django-templates

问题 I'm trying to override the default django-allauth templates. I've copied the templates from the allauth folder in my site-packages to my applications template directory. The structure is as follows myapp --templates ----account ----admin ----socialaccount ----www ----base.html My settings.py has the TEMPLATE_DIRS set TEMPLATE_DIRS = ( os.path.join(BASE_DIR, "templates"), ) As per this answer I'm loading my application before allauth. Making any changes to the templates in my directory doesn't

问题 I'm trying to override the default django-allauth templates. I've copied the templates from the allauth folder in my site-packages to my applications template directory. The structure is as follows myapp --templates ----account ----admin ----socialaccount ----www ----base.html My settings.py has the TEMPLATE_DIRS set TEMPLATE_DIRS = ( os.path.join(BASE_DIR, "templates"), ) As per this answer I'm loading my application before allauth. Making any changes to the templates in my directory doesn't

问题 How I can insert pdb.set_trace() in django template? Or maybe run some another debug inside template. 回答1: PyCharm Professional Edition supports graphical debugging of Django templates. More information about how to do that is here: https://www.jetbrains.com/help/pycharm/2016.1/debugging-django-templates.html PyCharm's debugger is very, very good. It is just about the best Python IDE available. Disclaimer: I am a satisfied customer, but have no other vested interest. 回答2: Here's a little

问题 I have a model where I upload a video, i want to display the same in the browser but somehow I am not able to. Kindly help me. I made an app with the name deploy, where I am uploading the video and saving it. Kindly tell me where I am doing wrong and what should be done here. I want the video which was uploaded should be displayed on the page and there should be a option for download as well. I shall be extremely thankful for the help. My models.py file: class Video(models.Model): Video

问题 So I am trying to optimize a fairly odd query, but this is a legacy database so I make do with what I have. These are the queries I am trying. They provide the same output at this point. w is my queryset. def future_schedule(request): past = datetime.date.today()-datetime.timedelta(days=730) extra_select = { 'addlcomplete': 'SELECT Complete FROM tblAdditionalDates WHERE Checkin.ShortSampleID = tblAdditionalDates.ShortSampleID', 'addldate': 'SELECT AddlDate FROM tblAdditionalDates WHERE

问题 Is there a way to display the weekday of a datetime object in a template as the actual name of the weekday? Basically I want it to print Friday instead of 5 . 回答1: See the documentation for the built-in date filter. From there you'll see you need to use: l Day of the week, textual, long. 'Friday' 回答2: For clarity's sake, the template tag format character "l" (lower-case "L") can be used in the Django template like so: {{ object.some_date_field | date:"l" }} Django 1.8.2 回答3: You can also use:

问题 Is there a way to display the weekday of a datetime object in a template as the actual name of the weekday? Basically I want it to print Friday instead of 5 . 回答1: See the documentation for the built-in date filter. From there you'll see you need to use: l Day of the week, textual, long. 'Friday' 回答2: For clarity's sake, the template tag format character "l" (lower-case "L") can be used in the Django template like so: {{ object.some_date_field | date:"l" }} Django 1.8.2 回答3: You can also use:

问题 I am trying to render a list of lists zipped with zip() . list_of_list = zip(location,rating,images) I want to render this list_of_list to template and want to show only the first image of each location. my location and image models are these: class Location(models.Model): locationname = models.CharField class Image(models.Model): of_location = ForeignKey(Location,related_name="locs_image") img = models.ImageField(upload_to=".",default='') here is the zipped list. How can I access only the

问题 I am trying to render a list of lists zipped with zip() . list_of_list = zip(location,rating,images) I want to render this list_of_list to template and want to show only the first image of each location. my location and image models are these: class Location(models.Model): locationname = models.CharField class Image(models.Model): of_location = ForeignKey(Location,related_name="locs_image") img = models.ImageField(upload_to=".",default='') here is the zipped list. How can I access only the

问题 I am using a Django Paginator and I want to have multiple available get parameters, such as: page=1 sort_by=price However, in my template tags I have: Showing items sorted by {{ SORT_PARAM }}. Showing {{ ITEMS_PER_PAGE }} items per page. {% if has_prev %} <a href="?page={{ prev_page }}">Previous</a> | {% endif %} However, this does not preserve the other GET variables. What I mean is, if I'm viewing page/?page=1&sort_by=price and I click the link in the template fragment above, I will go to