declaration

When I compile function with "gcc -o dene -Wall -ansi -pedantic-errors dene.c" ,gcc emits no error.(can you look a line which starts with char ....,in if loop,) static void remove_negation(char *s,char *s1) { char **cmainp=malloc(sizeof(char*)*1); int len=0;int d=0; int i=0; cmainp[0]=malloc(sizeof(char)*300); len=strlen(s); for(i=0;i<len;++i) { if(s[i]=='-') if(i==0 || s[i-1]==',') /*look*/ {char *p=malloc(sizeof(char)*3); /*look*/ ++i; p[0]=s[i]; p[1]='\0'; strcat(s1,","); strcat(s1,p); free(p); continue; } cmainp[0][d]=s[i]; ++d; } cmainp[0][d+1]='\0'; strcpy(cmainp[0],s); free(cmainp[0]);

when I declare C++ variables, I do it like this: int a,b,c,d; or string strA,strB,strC,strD; I.e., first the type then a comma separated list of variable names. However, I declare pointers like this: int *a,*b,*c,*d; and references like this: int &a,&b,&c,&d; To be consistent it should be int* a,b,c,d; and int& a,b,c,d; Why is it not consistent? It's because of the C heritage. The * modifier applies to the variable in C. So the C++ designers made & to apply to the variable as well by analogy, since they couldn't change the first without breaking C compatibility. Same is true for the array

Why was C++ designed such that the correct way to declare two int *s on the same line is int *x, *y; not int* x,y; I know some people think you should avoid either form and declare every variable on its own line, but I'm interested in why this language decision was made. To keep compatibility with C code, because that's how C works. Bjarne makes a good point here : The choice between int* p; and int *p; is not about right and wrong, but about style and emphasis. C emphasized expressions; declarations were often considered little more than a necessary evil. C++, on the other hand, has a heavy

This question already has an answer here: How to declare strings in C [duplicate] 4 answers A few weeks ago I started learning the programming language C. I have knowledge in web technologies like HMTL/CSS, Javscript, PHP, and basic server administration, but C is confusing me. To my understanding, the C language does not have a data type for strings, just characters, however I may be wrong. I have heard there are two ways of declaring a string. What is the difference between these two lines of declaring a string: a.) char stringName[]; b.) char *stringName; I get that char stringName[]; is an

int x; Is this a declaration or a definition? As I write the following code, #include <stdio.h> int main(void) { int x; printf("%p",&x); return 0; } it prints some address. So as memory is allocated, int x; can't be just a declaration. So is it a definition? From the C standard (n1256) : 6.7 Declarations ... 5 A declaration specifies the interpretation and attributes of a set of identifiers. A definition of an identifier is a declaration for that identifier that: — for an object, causes storage to be reserved for that object; — for a function, includes the function body; 101) — for an