decimalformat

问题 I have been trying to read a file which has date field and a numeric field. I have the data in an excel sheet and looks something like below - Date X 1/25/2008 0.0023456 12/23/2008 0.001987 When I read this in R using the readxl::read_xlsx function, the data in R looks like below - Date X 1/25/2008 0.0023456000000000 12/23/2009 0.0019870000000000 I have tried limiting the digits using functions like round, format (nsmall = 7), etc. but nothing seems to work. What am I doing wrong? I also

问题 I'm having the strangest thing with a DecimalFormat. I'm using it in an webapplication. I setup some test and it keeps on failing with me locally. A friend of me ran it and he was able to successfully ran the JUnit tests. The strange part is that on our server the application runs it perfectly without any problems either. Could it be that Java depends on the system settings like valuta and number settings? Or could there be another reason? This is how my piece of code looks like: public

问题 I am facing an issue where I need to do some calculations with a number like for example 5000,00 multiplied it by ( 1,025^3 ). So in this case 5000,00 * (1,025^3) = 5385,45 So my question is, how can I format the number 5385,45 to be like 5.385,45 using decimal format maybe? I tried by myself and I did this piece of code that outputs 5385,45 in the app but not 5.385,45 var interestValue = (5000,00*(Math.pow(1.025,yearValue))) val number = java.lang.Double.valueOf(interestValue) val dec =

问题 So I want to use the Decimal Format class to round numbers: double value = 10.555; DecimalFormat fmt = new DecimalFormat ("0.##"); System.out.println(fmt.format(value)); Here, the variable value would be rounded to 2 decimal places, because there are two # s. However, I want to round value to an unknown amount of decimal places, indicated by a separate integer called numPlaces . Is there a way I could accomplish this by using the Decimal Formatter? e.g. If numPlaces = 3 and value = 10.555 ,

问题 So I want to use the Decimal Format class to round numbers: double value = 10.555; DecimalFormat fmt = new DecimalFormat ("0.##"); System.out.println(fmt.format(value)); Here, the variable value would be rounded to 2 decimal places, because there are two # s. However, I want to round value to an unknown amount of decimal places, indicated by a separate integer called numPlaces . Is there a way I could accomplish this by using the Decimal Formatter? e.g. If numPlaces = 3 and value = 10.555 ,

问题 I am formatting a decimal number and I have the following criteria to format it: Number should be at most two decimal places ( 10.1234=>10.12 ) If there is only one digit after decimal then it will ends up with an extra 0 ( 10.5=>10.50 ) Thousand separator will be comma ( 12345.2345 => 12,345.23 ) I have written following logic: double x = Double.parseDouble(value.toString()); String dec = x % 1 == 0 ? new java.text.DecimalFormat("###,###.##").format(x) : new java.text.DecimalFormat("###,###

问题 I am formatting a decimal number and I have the following criteria to format it: Number should be at most two decimal places ( 10.1234=>10.12 ) If there is only one digit after decimal then it will ends up with an extra 0 ( 10.5=>10.50 ) Thousand separator will be comma ( 12345.2345 => 12,345.23 ) I have written following logic: double x = Double.parseDouble(value.toString()); String dec = x % 1 == 0 ? new java.text.DecimalFormat("###,###.##").format(x) : new java.text.DecimalFormat("###,###

问题 I am trying to format prices using DecimalFormat, but this isn't working for all variations. DecimalFormat df = new DecimalFormat("0.##") df.format(7.8) df.format(85.0) prints 7.80 and 85 but "7.79999" gets formatted as "7.8", not "7.80". I have tried doing things this way DecimalFormat df = new DecimalFormat("0.00") to force two dp, but then "85.0" gets formatted as "85.00" not "85"! Is there a way of capturing all variations, so that prices are printed either as #, ##, or #.##? For example:

问题 I am trying to keep two decimal places, even if then numbers are zeroes, using DecimalFormatter : DecimalFormat df = new DecimalFormat("#.00"); m_interest = Double.valueOf(df.format(m_principal * m_interestRate)); m_newBalance = Double.valueOf(df.format(m_principal + m_interest - m_payment)); m_principal = Double.valueOf(df.format(m_newBalance)); However for some values this gives two decimal places, and for others it doesnt. How can i fix this? 回答1: It is because you are using Double.valueOf

问题 Hey i am using the following code to format my numbers to have two decimal places public String format(double num) { String temp=""; DecimalFormat df=new DecimalFormat("R.##"); temp=temp+df.format(num); return temp; } When I print out the results it gives me the answeres with only one decimal place. Please can someone help me stop that. 回答1: You use # in DecimalFormat which is the character that says "print the digit. if it is 0 leave it out." You need to use 0 where 0 is also printed as 0. E