design-time

Is the constructor of a form not called upon opening the form in design view? Why not? Can I somehow force it to be called? I tested it by showing a MessageBox in the constructor, and only the MessageBox from the constructor of the form's base type (another form) is shown... This behavior is by design. The form designer in Visual Studio cannot instantiate the class being designed — instead, it instatiates its immediate parent. There is no way to change this behavior. If you need some logic to be executed during design time, you have to create a separate ancestor encapsulating that logic and

I'm creating custom control that will draw shape from list (or array) of points. I have basic drawing functionality done, but now I'm struggling with design-time support in Visual Studio. I've created two properties: private Point _point; public Point Point { get { return _point; } set { _point = value; } } private Point[] _points; public Point[] Points { get { return _points; } set { _points = value; } } As seen on screen below Point is editable, but editor for Points isn't working. For each property I get error Object does not match target type. If I change Point to MyPoint (custom class

I am not sure how to track down the following crash: It happens when Unloading a Designtime Package that is used in-house at my company. It is our code, thus it is our bug to fix, not a third party component vendor problem. It apppears that a thread is involved, but since it happens in the Function ThreadProc in Classes.pas, I'm guessing it's a bare System/RTL thread without even a TThread class wrapper that I should be searching for in our code. (Question Part A: Is that so?) The call stack contains none of my code, only the IDE itself, and the base function in the call stack is ntdll

I wish to allow the user of my control to choose the licensing method for the control. The choice comes from an enumeration, so they must choose one of the methods I have laid out for them. This license needs to be chosen prior to the code executing at runtime. Therefore I wish for them to selected a value at design time. Furthermore I do not wish for this property to be writable at runtime, if that can be avoided. Is there a way to make a property only available at design time? You can give a control design-time behavior by creating a separate designer class for the control. Since the control

[EDIT] To be clear, I know how to get a list of forms via reflection. I'm more concerned with the design time property grid. I have a user control with a public property of the type Form. I want to be able to select a form at design time from a dropdown. I want to populate the form dropdown list from a set namespace: UI.Foo.Forms This would work like if you have a public property of Control. At design time, the property will automatically populate a dropdown with all the controls on the form, for you to select from. I just want to populate it with all the forms in a namespace. How do I go

See the update below for VS2013. When using a class as a d:DesignInstance that exposes a KeyedCollection<TKey, TItem> , the XAML designer complains with the following warning: The number of generic arguments provided doesn't equal the arity of the generic type definition. Parameter name: instantiation The problem can be reproduced with the following simple program: <Window x:Class="Test.MainWindow" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns

I have something similar to a wizard control, in the middle is a Panel I would like to use to place any child controls. I have found using the ScrollableControlDesigner will allow dropped controls to be added to the custom/usercontrol, but this is not what I require. It needs to be added to the container, so layout can be applied without affecting the 'outer' controls (heading, navigation buttons). I have tried various ways, that did not work, and looked hacky. Any ideas? I found the answer here ! The key is ControlDesigner.EnableDesignMode() . 来源： https://stackoverflow.com/questions/594808