test5
arr1 =[11,22,33] arr2 =[44,22,33] arrSame = [] arrOneHaveTwoHaveNot = [] arrOneHaveTwoHaveNot1 = [] # 获取内容相同的元素列表: for item in arr1: for iter in arr2: if(item==iter): arrSame.append(iter) #获取arr1 和 arr2 中内容都不同的元素: for item in arr1: oneHas = 0 for iter in arr2: if(item!=iter): oneHas = 0 continue else: oneHas = 1 break if(oneHas == 0): print(item) arrOneHaveTwoHaveNot.append(item) i =3 for item in arr2: oneHas = 0 for iter in arr1: if(item!=iter): oneHas = 0 continue#中断for循环 else: oneHas = 1 break#跳出for循环 if(oneHas == 0):#判断是否为0 print(item) arrOneHaveTwoHaveNot1.append(item) #打印两位数: arr1=