delimiter

I have a bash script that recieves a set of files from the user. These files are sometimes under directories with spaces in their names. Unfortunately unlike this question all the filenames are passed via the command line interface. Let's assume the paths are correctly quoted as they are passed in by the user, so spaces (save for quoted spaces) are delimiters between paths. How would I forward these parameters to a subroutine within my bash script in a way that preserves the quoted spaces? #! /bin/bash for fname in "$@"; do process-one-file-at-a-time "$fname" done Note the excessive use of

Im trying to loop though a string with HTTP links inside and newlines, I want to loop over a line at a time. At the moment I have echo -e "$HTTP_LINKS" | while read HTTP_S_LINK ; do TEST_STRING="test" done But this way I don't have access to the TEST_STRING out side the loop, which is what I want. I'm using the while loop so that it will loop though each newline in $HTTP_LINKS and not just the words in the string. (I don't want to use a for loop with IFS set to \n) I thought maybe I could just do something like this #!/bin/bash while read HTTP_S_LINKS do TEST_STRING="test2" done < $HTTP_LINKS

I have seen '\0' to be used as a delimiter in mixed binary files (UTF8 strings + binary data). Could anyone explain what '\0' means or point to a good place to study? It's the null character; more info in this Wikipedia article . The two-character \0 representation is used in C source code to represent the NUL character, which is the (single) character with ASCII value 0. The NUL character is used in C style character strings to indicate where the end of the string is. For example, the string "Hello" is encoded as the hex bytes: 48 65 6c 6c 6f 00 In this case, the C compiler automatically adds

I want to parse a file that looks like this using batch : a: string_containing_various_characters,.:and spaces/1 b: string_containing_various_characters,.:and spaces/2 c: string_containing_various_characters,.:and spaces/3 d: string_containing_various_characters,.:and spaces/4 e: string_containing_various_characters,.:and spaces/5 f: string_containing_various_characters,.:and spaces/6 g: string_containing_various_characters,.:and spaces/7 I need to extract every string following "a: ","b: ","c: " etc... I can't use space as a delimiter since there can be spaces in the strings. The only thing

I'd like to specify a delimiter for a scanner that splits on some pattern, but doesn't remove that pattern from the tokens. I can't seem to make this work, as anything that is identified by the regex also gets eaten as part of the delimiter. Any suggestions? My specific problem, I have file that looks like: text/numbers mix numbers numbers text/numbers mix numbers numbers numbers . . I'd like to split out from the text/numbers mix+rows until the next text/numbers mix. I have the regex to identify them, but as stated, using that as the delimiter eats part of what I want. EDIT: code addition:

Example of what I want to do: If you pass in "abc|xyz" as the first argument and "|" as the second argument the method returns List("abc","xyz") public List<String> splitIt(String string, String delimiter){ //create and init arraylist. List<String> list = new ArrayList<String>(); //create and init newString. String newString=""; //add string to arraylist 'list'. list.add(string); //loops through string. for(int i=0;i<string.length();i++){ //stores each character from string in newString. newString += string.charAt(i); } newString.replace(delimiter, ""); //remove string from arraylist 'list'.