division

Getting place values of a number w/ modulus?

前提是你 提交于 2019-12-07 09:36:34
问题 I need to get the place value of a random number submitted by a user. This number can by anything from 0-1000000000000000 (zero to one trillion) . I think this can be achieved by using the JavaScript modulus % operator. The problem, I don't really know how to use it, nor do I understand it. Here is the Fiddle. (All I know is 10%3 returns 1 because 3*3 = 9 and 10-9 = 1 ) I figured out the ones, tens, hundreds, and thousands: var ones = Math.floor(num % 10), tens = Math.floor(num / 10 % 10),

Overflow Exception when dividing two decimals in .NET

自闭症网瘾萝莉.ら 提交于 2019-12-07 07:28:38
问题 I'm having an issue trying to divide two decimals and then display the result. Annoyingly this is only happening on our server, and it appears to work perfectly fine if I run the code locally. This is the code that I am trying to run decimal dOne = -966.96M; decimal dTwo = 2300M; decimal dResult = Decimal.Round((dOne / dTwo), 28, MidpointRounding.AwayFromZero); The resulting number (as generated from windows calculator) is -0.43346086956521739130434782608696 This always results in an overflow

What decides Nan and Infinity in java division operations

血红的双手。 提交于 2019-12-07 06:58:04
问题 Output of the below code confusing me. Why NaN sometimes and Infinity other times ? public static void main (String[] args) { double a = 0.0; double b = 1.0; int c = 0; System.out.println(a/0.0); System.out.println(a/0); System.out.println(b/0.0); System.out.println(b/0); System.out.println(c/0.0); System.out.println(c/0); } Outputs is: NaN NaN Infinity Infinity NaN Exception in thread "main" java.lang.ArithmeticException: / by zero What is the deciding factor here ? 回答1: This is because of

Exact difference between div and quot

北慕城南 提交于 2019-12-06 22:01:12
问题 In this question here on SO the differences between the two operators div and quot are mentioned as well as the fact that the quot operator is more efficient than the div operator, whereas div is more natural for us humans to use. My question is what the exact implementations of the two operators are and linked to that what the difference between implementations is. Also I want to know how the speed difference between those two comes to be, as using Hoogle and browsing the sources did not

Division in c not giving expected value

丶灬走出姿态 提交于 2019-12-06 21:03:27
When doing a division im getting a rounded answer? double div; div = 25/8; printf("%lf",div); When i do this prints out 3.0000 why dont i get 3.125 ? Because you are doing an integer division, try with: div = 25.0/8; or div = (double)25/8; Typing 25.0 means a double literal. You could also use 25.f for a float literal. Both of these trigger floating point division. Either typecast explicitly to double data type or change numerator to get desired value i.e. 25.o or use floating point literal 25.f. brokenfoot Typecast it, i.e. change it to: double div; div = (double)25/(double)8; printf("%lf"

Why is math.floor(x/y) != x // y for two evenly divisible floats in Python?

帅比萌擦擦* 提交于 2019-12-06 18:22:12
问题 I have been reading about division and integer division in Python and the differences between division in Python2 vs Python3. For the most part it all makes sense. Python 2 uses integer division only when both values are integers. Python 3 always performs true division. Python 2.2+ introduced the // operator for integer division. Examples other programmers have offered work out nice and neat, such as: >>> 1.0 // 2.0 # floors result, returns float 0.0 >>> -1 // 2 # negatives are still floored

Divide two large numbers as strings without using Bignumbers in java

删除回忆录丶 提交于 2019-12-06 15:36:40
I need to divide two large integers WITHOUT using Biginteger since the Numbers can't be stored inside a primitive type , since I need to do it char by char from the strings I am given,I have already created a class called BigNumber, with this class I can: Add multiply compare two strings with large integers inside Now I only need to implement the Dividing method but I can't get my head around how to do it with two strings instead of one String and an Int, here's what I got so far, it works if the number we are dividing the String by is small enough to be an int class BigNumber { String Number;

64 bit division in ARM Assembly SOS

此生再无相见时 提交于 2019-12-06 13:05:24
I am calculating the average of sixteen 64 bit numbers added together and I think that I have done all the addition correctly, but now I need to figure out how to divide a 64 bit number by 16 and I am stuck! Any help would be great thank you so much. Here is my code so far. tableSize EQU 16 sum EQU 0x40000000 average EQU 0x40000008 MOV r8, #14 ADR r0, table LDR r9, =sum LDR r10,=average LDR r1, [r0], #1 ;hi #1 LDR r2, [r0], #1 ;lo #1 SUM SUB r8, r8, #1 LDR r3, [r0], #1 ;hi #2 LDR r4, [r0], #1 ;lo #2 ADDS r5, r2, r4 ;lo 1 + lo 2 set flags ADC r6, r1, r3 ;hi 1 + hi 2 + carry MOV r1, r6 MOV r2,

Numpy Array Division - unsupported operand type(s) for /: 'list' and 'float'

江枫思渺然 提交于 2019-12-06 11:40:13
问题 I defined the following numpy array: import numpy as np numpy_array = np.array([[-1,-1,-1,-1,-1], [-1,2,2,2,-1], [-1,2,8,2,-1], [-1,2,2,2,-1], [-1,-1,-1,-1,-1,-1]]) Now I wanted to divide the whole array by 8: numpy_array /= np.float(8.0) I get the following error message: TypeError: unsupported operand type(s) for /: 'list' and 'float' I hope someone has a hint for me, what I am doing wrong. 回答1: The array has a list of the incorrect size, the final list is incorrect. if you want to keep the

Safe Floating Point Division

扶醉桌前 提交于 2019-12-06 11:04:49
I have some places in my code where I want to assure that a division of 2 arbitrary floating point numbers (32 bit single precision) won't overflow. The target/compiler does not guarantee (explicitly enough) nice handling of -INF/INF and (does not fully guarantees IEEE 754 for the exceptional values - (possibly undefined) - and target might change). Also I cannot make save assumtions on the inputs for this few special places and I am bound to C90 standard libraries. I have read What Every Computer Scientist Should Know About Floating-Point Arithmetic but to be honest, I am a little bit lost.