django-templates

I'm using the django-compressor app in Django 1.2.3 to minify and merge a number of included CSS and JS files. In a base template, I have {% load compress %} {% compress js %} {% block js %} <script type="text/javascript" src="/site_media/js/jquery.query-2.1.7.js"> {% endblock %} and in a child, {% block js %} {{block.super}} <script type="text/javascript" src="/site_media/js/jquery.validate.min.js"> {% endblock %} When the templates render, the first script tag is correctly minified, but the second isn't. In similar scenarios, I've confirmed that the issue is inheritance. I don't want to keep

I have a line in a Django form : {% for aa in my_array %} which seems to be triggering this error : Template error Caught an exception while rendering: Reverse for 'dev_env.profiles.views.viewPlan' with arguments '('',)' and keyword arguments '{}' not found. What does this error message really mean? I suspect that either the line is correct, but the error message is wrong. Or the error is real but this line is a red-herring. What on earth should I be looking for? Update : Paulo sorted this, below. In fact, I had a {% url viewPlan planId %} a couple of lines away (so the reported error line was

I have been trying to find information about this setting but there isn't much. Can someone explain me what is this setting about? Should I turn it off in production?... Just want to learn about it, maybe I'm missing something important in django. (I use django 1.6) This setting helps with debugging errors/exceptions raised while rendering the templates. If it is set to True and DEBUG is True , Django would show you usual "fancy" error page with a traceback, request details and other important information, and highlight at which line the error happened . If it is set to False and DEBUG is True

In my django application I am using a template to construct email body, one of the parameters is url, note there are two parametes separated by ampersand in the url. t = loader.get_template("sometemplate") c = Context({ 'foo': 'bar', 'url': 'http://127.0.0.1/test?a=1&b=2', }) print t.render(c) After rendering it produces: http://127.0.0.1/test?a=1&amp;b=2 Note the ampersand is HTML encoded as "&". One way around the problem is to pass each parameter separately to my template and construct the url in the template, however I'd like to avoid doing that. Is there a way to disable HTML encoding of

I am new to Django. I made a folder named templates in my project and "base.html" inside it, it works fine. But when I make new folder inside templates welcome and then "home.html" and I write some lines of code in my views.py file as from django.shortcuts import render_to_response def hello(request): return render_to_response('welcome/home.html') and settings.py includes # Django settings for Telecom project. DEBUG = True TEMPLATE_DEBUG = DEBUG import os #BASE_DIR = os.path.dirname(os.path.dirname(__file__)) PROJECT_DIR = os.path.dirname(__file__) ADMINS = ( # ('Your Name', 'your_email

I have a template that includes several tables. I want to use a sub-template which renders these tables in the same way. I can get it to work for a single table, by setting the context in the view and passing that to the template. But how do you change the data for to render another table for different data? **'myview.py'** from django.shortcuts import render_to_response table_header = ("First Title", "Second Title") table_data = (("Line1","Data01","Data02"), ("Line2","Data03","Data03")) return render_to_response('mytemplate.html',locals()) **'mytemplate.html'** {% extends "base.html" %} {%

I have been trying to call a block inside an if condition in django template. I have a base template . I have many other templates that extend the base template. I have defined a block in base template: {% block test_block %}Test{% endblock %} I then want to override this block on a certain condition in the other templates. If the condition fails, the block shouldn't get overridden. This is something what I have written: {% if test_value %}{% block test_block %}Development{% endblock %}{% endif %} This actually (or may be virtually) ignores the if condition. What I finally did: {% block test

This question already has answers here : How to check the TEMPLATE_DEBUG flag in a django template? (6 answers) I would like distinguish a look of some toolbar in layout.html depending if DEBUG = True or not. I am aware of this answer using django.core.context_processors.debug but it forces me to use RequestContext instead of Request what I not really like, btw how can I use RequestContext for layout.html which extends base.html ? And generally is there some better way to that than mentioned one or the one using custom template tag ? I am currently on Django 1.7 andilabs In newer versions of