division

问题 I need to know how to do this procedure. calculation1: 1/4 = 0,25 calculation2: 1/8 = 0,125 calculation3: 47/183 = 0,25683060109289617486338797814207...... calculation4: 58/889 = 0,06524184476940382452193475815523...... calculation5: 1/5 = 0,2 The results of calculations 1, 2 and 5 will give a short result, no periods or and endless string of digits. The results of calculations 3 and 4 are very long and complicated. How can I check which calculation is an "easy one" and gives a "short" result

问题 I need to know how to do this procedure. calculation1: 1/4 = 0,25 calculation2: 1/8 = 0,125 calculation3: 47/183 = 0,25683060109289617486338797814207...... calculation4: 58/889 = 0,06524184476940382452193475815523...... calculation5: 1/5 = 0,2 The results of calculations 1, 2 and 5 will give a short result, no periods or and endless string of digits. The results of calculations 3 and 4 are very long and complicated. How can I check which calculation is an "easy one" and gives a "short" result

问题 I'm pretty sure I'm being stupid but why isn't this working!? form.find( '.per_time' ).on( 'change', function() { var price = parseInt( form.find( '.section-price' ).attr('data-price'), 10 ) ; var multiplier = parseInt( $( this ).val(), 10 ); var newprice = (price / 7) * multiplier; form.find( '.section-price .price' ).html( newprice ) }) It's this line I'm concerned about: var newprice = (price / 7) * multiplier; The calculation is not dividing by 7, it only calculates price * multiplier ?

问题 I'm pretty sure I'm being stupid but why isn't this working!? form.find( '.per_time' ).on( 'change', function() { var price = parseInt( form.find( '.section-price' ).attr('data-price'), 10 ) ; var multiplier = parseInt( $( this ).val(), 10 ); var newprice = (price / 7) * multiplier; form.find( '.section-price .price' ).html( newprice ) }) It's this line I'm concerned about: var newprice = (price / 7) * multiplier; The calculation is not dividing by 7, it only calculates price * multiplier ?

问题 Currently I write some ugly code like def div(dividend: Int, divisor: Int) = { val q = dividend / divisor val mod = dividend % divisor (q, mod) } Is it specified in standard library? 回答1: No (except for BigInt , as mentioned in other answers), but you can add it: implicit class QuotRem[T: Integral](x: T) { def /%(y: T) = (x / y, x % y) } will work for all integral types. You can improve performance by making separate classes for each type such as implicit class QuotRemInt(x: Int) extends

问题 For large quotients, integer division ( // ) doesn't seem to be necessarily equal to the floor of regular division ( math.floor(a/b) ). According to Python docs (https://docs.python.org/3/reference/expressions.html - 6.7), floor division of integers results in an integer; the result is that of mathematical division with the ‘floor’ function applied to the result. However, math.floor(648705536316023400 / 7) = 92672219473717632 648705536316023400 // 7 = 92672219473717628 '{0:.10f}'.format

问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 7 years ago . I am trying to complete an assignment that requires me to write three functions for binary arithmetic. badd() was provided for me, so I used it to help write the bsub() and bmult() functions. I am having trouble

问题 I couldn't really come up with a proper title for my question but allow me to present my case; I want to calculate a significance ratio in the form: p = 1 - X / Y Here X comes from an iterative process; the process takes a large number of steps and counts how many different ways the process can end up in different states (stored in a HashMap). Once the iteration is over, I select a number of states and sum their values. It's hard to tell how large these numbers are so I am intending to

问题 I'm trying to divide screenwidth by a variable in order to draw equally spaced UI parts in webview. However, when the variable is 3, 100 / 3 results 33.3333333333333336 in JavaScript, and the third part cannot be drawn as intended because the sum of the quotients is bigger than 100%, I gusss. Is there any nice workaround for this problem? 回答1: You can specify the precision of the division: var width = (100 / 3).toPrecision(3); 回答2: The best you can do is get as close as possible: (100 / 3)

问题 I'm programming with Python 2.7.6 using numpy. I have this division between two numpy matrixes V/np.dot(W,H) . Sometimes happens that the denominator has some cell values equal to 0, so i get a Runtime error. I would like to implement a safe division in a efficient way. How can i write a code that performs the Matrix division and for the elements where the denominator is equal to 0 puts 0 in the output Matrix? 回答1: Numpy actually allows you to set what you'd like to do in the case of a divide