django-tables2

I have a django_tables2 table inside a form, this is necessary because there's a delete selected button on top. In every row, I need a submit button with some action like 'accept', 'deny', etc. But I don't know how to recognize the row of which the button was pressed. How can I accomplish this? GGette1011 I have found this way to add a button to each row with an id that refers to the row you select : in app/tables.py import django_tables2 as tables from app.models import MyModel from django.utils.safestring import mark_safe from django.utils.html import escape class MyColumn(tables.Column):

I would like to create a table with django-tables2 such that different rows have different properties. By default I get either <tr class="odd"> or <tr class="even"> How can I specify my own class for some of the rows? Similarly, if I have a CheckBoxColumn and I specify some data for this column, it goes into the value : <input type="checkbox" name="col" value="123"/> This is great for figuring out which checkbox was checked. However, how can I set some checkboxes as checked when the table is created? My scenario: the user picks some rows from a large table. For example, the table has orange 1

In my Django project I need to have tables which columns are dynamic and depend on what is in the database. So I found a solution in here and it works but with a little problem. Here's the class with a table I'm extending dynamically: class ClientsTable(tables.Table): class Meta: model = Client attrs = {"class": "paleblue", "orderable":"True", "width":"100%"} fields = ('name',) def __init__(self, *args, **kwargs): super(ClientsTable, self).__init__(*args, **kwargs) self.counter = itertools.count() def render_row_number(self): return '%d' % next(self.counter) def render_id(self, value): return