django-templates

I am trying to build a import form for a CSV file into the admin interface for a given model. the view can be reached from the change_list of the model, but it throws a template syntax error. What am I doing wrong? Do I have to create my own template or can I re-use the existing admin/change_form.html somehow and I just don't get it? Traceback Line 60 is highlighted. Template error: In template site-packages\django\contrib\admin\templates\admin\change_form.html, error at line 60 Caught KeyError while rendering: 'opts' 50 : {% endfor %} 51 : 52 : {% block after_field_sets %}{% endblock %} 53 :

I'm new to Django and fairly confused about how third-party apps are best integrated. In my (possibly naive) interpretation of DRY, I want to minimize copy/pasting not only my own code but other people's code as well, so I'm happy with, for example, the pattern of using contrib.auth as mostly a black box if I needed additional info on auth.User (by extending auth.User with a UserProfile object or inheritance). And this was how I imagined I'd use most third-party apps as well. However, I quickly found out this was very difficult, so now I've resigned to having "copies" of all of my third-party

My forms.py: class AlertForm(forms.ModelForm): class Meta: model=Alert fields = ('high','medium', 'user') widgets = { 'user': forms.HiddenInput() } AlertCountFormset = modelformset_factory(Alert, form = AlertForm) Another Django Form class: class NotifierForm(forms.ModelForm): high = forms.ChoiceField(choices=NOTIFIER_TYPE) medium = forms.ChoiceField(choices=NOTIFIER_TYPE) low = forms.ChoiceField(choices=NOTIFIER_TYPE) def save(self, commit=True): alert = super(NotifierForm, self).save(commit=False) alert.high = self.cleaned_data["high"] alert.medium = self.cleaned_data["medium"] alert.low =

I am creating a blog on django/webfaction. My hompage currently displays 4 posts by default (posts are limited to 4 on queryset in urls.py ). Now I would like to load four more posts once user reaches the bottom of the page and keep on continuing that until last post is reached. How to achieve this? Anoop If you want to load your content on reaching extreme bottom of document use following code: $(window).scroll(function() { if($(window).scrollTop() == $(document).height() - $(window).height()) { // load your content } }); If you want to load content before reaching 100 pixel of bottom use var

I've found a similar question on StackOverflow , but the solution doesn't seem to work for me, unless I'm doing it wrong. I have a ID number, which I'd like to append to a string in a template tag. Here's my attempt: {% with "image-"|add:vid.the_id as image_id %} {# custom template tag to generate image #} {% image vid.teaser_thumbnail alt=vid.title id=image_id %} {% endwith %} But image_id is coming out as empty. What am I doing wrong here? My desired output of image_id would be something like "image-8989723123". Try this way (added with statement with stringformat on top of yours): {% with

So I am using django-registration app to implement a user registration page for my site. I used Django's backends.simple views which allows the users to immediately login after registration. My question is how do I redirect them to my other app's page located in the same directory as the project. Here is what my main urls.py looks like: from django.conf.urls import patterns, include, url # Uncomment the next two lines to enable the admin: # from django.contrib import admin # admin.autodiscover() urlpatterns = patterns('', url(r'^accounts/', include('registration.backends.simple.urls')), url(r'