decimal

IP address conversion to decimal and vice versa

做~自己de王妃 提交于 2019-12-04 15:12:04
Suppose my decimal number is 9766322441 so its corresponding is 70.30.65.9 but when this IP address IC converted back, its gives some different decimal number 1176387849 ... and when I convert the IP address pf google.com i.e 64.233.187.99 then it gives the 1089059683 and reverse conversion gives the correct IP address i.e 64.233.187.99 ... My question is what is wrong with the the above mention number? I also try with 9579342332 but the same result. It gives the wrong reverse conversion?? What is the reason behind it?? You could use this calculator for calculations. Vincenzo Pii IPv4

Configure android EditText to allow decimals and negatives

ⅰ亾dé卋堺 提交于 2019-12-04 15:05:52
问题 I have an Android EditText that I want to have the number keyboard come up. If I set the android:inputType to numberSigned, I get the number keyboard and the ability to type in negatives. However this won't let me use decimals. If I use the numberDecimal inputType I can use decimals but not negatives. How do you get the number keyboard with the ability to type in decimals and negatives? 回答1: You are just missing this in your EditText, android:inputType="numberDecimal|numberSigned" 回答2: We can

How to pass a decimal value from JSP to Action with a Localized decimal separator?

拜拜、爱过 提交于 2019-12-04 14:54:46
In the JSP: <input type = "number" name = "score" min = "0" max = "100" maxlength = "3" step = "0.01" /> In the Action: @Getter @Setter private Float score; When the value has decimal places (eg. 56,78 ), in the Action I get 5678.0 . This is due to the fact that Struts2 is not aware that in my country , is the decimal separator, not the thousands separator. Is there a way to instruct Struts2 to use the decimal separator of a specific Locale , so that it will be able to convert the floating numbers correctly ? When the value has decimal places (eg. 56,78), in the Action I get 5678.0 This is

Python - Decimal to Hex, Reverse byte order, Hex to Decimal

时间秒杀一切 提交于 2019-12-04 14:06:56
问题 I've been reading up a lot on stuct.pack and hex and the like. I am trying to convert a decimal to hexidecimal with 2-bytes. Reverse the hex bit order, then convert it back into decimal. I'm trying to follow these steps...in python Convert the decimal value **36895** to the equivalent 2-byte hexadecimal value: **0x901F** Reverse the order of the 2 hexadecimal bytes: **0x1F90** Convert the resulting 2-byte hexadecimal value to its decimal equivalent: **8080** 回答1: >>> x = 36895 >>> ((x << 8) |

How do I use decimal (float) in C++?

萝らか妹 提交于 2019-12-04 13:03:12
问题 According to IEEE 754-2008 there are There are three binary floating-point basic formats (which can be encoded using 32, 64 or 128 bits) and two decimal floating-point basic formats (which can be encoded using 64 or 128 bits). This chart is under it. In C++ I believe float and double are single and double precision ( binary32 and binary64 ). Name Common name Base Digits E min E max Digits E max binary32 Single precision 2 23+1 −126 +127 7.22 38.23 binary64 Double precision 2 52+1 −1022 +1023

How to customize the form of rounding

放肆的年华 提交于 2019-12-04 12:22:29
My question may seem simple, but still can not get something that works. I need to customize the Math.round rounding format or something to make it work as follows: If the number is 1.6 he should round to 1, if greater than or equal to 1.7 should round to 2.0 . And so to all other decimal results with # .6 The way I'm doing the 1.6 being rounded to 2 shall be rounded to 1. How can I do that? Thank you! Simply do this: double threshold = 0.7; Math.round(x - threshold + 0.5); You could write a method that takes a double variable as input and returns the integer based on the first digit after the

Masked TextBox with decimal numbers

若如初见. 提交于 2019-12-04 12:11:59
In my window application I need masked textbox which accept real decmal numbers. eg. 1) 1.56 2) 22.34 3) 123.34 4) 12312.34 This all value should be valid. Can anyone tell me how can I do this? And ya if anyone have better solution for real decimal numbers, instead of this masked TextBox than I love to see it. Thanks... Use a custom control like this one (modify it to fulfill your needs): using System; using System.ComponentModel; using System.Text; using System.Windows.Forms; using System.Drawing; namespace CustomControls { public enum PasteRejectReasons { Unknown = 0, NoData,

Converting a decimal to a hexadecimal number

亡梦爱人 提交于 2019-12-04 11:48:52
Why we use + 55 for converting decimal to hex num . in this code we use +48 to convert integer to character . when temp < 10 . But when temp > =10 we use +55 . what does it mean by +55 ? #include<stdio.h> int main(){ long int decimalNumber,remainder,quotient; int i=1,j,temp; char hexadecimalNumber[100]; printf("Enter any decimal number: "); scanf("%ld",&decimalNumber); quotient = decimalNumber; while(quotient!=0){ temp = quotient % 16; //To convert integer into character if( temp < 10) temp =temp + 48; else temp = temp + 55; hexadecimalNumber[i++]= temp; quotient = quotient / 16; } printf(

Using C++ hex and cin

倖福魔咒の 提交于 2019-12-04 11:21:37
If you have the following code: cout << hex << 10; The output is 'a', which means the decimal 10 is converted into its hexadecimal value. However, in the code below... int n; cin >> hex >> n; cout << n << endl; When input is 12, the output becomes 18. Can anyone explain the details of the conversion? How did it became a decimal value? I'm interested in the point where it became an int. If broken down, it would be: (( cin >> hex ) >> n); Is this correct? The hex manipulator only controls how a value is read - it is always stored using the same internal binary representation. There is no way for

Get Last 2 Decimal Places with No Rounding

☆樱花仙子☆ 提交于 2019-12-04 11:19:35
问题 In C#, I'm trying to get the last two decimal places of a double with NO rounding. I've tried everything from Math.Floor to Math.Truncate and nothing is working. Samples of the results I'd like: 1,424.2488298 -> 1,424.24 53.5821 -> 53.58 10,209.2991 -> 10,209.29 Any ideas? 回答1: Well, mathematically it's simple: var f = 1.1234; f = Math.Truncate(f * 100) / 100; // f == 1.12 Move the decimal two places to the right, cast to an int to truncate, shift it back to the left two places. There may be