this repeatedly I think I'm going to have to learn how to write custom tags filters, and I don't want to reinvent the wheel if it's already been done. As an extension, my attempts to drop the Oxford Comma (ie return "apples, oranges and pears") are even messier. First choice: use the existing join template tag. http://docs.djangoproject

how do i implement the tree structure in django templates with out using django-mptt. i have model. class Person(TimeStampedModel): name = models.CharField(max_length=32) parent = models.ForeignKey('self', null=True, blank=True, related_name='children') now i want .. Parent Child 1 subchild 1.1 subchild 1.2 nextsubchild 1.2.1 Child 2 Child 3 there names should be click able to show their profile. DTing from Django while loop question and http://docs.djangoproject.com/en/dev/howto/custom-template-tags/#inclusion-tags # view.py @register.inclusion_tag('children.html') def children_tag(person):

I'm trying to learning django templates but it's not easy. I have a certain views.py containing a dictionary to be rendered with a template. The dictionary is made of key-value pairs, where key are unique names and values are some values associated to those names. I render the dictionary in the following way: return render_to_response('results.html', {'data': results_dict}) Now my problem is that in my template I need to display the names in alphabetical (or ASCIIbetical) order with the relatives values. Actually in my template I have: <table> {% for key, value in data.items %} <tr> <td> {{

I'm new to Django and I wonder if there is a way to dump all the variables available to a template for debugging purposes. In Python I might use something like locals() , is there something equivalent for the default template engine? Note: suppose I don't have access to the view for the purposes of this question. Both Ned's and blaine's answers are good, but if you really want to achieve exactly what you ask for there's a template tag for it: {% debug %} Builtins:debug More information in the context_processor.debug including: If this processor is enabled, every RequestContext will contain

How do you get your template/view to recognize whether or not a logged in user is a super user or not? There are certain buttons on my forms (in the template) that I want completely hidden if the user is not a super-user How would you go about doing that? Check out is_superuser on the User object: {% if request.user.is_superuser %} ... <button>...</button> ... {% else %} ... {% endif %} EDIT: after @mustafa-0x comments The above assumes that you have django.core.context_processors.request included in your TEMPLATE_CONTEXT_PROCESSORS setting which isn't the default . The default setting for